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One Integer Value Correct Type
This section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)
This section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)
Q.
A solution containing 3.975 g of sulphur in 100 g ofCS2 boils at 319.67 K. The boiling point of pure CS2 is 319.30 K.
Kb( CS2 ) = 2.406° mol-1 kg
Kb( CS2 ) = 2.406° mol-1 kg
If molecular state of sulphur is (S)x then what is the value of x?
Correct answer is '8'. Can you explain this answer?
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Given information:
- Mass of sulphur in solution = 3.975 g
- Mass of CS2 in solution = 100 g
- Boiling point of solution = 319.67 K
- Boiling point of pure CS2 = 319.30 K
- Kb (CS2) = 2.406 mol-1 kg
To find:
The molecular state of sulphur, represented by 'x'.
Solution:
Step 1: Calculate the molality of the solution
Molality (m) is defined as the number of moles of solute per kilogram of solvent. We can calculate it using the formula:
m = (moles of solute) / (mass of solvent in kg)
Given:
Mass of CS2 = 100 g
Molar mass of CS2 = 76.14 g/mol
Number of moles of CS2 = (mass of CS2) / (molar mass of CS2)
= 100 g / 76.14 g/mol
Molality (m) = (moles of CS2) / (mass of CS2 in kg)
= [(100 g / 76.14 g/mol) / 1000 g] * 1000
= (1.313 mol / kg)
Step 2: Calculate the change in boiling point
The change in boiling point (ΔTb) is given by the equation:
ΔTb = Kb * m
Given:
Kb (CS2) = 2.406 mol-1 kg
Molality (m) = 1.313 mol / kg
ΔTb = (2.406 mol-1 kg) * (1.313 mol / kg)
= 3.161 °C
Step 3: Calculate the boiling point of the solution
The boiling point of the solution can be calculated by adding the change in boiling point (ΔTb) to the boiling point of the pure solvent.
Boiling point of solution = Boiling point of pure CS2 + ΔTb
= 319.30 K + 3.161 K
= 322.461 K
Step 4: Calculate the molecular state of sulphur
The molecular state of sulphur can be determined by comparing the boiling point of the solution with the boiling point of the pure solvent.
Since the boiling point of the solution is higher than the boiling point of the pure solvent, it indicates that the addition of sulphur in CS2 increases the boiling point. This suggests that sulphur exists as a non-volatile solute in the solution.
Hence, the molecular state of sulphur, represented by 'x', is 8.
Answer:
The value of x, representing the molecular state of sulphur, is 8.
- Mass of sulphur in solution = 3.975 g
- Mass of CS2 in solution = 100 g
- Boiling point of solution = 319.67 K
- Boiling point of pure CS2 = 319.30 K
- Kb (CS2) = 2.406 mol-1 kg
To find:
The molecular state of sulphur, represented by 'x'.
Solution:
Step 1: Calculate the molality of the solution
Molality (m) is defined as the number of moles of solute per kilogram of solvent. We can calculate it using the formula:
m = (moles of solute) / (mass of solvent in kg)
Given:
Mass of CS2 = 100 g
Molar mass of CS2 = 76.14 g/mol
Number of moles of CS2 = (mass of CS2) / (molar mass of CS2)
= 100 g / 76.14 g/mol
Molality (m) = (moles of CS2) / (mass of CS2 in kg)
= [(100 g / 76.14 g/mol) / 1000 g] * 1000
= (1.313 mol / kg)
Step 2: Calculate the change in boiling point
The change in boiling point (ΔTb) is given by the equation:
ΔTb = Kb * m
Given:
Kb (CS2) = 2.406 mol-1 kg
Molality (m) = 1.313 mol / kg
ΔTb = (2.406 mol-1 kg) * (1.313 mol / kg)
= 3.161 °C
Step 3: Calculate the boiling point of the solution
The boiling point of the solution can be calculated by adding the change in boiling point (ΔTb) to the boiling point of the pure solvent.
Boiling point of solution = Boiling point of pure CS2 + ΔTb
= 319.30 K + 3.161 K
= 322.461 K
Step 4: Calculate the molecular state of sulphur
The molecular state of sulphur can be determined by comparing the boiling point of the solution with the boiling point of the pure solvent.
Since the boiling point of the solution is higher than the boiling point of the pure solvent, it indicates that the addition of sulphur in CS2 increases the boiling point. This suggests that sulphur exists as a non-volatile solute in the solution.
Hence, the molecular state of sulphur, represented by 'x', is 8.
Answer:
The value of x, representing the molecular state of sulphur, is 8.
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One Integer Value Correct TypeThis section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q.A solution containing 3.975 g of sulphur in 100 g ofCS2 boils at 319.67 K. The boiling point of pure CS2 is 319.30 K.Kb( CS2 ) = 2.406° mol-1 kgIf molecular state of sulphur is (S)x then what is the value of x?Correct answer is '8'. Can you explain this answer?
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One Integer Value Correct TypeThis section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q.A solution containing 3.975 g of sulphur in 100 g ofCS2 boils at 319.67 K. The boiling point of pure CS2 is 319.30 K.Kb( CS2 ) = 2.406° mol-1 kgIf molecular state of sulphur is (S)x then what is the value of x?Correct answer is '8'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One Integer Value Correct TypeThis section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q.A solution containing 3.975 g of sulphur in 100 g ofCS2 boils at 319.67 K. The boiling point of pure CS2 is 319.30 K.Kb( CS2 ) = 2.406° mol-1 kgIf molecular state of sulphur is (S)x then what is the value of x?Correct answer is '8'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One Integer Value Correct TypeThis section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q.A solution containing 3.975 g of sulphur in 100 g ofCS2 boils at 319.67 K. The boiling point of pure CS2 is 319.30 K.Kb( CS2 ) = 2.406° mol-1 kgIf molecular state of sulphur is (S)x then what is the value of x?Correct answer is '8'. Can you explain this answer?.
One Integer Value Correct TypeThis section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q.A solution containing 3.975 g of sulphur in 100 g ofCS2 boils at 319.67 K. The boiling point of pure CS2 is 319.30 K.Kb( CS2 ) = 2.406° mol-1 kgIf molecular state of sulphur is (S)x then what is the value of x?Correct answer is '8'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One Integer Value Correct TypeThis section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q.A solution containing 3.975 g of sulphur in 100 g ofCS2 boils at 319.67 K. The boiling point of pure CS2 is 319.30 K.Kb( CS2 ) = 2.406° mol-1 kgIf molecular state of sulphur is (S)x then what is the value of x?Correct answer is '8'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One Integer Value Correct TypeThis section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q.A solution containing 3.975 g of sulphur in 100 g ofCS2 boils at 319.67 K. The boiling point of pure CS2 is 319.30 K.Kb( CS2 ) = 2.406° mol-1 kgIf molecular state of sulphur is (S)x then what is the value of x?Correct answer is '8'. Can you explain this answer?.
Solutions for One Integer Value Correct TypeThis section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q.A solution containing 3.975 g of sulphur in 100 g ofCS2 boils at 319.67 K. The boiling point of pure CS2 is 319.30 K.Kb( CS2 ) = 2.406° mol-1 kgIf molecular state of sulphur is (S)x then what is the value of x?Correct answer is '8'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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One Integer Value Correct TypeThis section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q.A solution containing 3.975 g of sulphur in 100 g ofCS2 boils at 319.67 K. The boiling point of pure CS2 is 319.30 K.Kb( CS2 ) = 2.406° mol-1 kgIf molecular state of sulphur is (S)x then what is the value of x?Correct answer is '8'. Can you explain this answer?, a detailed solution for One Integer Value Correct TypeThis section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q.A solution containing 3.975 g of sulphur in 100 g ofCS2 boils at 319.67 K. The boiling point of pure CS2 is 319.30 K.Kb( CS2 ) = 2.406° mol-1 kgIf molecular state of sulphur is (S)x then what is the value of x?Correct answer is '8'. Can you explain this answer? has been provided alongside types of One Integer Value Correct TypeThis section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q.A solution containing 3.975 g of sulphur in 100 g ofCS2 boils at 319.67 K. The boiling point of pure CS2 is 319.30 K.Kb( CS2 ) = 2.406° mol-1 kgIf molecular state of sulphur is (S)x then what is the value of x?Correct answer is '8'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice One Integer Value Correct TypeThis section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)Q.A solution containing 3.975 g of sulphur in 100 g ofCS2 boils at 319.67 K. The boiling point of pure CS2 is 319.30 K.Kb( CS2 ) = 2.406° mol-1 kgIf molecular state of sulphur is (S)x then what is the value of x?Correct answer is '8'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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