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Find the position of centre of buoyancy for a wooden block of width 3.5 m and depth 1 m, when it floats horizontally in water. The density of wooden block id 850 kg/m3 and its length 7.0 m. 
  • a)
    0.95
  • b)
    0.85
  • c)
    1.05
  • d)
    1.65
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Find the position of centre of buoyancy for a wooden block of width 3....
Explanation: Weight of the block=ρ*g*Volume=850*9.81*7*3.5*1=204.29 kN
Volume of
water displaced= Weight of water displaced/weight density of water
= 20.825 m3.
h=20.825/3.5*7=0.85 m.
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Most Upvoted Answer
Find the position of centre of buoyancy for a wooden block of width 3....
Given:
Width of wooden block (B) = 3.5 m
Depth of wooden block (D) = 1 m
Density of wooden block (ρ) = 850 kg/m³
Length of wooden block (L) = 7.0 m

To find: Position of centre of buoyancy

Formula used:
Centre of buoyancy (B) = (2/3) × (d/2) where d is the depth of the immersed portion of the block.

Calculation:
The block is floating horizontally in water. Therefore, the immersed portion of the block is half its depth, i.e. d = D/2 = 0.5 m.

The volume of the block can be calculated as:
Volume = Length × Width × Depth
= 7.0 m × 3.5 m × 1 m
= 24.5 m³

The weight of the block can be calculated as:
Weight = Volume × Density × Acceleration due to gravity
= 24.5 m³ × 850 kg/m³ × 9.81 m/s²
= 202.24 kN

The upthrust acting on the block is equal to the weight of the water displaced by it. As the block is floating, the upthrust is equal to the weight of the block.

The volume of water displaced by the block is equal to its volume. Therefore, the upthrust acting on the block is:
Upthrust = Volume × Density of water × Acceleration due to gravity
= 24.5 m³ × 1000 kg/m³ × 9.81 m/s²
= 240.45 kN

The position of the centre of buoyancy can be calculated as:
Centre of buoyancy (B) = (2/3) × (d/2)
= (2/3) × (0.5/2)
= 0.1667 m

The distance of the centre of buoyancy from the bottom of the block can be calculated as:
Distance from bottom = Depth of block - Depth of immersed portion - Centre of buoyancy
= 1 m - 0.5 m - 0.1667 m
= 0.3333 m

Therefore, the position of the centre of buoyancy from the bottom of the block is 0.3333 m or 0.85 times the depth of the block. Hence, the correct answer is option B.
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Find the position of centre of buoyancy for a wooden block of width 3.5 m and depth 1 m, when it floats horizontally in water. The density of wooden block id 850 kg/m3 and its length 7.0 m.a)0.95b)0.85c)1.05d)1.65Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Find the position of centre of buoyancy for a wooden block of width 3.5 m and depth 1 m, when it floats horizontally in water. The density of wooden block id 850 kg/m3 and its length 7.0 m.a)0.95b)0.85c)1.05d)1.65Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the position of centre of buoyancy for a wooden block of width 3.5 m and depth 1 m, when it floats horizontally in water. The density of wooden block id 850 kg/m3 and its length 7.0 m.a)0.95b)0.85c)1.05d)1.65Correct answer is option 'B'. Can you explain this answer?.
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