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One Integer Value Correct Type
This section contains 3 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)
Q.
A platinum electrode is immersed in a solution containing 0.1 M Fe2+ and 0.1 M Fe3+.It iscoupled with SHE.Concentration Fe3+ of increased to 0.1 M without change in [Fe2+], then the change in EMF (in centivolt) is
Correct answer is '6'. Can you explain this answer?
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Explanation:
To understand the change in EMF when the concentration of Fe3+ is increased without any change in the concentration of Fe2+, we need to consider the Nernst equation and the half-cell reactions involved.
Nernst Equation:
The Nernst equation relates the standard electrode potential (E°) of a half-cell reaction to the actual cell potential (E) and the concentrations of the reactants and products involved. It is given by:
E = E° - (0.0592/n) * log(Q)
Where:
E = Cell potential
E° = Standard electrode potential
n = Number of electrons transferred in the half-cell reaction
Q = Reaction quotient
In this case, the half-cell reaction involving Fe2+ and Fe3+ can be represented as follows:
Fe2+ + 2e- → Fe (E1°)
Fe3+ + 3e- → Fe (E2°)
Change in EMF:
Now, let's consider the scenario where the concentration of Fe3+ is increased from 0.1 M to 0.1 M without any change in the concentration of Fe2+.
This change in concentration affects the reaction quotient (Q) in the Nernst equation. Initially, when the concentrations of Fe2+ and Fe3+ are both 0.1 M, the reaction quotient (Q1) can be calculated as follows:
Q1 = [Fe] / [Fe3+] = 0.1 / 0.1 = 1
After increasing the concentration of Fe3+ to 0.1 M, the new reaction quotient (Q2) becomes:
Q2 = [Fe] / [Fe3+] = 0.1 / 0.1 = 1
Since there is no change in the reaction quotient, the change in EMF can be calculated as follows:
ΔE = E2 - E1 = [E2° - (0.0592/n) * log(Q2)] - [E1° - (0.0592/n) * log(Q1)]
Since the standard electrode potentials (E°) for both half-cell reactions are the same (Fe2+ and Fe3+ are being reduced to Fe), they cancel out and we are left with:
ΔE = (0.0592/n) * log(Q1/Q2)
In this case, n = 2 (as per the half-cell reactions), and the change in EMF can be simplified to:
ΔE = (0.0592/2) * log(1/1) = (0.0296) * log(1) = 0
Therefore, the change in EMF is 0 centivolts, which corresponds to the integer value of 0.
The correct answer is '0', not '6'.
To understand the change in EMF when the concentration of Fe3+ is increased without any change in the concentration of Fe2+, we need to consider the Nernst equation and the half-cell reactions involved.
Nernst Equation:
The Nernst equation relates the standard electrode potential (E°) of a half-cell reaction to the actual cell potential (E) and the concentrations of the reactants and products involved. It is given by:
E = E° - (0.0592/n) * log(Q)
Where:
E = Cell potential
E° = Standard electrode potential
n = Number of electrons transferred in the half-cell reaction
Q = Reaction quotient
In this case, the half-cell reaction involving Fe2+ and Fe3+ can be represented as follows:
Fe2+ + 2e- → Fe (E1°)
Fe3+ + 3e- → Fe (E2°)
Change in EMF:
Now, let's consider the scenario where the concentration of Fe3+ is increased from 0.1 M to 0.1 M without any change in the concentration of Fe2+.
This change in concentration affects the reaction quotient (Q) in the Nernst equation. Initially, when the concentrations of Fe2+ and Fe3+ are both 0.1 M, the reaction quotient (Q1) can be calculated as follows:
Q1 = [Fe] / [Fe3+] = 0.1 / 0.1 = 1
After increasing the concentration of Fe3+ to 0.1 M, the new reaction quotient (Q2) becomes:
Q2 = [Fe] / [Fe3+] = 0.1 / 0.1 = 1
Since there is no change in the reaction quotient, the change in EMF can be calculated as follows:
ΔE = E2 - E1 = [E2° - (0.0592/n) * log(Q2)] - [E1° - (0.0592/n) * log(Q1)]
Since the standard electrode potentials (E°) for both half-cell reactions are the same (Fe2+ and Fe3+ are being reduced to Fe), they cancel out and we are left with:
ΔE = (0.0592/n) * log(Q1/Q2)
In this case, n = 2 (as per the half-cell reactions), and the change in EMF can be simplified to:
ΔE = (0.0592/2) * log(1/1) = (0.0296) * log(1) = 0
Therefore, the change in EMF is 0 centivolts, which corresponds to the integer value of 0.
The correct answer is '0', not '6'.
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One Integer Value Correct TypeThis section contains 3questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q. A platinum electrode is immersed in a solution containing 0.1 M Fe2+and 0.1 MFe3+.It iscoupled with SHE.Concentration Fe3+of increased to 0.1 M without change in [Fe2+], then the change in EMF (in centivolt) isCorrect answer is '6'. Can you explain this answer?
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One Integer Value Correct TypeThis section contains 3questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q. A platinum electrode is immersed in a solution containing 0.1 M Fe2+and 0.1 MFe3+.It iscoupled with SHE.Concentration Fe3+of increased to 0.1 M without change in [Fe2+], then the change in EMF (in centivolt) isCorrect answer is '6'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One Integer Value Correct TypeThis section contains 3questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q. A platinum electrode is immersed in a solution containing 0.1 M Fe2+and 0.1 MFe3+.It iscoupled with SHE.Concentration Fe3+of increased to 0.1 M without change in [Fe2+], then the change in EMF (in centivolt) isCorrect answer is '6'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One Integer Value Correct TypeThis section contains 3questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q. A platinum electrode is immersed in a solution containing 0.1 M Fe2+and 0.1 MFe3+.It iscoupled with SHE.Concentration Fe3+of increased to 0.1 M without change in [Fe2+], then the change in EMF (in centivolt) isCorrect answer is '6'. Can you explain this answer?.
One Integer Value Correct TypeThis section contains 3questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q. A platinum electrode is immersed in a solution containing 0.1 M Fe2+and 0.1 MFe3+.It iscoupled with SHE.Concentration Fe3+of increased to 0.1 M without change in [Fe2+], then the change in EMF (in centivolt) isCorrect answer is '6'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One Integer Value Correct TypeThis section contains 3questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q. A platinum electrode is immersed in a solution containing 0.1 M Fe2+and 0.1 MFe3+.It iscoupled with SHE.Concentration Fe3+of increased to 0.1 M without change in [Fe2+], then the change in EMF (in centivolt) isCorrect answer is '6'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One Integer Value Correct TypeThis section contains 3questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q. A platinum electrode is immersed in a solution containing 0.1 M Fe2+and 0.1 MFe3+.It iscoupled with SHE.Concentration Fe3+of increased to 0.1 M without change in [Fe2+], then the change in EMF (in centivolt) isCorrect answer is '6'. Can you explain this answer?.
Solutions for One Integer Value Correct TypeThis section contains 3questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q. A platinum electrode is immersed in a solution containing 0.1 M Fe2+and 0.1 MFe3+.It iscoupled with SHE.Concentration Fe3+of increased to 0.1 M without change in [Fe2+], then the change in EMF (in centivolt) isCorrect answer is '6'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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