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A thin cylindrical shell of mean diameter 750 mm and wall thickness 10 mm has its ends rigidly closed by flat steel plates. The shell is subjected to internal fluid pressure of 10 N/mm2 and an axial external pressure P1. If the longitudinal stress in the shell is to be zero, what should be the approximate value of P1?
- a)8 N/mm2
- b)9 N/mm2
- c)10 N/mm2
- d)12 N/mm2
Correct answer is option 'C'. Can you explain this answer?
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A thin cylindrical shell of mean diameter 750 mm and wall thickness 10...
Tensile longitudinal stress due to internal fluid pressure 
tensile. Compressive longitudinal stress due to external pressure 
tensile. Compressive longitudinal stress due to external pressure 
compressive. For zero longitudinal stress 
Most Upvoted Answer
A thin cylindrical shell of mean diameter 750 mm and wall thickness 10...
Given data:
Mean diameter of the cylindrical shell (D) = 750 mm
Wall thickness (t) = 10 mm
Internal fluid pressure (p) = 10 N/mm2
Axial external pressure (P1) = ?
Longitudinal stress (σl) = 0
Formula used:
The formula used to calculate the longitudinal stress in a cylindrical shell is given by:
σl = (pd/2t) + (P1D/2t)
Where,
σl = Longitudinal stress
p = Internal fluid pressure
d = Diameter of the cylindrical shell
t = Wall thickness of the cylindrical shell
P1 = Axial external pressure
Calculation:
Given, σl = 0
p = 10 N/mm2
D = 750 mm
t = 10 mm
Substituting the above values in the formula, we get:
0 = (10 × 750/2 × 10) + (P1 × 750/2 × 10)
0 = 375 + (P1 × 37.5)
P1 = -10 N/mm2
The negative value of P1 indicates that the external pressure is acting in the opposite direction to the internal pressure, which is not physically possible. Hence, we need to take the absolute value of the calculated pressure to get the correct answer.
P1 = | -10 N/mm2 | = 10 N/mm2
Therefore, the approximate value of axial external pressure (P1) should be 10 N/mm2 to make the longitudinal stress in the shell zero. Hence, option (c) is the correct answer.
Mean diameter of the cylindrical shell (D) = 750 mm
Wall thickness (t) = 10 mm
Internal fluid pressure (p) = 10 N/mm2
Axial external pressure (P1) = ?
Longitudinal stress (σl) = 0
Formula used:
The formula used to calculate the longitudinal stress in a cylindrical shell is given by:
σl = (pd/2t) + (P1D/2t)
Where,
σl = Longitudinal stress
p = Internal fluid pressure
d = Diameter of the cylindrical shell
t = Wall thickness of the cylindrical shell
P1 = Axial external pressure
Calculation:
Given, σl = 0
p = 10 N/mm2
D = 750 mm
t = 10 mm
Substituting the above values in the formula, we get:
0 = (10 × 750/2 × 10) + (P1 × 750/2 × 10)
0 = 375 + (P1 × 37.5)
P1 = -10 N/mm2
The negative value of P1 indicates that the external pressure is acting in the opposite direction to the internal pressure, which is not physically possible. Hence, we need to take the absolute value of the calculated pressure to get the correct answer.
P1 = | -10 N/mm2 | = 10 N/mm2
Therefore, the approximate value of axial external pressure (P1) should be 10 N/mm2 to make the longitudinal stress in the shell zero. Hence, option (c) is the correct answer.
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A thin cylindrical shell of mean diameter 750 mm and wall thickness 10 mm has its ends rigidly closed by flat steel plates. The shell is subjected to internal fluid pressure of 10 N/mm2 and an axial external pressure P1. If the longitudinal stress in the shell is to be zero, what should be the approximate value of P1?a)8 N/mm2b)9 N/mm2c)10 N/mm2d)12 N/mm2Correct answer is option 'C'. Can you explain this answer?
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A thin cylindrical shell of mean diameter 750 mm and wall thickness 10 mm has its ends rigidly closed by flat steel plates. The shell is subjected to internal fluid pressure of 10 N/mm2 and an axial external pressure P1. If the longitudinal stress in the shell is to be zero, what should be the approximate value of P1?a)8 N/mm2b)9 N/mm2c)10 N/mm2d)12 N/mm2Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A thin cylindrical shell of mean diameter 750 mm and wall thickness 10 mm has its ends rigidly closed by flat steel plates. The shell is subjected to internal fluid pressure of 10 N/mm2 and an axial external pressure P1. If the longitudinal stress in the shell is to be zero, what should be the approximate value of P1?a)8 N/mm2b)9 N/mm2c)10 N/mm2d)12 N/mm2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A thin cylindrical shell of mean diameter 750 mm and wall thickness 10 mm has its ends rigidly closed by flat steel plates. The shell is subjected to internal fluid pressure of 10 N/mm2 and an axial external pressure P1. If the longitudinal stress in the shell is to be zero, what should be the approximate value of P1?a)8 N/mm2b)9 N/mm2c)10 N/mm2d)12 N/mm2Correct answer is option 'C'. Can you explain this answer?.
A thin cylindrical shell of mean diameter 750 mm and wall thickness 10 mm has its ends rigidly closed by flat steel plates. The shell is subjected to internal fluid pressure of 10 N/mm2 and an axial external pressure P1. If the longitudinal stress in the shell is to be zero, what should be the approximate value of P1?a)8 N/mm2b)9 N/mm2c)10 N/mm2d)12 N/mm2Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A thin cylindrical shell of mean diameter 750 mm and wall thickness 10 mm has its ends rigidly closed by flat steel plates. The shell is subjected to internal fluid pressure of 10 N/mm2 and an axial external pressure P1. If the longitudinal stress in the shell is to be zero, what should be the approximate value of P1?a)8 N/mm2b)9 N/mm2c)10 N/mm2d)12 N/mm2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A thin cylindrical shell of mean diameter 750 mm and wall thickness 10 mm has its ends rigidly closed by flat steel plates. The shell is subjected to internal fluid pressure of 10 N/mm2 and an axial external pressure P1. If the longitudinal stress in the shell is to be zero, what should be the approximate value of P1?a)8 N/mm2b)9 N/mm2c)10 N/mm2d)12 N/mm2Correct answer is option 'C'. Can you explain this answer?.
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