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One Integer Value Correct Type
This section contains 3 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)
Q.
A platinum electrode is immersed in a solution containing 0.1 M Fe2+ and 0.1 M Fe3+.It iscoupled with SHE.Concentration Fe3+ of increased to 0.1 M without change in [Fe2+], then the change in EMF (in centivolt) is 
    Correct answer is '6'. Can you explain this answer?
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    Explanation:

    To understand the change in EMF when the concentration of Fe3+ is increased without any change in the concentration of Fe2+, we need to consider the Nernst equation and the half-cell reactions involved.

    Nernst Equation:
    The Nernst equation relates the standard electrode potential (E°) of a half-cell reaction to the actual cell potential (E) and the concentrations of the reactants and products involved. It is given by:

    E = E° - (0.0592/n) * log(Q)

    Where:
    E = Cell potential
    E° = Standard electrode potential
    n = Number of electrons transferred in the half-cell reaction
    Q = Reaction quotient

    In this case, the half-cell reaction involving Fe2+ and Fe3+ can be represented as follows:

    Fe2+ + 2e- → Fe (E1°)

    Fe3+ + 3e- → Fe (E2°)

    Change in EMF:
    Now, let's consider the scenario where the concentration of Fe3+ is increased from 0.1 M to 0.1 M without any change in the concentration of Fe2+.

    This change in concentration affects the reaction quotient (Q) in the Nernst equation. Initially, when the concentrations of Fe2+ and Fe3+ are both 0.1 M, the reaction quotient (Q1) can be calculated as follows:

    Q1 = [Fe] / [Fe3+] = 0.1 / 0.1 = 1

    After increasing the concentration of Fe3+ to 0.1 M, the new reaction quotient (Q2) becomes:

    Q2 = [Fe] / [Fe3+] = 0.1 / 0.1 = 1

    Since there is no change in the reaction quotient, the change in EMF can be calculated as follows:

    ΔE = E2 - E1 = [E2° - (0.0592/n) * log(Q2)] - [E1° - (0.0592/n) * log(Q1)]

    Since the standard electrode potentials (E°) for both half-cell reactions are the same (Fe2+ and Fe3+ are being reduced to Fe), they cancel out and we are left with:

    ΔE = (0.0592/n) * log(Q1/Q2)

    In this case, n = 2 (as per the half-cell reactions), and the change in EMF can be simplified to:

    ΔE = (0.0592/2) * log(1/1) = (0.0296) * log(1) = 0

    Therefore, the change in EMF is 0 centivolts, which corresponds to the integer value of 0.

    The correct answer is '0', not '6'.
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    One Integer Value Correct TypeThis section contains 3questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q. A platinum electrode is immersed in a solution containing 0.1 M Fe2+and 0.1 MFe3+.It iscoupled with SHE.Concentration Fe3+of increased to 0.1 M without change in [Fe2+], then the change in EMF (in centivolt) isCorrect answer is '6'. Can you explain this answer?
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