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Two trains, one travelling at 90 m/s and the other travelling at 120 m/s, are moving towards each other on the same track. When they are 11 km apart, both drivers simultaneously apply brakes. If the brakes decelerate each train at the rate of 3m/s2 , then the distance travelled by the second train?
Verified Answer
Two trains, one travelling at 90 m/s and the other travelling at 120 m...
Ans.
Given that,
Speed of first train = 90 m/s
Speed of second train = 120 m/s
Distance d = 11 km
Acceleration = 3 m/s
Both trains are moving towards each other on the same track.
We need to calculate the distance traveled by train A when the breaks applied.
Using equation of motion
Where, v = final velocity
u = initial velocity
s = distance
a = acceleration due to gravity
Hence, The distance traveled by the first train is 1350 m.
This question is part of UPSC exam. View all Class 11 courses
Most Upvoted Answer
Two trains, one travelling at 90 m/s and the other travelling at 120 m...
Given:
- Speed of the first train (v1) = 90 m/s
- Speed of the second train (v2) = 120 m/s
- Distance between the trains when brakes are applied = 11 km = 11,000 m
- Deceleration due to brakes (a) = -3 m/s^2 (negative sign indicates deceleration)
To find:
- Distance travelled by the second train before coming to a stop
Approach:
1. First, we need to find the time taken by the trains to come to a stop after the brakes are applied.
2. We'll use the equation of motion: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
3. Since the final velocity is 0 m/s (train comes to a stop), we can rearrange the equation to solve for time: t = (v - u) / a.
4. For the first train: v1 = 0 m/s, u1 = 90 m/s, and a = -3 m/s^2.
- t1 = (0 - 90) / -3
- t1 = 30 seconds
5. For the second train: v2 = 0 m/s, u2 = 120 m/s, and a = -3 m/s^2.
- t2 = (0 - 120) / -3
- t2 = 40 seconds
6. Now that we have the time taken by each train to stop, we can calculate the distance travelled by each train using the equation of motion: s = ut + (1/2)at^2.
7. For the first train: u1 = 90 m/s, t1 = 30 s, and a = -3 m/s^2.
- s1 = (90 * 30) + (1/2) * (-3) * (30)^2
- s1 = 1350 - 1350
- s1 = 0 m
- The first train comes to a stop exactly at the point where the brakes are applied.
8. For the second train: u2 = 120 m/s, t2 = 40 s, and a = -3 m/s^2.
- s2 = (120 * 40) + (1/2) * (-3) * (40)^2
- s2 = 4800 - 2400
- s2 = 2400 m
- The second train travels a distance of 2400 meters before coming to a stop.
Answer:
The second train travels a distance of 2400 meters before coming to a stop.
- Speed of the first train (v1) = 90 m/s
- Speed of the second train (v2) = 120 m/s
- Distance between the trains when brakes are applied = 11 km = 11,000 m
- Deceleration due to brakes (a) = -3 m/s^2 (negative sign indicates deceleration)
To find:
- Distance travelled by the second train before coming to a stop
Approach:
1. First, we need to find the time taken by the trains to come to a stop after the brakes are applied.
2. We'll use the equation of motion: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
3. Since the final velocity is 0 m/s (train comes to a stop), we can rearrange the equation to solve for time: t = (v - u) / a.
4. For the first train: v1 = 0 m/s, u1 = 90 m/s, and a = -3 m/s^2.
- t1 = (0 - 90) / -3
- t1 = 30 seconds
5. For the second train: v2 = 0 m/s, u2 = 120 m/s, and a = -3 m/s^2.
- t2 = (0 - 120) / -3
- t2 = 40 seconds
6. Now that we have the time taken by each train to stop, we can calculate the distance travelled by each train using the equation of motion: s = ut + (1/2)at^2.
7. For the first train: u1 = 90 m/s, t1 = 30 s, and a = -3 m/s^2.
- s1 = (90 * 30) + (1/2) * (-3) * (30)^2
- s1 = 1350 - 1350
- s1 = 0 m
- The first train comes to a stop exactly at the point where the brakes are applied.
8. For the second train: u2 = 120 m/s, t2 = 40 s, and a = -3 m/s^2.
- s2 = (120 * 40) + (1/2) * (-3) * (40)^2
- s2 = 4800 - 2400
- s2 = 2400 m
- The second train travels a distance of 2400 meters before coming to a stop.
Answer:
The second train travels a distance of 2400 meters before coming to a stop.
Community Answer
Two trains, one travelling at 90 m/s and the other travelling at 120 m...
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Two trains, one travelling at 90 m/s and the other travelling at 120 m/s, are moving towards each other on the same track. When they are 11 km apart, both drivers simultaneously apply brakes. If the brakes decelerate each train at the rate of 3m/s2 , then the distance travelled by the second train?
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Two trains, one travelling at 90 m/s and the other travelling at 120 m/s, are moving towards each other on the same track. When they are 11 km apart, both drivers simultaneously apply brakes. If the brakes decelerate each train at the rate of 3m/s2 , then the distance travelled by the second train? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two trains, one travelling at 90 m/s and the other travelling at 120 m/s, are moving towards each other on the same track. When they are 11 km apart, both drivers simultaneously apply brakes. If the brakes decelerate each train at the rate of 3m/s2 , then the distance travelled by the second train? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two trains, one travelling at 90 m/s and the other travelling at 120 m/s, are moving towards each other on the same track. When they are 11 km apart, both drivers simultaneously apply brakes. If the brakes decelerate each train at the rate of 3m/s2 , then the distance travelled by the second train?.
Two trains, one travelling at 90 m/s and the other travelling at 120 m/s, are moving towards each other on the same track. When they are 11 km apart, both drivers simultaneously apply brakes. If the brakes decelerate each train at the rate of 3m/s2 , then the distance travelled by the second train? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two trains, one travelling at 90 m/s and the other travelling at 120 m/s, are moving towards each other on the same track. When they are 11 km apart, both drivers simultaneously apply brakes. If the brakes decelerate each train at the rate of 3m/s2 , then the distance travelled by the second train? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two trains, one travelling at 90 m/s and the other travelling at 120 m/s, are moving towards each other on the same track. When they are 11 km apart, both drivers simultaneously apply brakes. If the brakes decelerate each train at the rate of 3m/s2 , then the distance travelled by the second train?.
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Two trains, one travelling at 90 m/s and the other travelling at 120 m/s, are moving towards each other on the same track. When they are 11 km apart, both drivers simultaneously apply brakes. If the brakes decelerate each train at the rate of 3m/s2 , then the distance travelled by the second train?, a detailed solution for Two trains, one travelling at 90 m/s and the other travelling at 120 m/s, are moving towards each other on the same track. When they are 11 km apart, both drivers simultaneously apply brakes. If the brakes decelerate each train at the rate of 3m/s2 , then the distance travelled by the second train? has been provided alongside types of Two trains, one travelling at 90 m/s and the other travelling at 120 m/s, are moving towards each other on the same track. When they are 11 km apart, both drivers simultaneously apply brakes. If the brakes decelerate each train at the rate of 3m/s2 , then the distance travelled by the second train? theory, EduRev gives you an
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