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At 143 K, the reaction of XeF4 with O2F2 produces xenon compound Y. The total number of lone Pair(s) of electrons present on the whole molecule of Y is ………
    Correct answer is '19.00'. Can you explain this answer?
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    At 143 K, the reaction of XeF4 with O2F2 produces xenon compound Y. Th...
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    At 143 K, the reaction of XeF4 with O2F2 produces xenon compound Y. Th...
    To determine the number of lone pairs of electrons on the molecule of Y, we first need to write the balanced chemical equation for the reaction of XeF4 with O2F2:

    XeF4 + 2O2F2 -> XeOF4 + 2OF2

    From this equation, we can see that the product Y is XeOF4. To determine the number of lone pairs of electrons on XeOF4, we need to draw its Lewis structure.

    First, we determine the total number of valence electrons in XeOF4:

    Xe: 8 valence electrons
    O: 6 valence electrons x 4 = 24 valence electrons
    Total: 32 valence electrons

    We then arrange the atoms in the molecule with Xe as the central atom:

    F
    |
    O Xe O
    |
    F

    Each bond in the molecule represents two electrons, so we can subtract 8 electrons for the four Xe-O bonds:

    32 valence electrons - 8 electrons in Xe-O bonds = 24 electrons

    We then distribute the remaining 24 electrons as lone pairs around the atoms:

    F
    |
    O Xe O
    | || |
    e- LP e-
    |
    F

    Each lone pair represents two electrons, so we can count the number of lone pairs to find the total number of lone pair electrons on the molecule:

    4 lone pairs x 2 electrons per lone pair = 8 electrons

    Therefore, the total number of lone pair electrons on the whole molecule of XeOF4 (product Y) is 8.
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    At 143 K, the reaction of XeF4 with O2F2 produces xenon compound Y. Th...
    XeF4 +O2F2 ===> XeF6 + O2


    in XeF6 , six flourine atoms have 6×3=18 lone pairs of electrons and Xe atom has one lone pair
    In total 19 lone pairs (& 6 bond pairs of e-)
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    Chemical reactions involve interaction of atoms and molecules. A large number of atoms/molecules (approximately 6.023 × 1023) are present in a few grams of any chemical compound varying with their atomic/molecular masses. To handle such large numbers conveniently, the mole concept was introduced.This concept has implications in diverse areas such as analytical chemistry, biochemistry, electrochemistry and radiochemistry. The following example illustrates a typical case, involving chemical/electrochemical reaction, which requires a clear understanding of the mole concept. A 4.0 molar aqueous solution NaCl is prepared and 500 mL of this solution is electrolysed. This leads to the evolution of chlorine gas at one of the electrodes (atomic mass: Na = 23, Hg = 200; 1 Faraday = 96,500 coulombs)If the cathode is a Hg electrode, the maximum weight (g) of amalgam formed from this solution is Correct answer is '446'. Can you explain this answer?

    On the basis of aromaticity, there are three types of compounds i.e. aromatic, non-aromatic and antiaromatic. The increasing order of stability of these compounds are is under: Anti-aromatic compound < non-aromatic compound < aromatic compounds. Compounds to be aromaticfollow the following conditions (according to valence bond theory)(i) The compounds must be be cyclic in structure having (4n + 2)π e–, where n = Hückel’s number = 0, 1, 2, 3 et.c(ii) The each atoms of the cyclic structure must have unhybridised p-orbital i.e. the atoms of the compounds have unhybridised p-orbital i.e. usually have sp2 hybrid or planar.(iii) There must be a ring current of π electrons in the ring or cyclic structure i.e. cyclic structure mustundergo resonance .Compounds to be anti-aromatic, it must have 4nπe– where n = 1, 2… and it must be planar and undergo resonance. Non-aromatic compounds the name itself spells that compounds must be non-planarirrespective of number of π electrons. Either it has 4nπe– or (4n + 2) π electrons it does not matter.The rate of reaction of any aromatic compounds depends upon the following factors:(i) Electron density(ii) stability of carbocation producedHigher the amount of electron density of the ring, higher will be its rate towards aromatic electrophilic substitution and vice-versa. Similarly, higher will be the stability of the produced carbocation after the attack of electrophile, higher will be its rate towards aromatic electrophilic substitution. There is a great effect of kinetic labelling on the rate of aromatic electrophilic substitution. As we known that higher the atomic weight or, molecualr weight, higher will be the van der Waal’s force of attraction or, bond energy. Since there will be effect of kienetic labelling if the 2nd step of the reaction will be the slow step, (r.d.s.) otherwise there will be no effect of kinetic labelling.Q. Which of the following is correct order of the rate of reaction of C6H6, C6D6 and C6T6 towardssulphonation?

    Can you explain the answer of this question below:On the basis of aromaticity, there are three types of compounds i.e. aromatic, non-aromatic and antiaromatic.The increasing order of stability of these compounds are is under:Anti-aromatic compound non-aromatic compound aromatic compounds. Compounds to be aromaticfollow the following conditions (according to valence bond theory)(i) The compounds must be be cyclic in structure having (4n + 2) e, where n = Hckels number = 0, 1,2, 3 et.c(ii) The each atoms of the cyclic structure must have unhybridised p-orbital i.e. the atoms of thecompounds have unhybridised p-orbital i.e. usually have sp2 hybrid or planar.(iii) There must be a ring current of electrons in the ring or cyclic structure i.e. cyclic structure mustundergo resonance .Compounds to be anti-aromatic, it must have 4ne where n = 1, 2 and it must be planar and undergoresonance. Non-aromatic compounds the name itself spells that compounds must be non-planarirrespective of number of electrons. Either it has 4ne or (4n + 2) electrons it does not matter.The rate of reaction of any aromatic compounds depends upon the following factors:(i) Electron density(ii) stability of carbocation producedHigher the amount of electron density of the ring, higher will be its rate towards aromatic electrophilicsubstitution and vice-versa. Similarly, higher will be the stability of the produced carbocation after theattack of electrophile, higher will be its rate towards aromatic electrophilic substitution. There is a greateffect of kinetic labelling on the rate of aromatic electrophilic substitution. As we known that higher theatomic weight or, molecualr weight, higher will be the van der Waals force of attraction or, bond energy.Since there will be effect of kienetic labelling if the 2nd step of the reaction will be the slow step, (r.d.s.)otherwise there will be no effect of kinetic labelling.Q. Which of the following is correct order of the rate of reaction of C6H6, C6D6 and C6T6 towardsnitrations?A:C6H6 C6D6 C6T6B:C6H6 = C6D6 = C6T6C:C6H6 C6D6 = C6T6D:C6T6 C6D6 C6H6The answer is b.

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    At 143 K, the reaction of XeF4 with O2F2 produces xenon compound Y. The total number of lone Pair(s) of electrons present on the whole molecule of Y is ………Correct answer is '19.00'. Can you explain this answer?
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    At 143 K, the reaction of XeF4 with O2F2 produces xenon compound Y. The total number of lone Pair(s) of electrons present on the whole molecule of Y is ………Correct answer is '19.00'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about At 143 K, the reaction of XeF4 with O2F2 produces xenon compound Y. The total number of lone Pair(s) of electrons present on the whole molecule of Y is ………Correct answer is '19.00'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 143 K, the reaction of XeF4 with O2F2 produces xenon compound Y. The total number of lone Pair(s) of electrons present on the whole molecule of Y is ………Correct answer is '19.00'. Can you explain this answer?.
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