A thin walled water pipe carries water under a pressure of 2 N/mm2 and...
Given data:
Pressure (p) = 2 N/mm²
Diameter (d) = 25 mm
Thickness (t) = 25 mm
We need to find the longitudinal stress induced in the pipe.
Formula:
The longitudinal stress induced in the pipe is given by the formula:
σl = pd/2t
where,
σl = longitudinal stress induced
p = pressure
d = diameter
t = thickness
Calculation:
Substituting the given values in the above formula, we get:
σl = (2×25)/2×25
σl = 5 N/mm²
Therefore, the longitudinal stress induced in the pipe is 5 N/mm².
Conclusion:
When a thin walled water pipe carries water under pressure, the longitudinal stress induced in the pipe can be calculated using the formula σl = pd/2t. In this case, the longitudinal stress induced in the pipe is 5 N/mm².
A thin walled water pipe carries water under a pressure of 2 N/mm2 and...
Answer should be option a, 0. Reason: Even though the pipe is under internal pressure, there is no axial load acting,i.e., the pipe is flow is not restricted. So no axial pull is present. Hence no axial stress.