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A single coloumn manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find the pressure in the pipe if the area of reservoir is 250 times the area of tube for the manometer reading. The difference in mercury level is 40 cm. On the left limb the fluid is upto the height of 20 cm.
- a)10.42 N/cm2
- b)5.21 N/cm2
- c)2.60 N/cm2
- d)None of the mentioned
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A single coloumn manometer is connected to a pipe containing a liquid ...
Explanation: Pressure = a/A height × (density of mercury × 9.81-density of fluid × 9.81)+ height in right limb × density of mercury × 9.81 – height in left limb × density of fluid × 9.81
= 5.21 N/cm2
{ Here a/A = 1/ 250}.
= 5.21 N/cm2
{ Here a/A = 1/ 250}.
Most Upvoted Answer
A single coloumn manometer is connected to a pipe containing a liquid ...
Given:
Specific gravity of liquid = 0.75
Difference in mercury level = 40 cm
Height of fluid on left limb = 20 cm
Area of reservoir / Area of tube = 250
To find:
Pressure in the pipe
Solution:
1. Find the density of the liquid using the specific gravity:
Density of liquid = Specific gravity x Density of water
Density of water = 1000 kg/m³
Density of liquid = 0.75 x 1000 = 750 kg/m³
2. Find the pressure difference between the two limbs of the manometer:
Pressure difference = Density of mercury x Difference in mercury level
Density of mercury = 13600 kg/m³
Pressure difference = 13600 x 0.4 = 5440 N/m²
3. Find the pressure of the liquid in the pipe at the level of the manometer:
Pressure of liquid = Density of liquid x Height of fluid on left limb
Pressure of liquid = 750 x 0.2 = 150 N/m²
4. Find the pressure of the liquid in the pipe at the level of the reservoir:
Pressure of liquid at reservoir = Pressure of liquid + Pressure difference
Pressure of liquid at reservoir = 150 + 5440 = 5590 N/m²
5. Find the pressure in the pipe:
Let the pressure in the pipe be P.
Pressure at reservoir = P + (Density of liquid x g x Height of reservoir)
Height of reservoir / Height of tube = Area of tube / Area of reservoir
Height of reservoir = (Area of tube / Area of reservoir) x Height of tube
Height of tube = Height of fluid on left limb + Difference in mercury level
Height of tube = 20 + 40 = 60 cm = 0.6 m
Height of reservoir = (1/250) x 0.6 = 0.0024 m
P + (750 x 9.81 x 0.0024) = 5590
P = 5219.8 N/m²
Therefore, the pressure in the pipe is 5.21 N/cm².
Answer: (b) 5.21 N/cm²
Specific gravity of liquid = 0.75
Difference in mercury level = 40 cm
Height of fluid on left limb = 20 cm
Area of reservoir / Area of tube = 250
To find:
Pressure in the pipe
Solution:
1. Find the density of the liquid using the specific gravity:
Density of liquid = Specific gravity x Density of water
Density of water = 1000 kg/m³
Density of liquid = 0.75 x 1000 = 750 kg/m³
2. Find the pressure difference between the two limbs of the manometer:
Pressure difference = Density of mercury x Difference in mercury level
Density of mercury = 13600 kg/m³
Pressure difference = 13600 x 0.4 = 5440 N/m²
3. Find the pressure of the liquid in the pipe at the level of the manometer:
Pressure of liquid = Density of liquid x Height of fluid on left limb
Pressure of liquid = 750 x 0.2 = 150 N/m²
4. Find the pressure of the liquid in the pipe at the level of the reservoir:
Pressure of liquid at reservoir = Pressure of liquid + Pressure difference
Pressure of liquid at reservoir = 150 + 5440 = 5590 N/m²
5. Find the pressure in the pipe:
Let the pressure in the pipe be P.
Pressure at reservoir = P + (Density of liquid x g x Height of reservoir)
Height of reservoir / Height of tube = Area of tube / Area of reservoir
Height of reservoir = (Area of tube / Area of reservoir) x Height of tube
Height of tube = Height of fluid on left limb + Difference in mercury level
Height of tube = 20 + 40 = 60 cm = 0.6 m
Height of reservoir = (1/250) x 0.6 = 0.0024 m
P + (750 x 9.81 x 0.0024) = 5590
P = 5219.8 N/m²
Therefore, the pressure in the pipe is 5.21 N/cm².
Answer: (b) 5.21 N/cm²
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A single coloumn manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find the pressure in the pipe if the area of reservoir is 250 times the area of tube for the manometer reading. The difference in mercury level is 40 cm. On the left limb the fluid is upto the height of 20 cm.a)10.42 N/cm2b)5.21 N/cm2c)2.60 N/cm2d)None of the mentionedCorrect answer is option 'B'. Can you explain this answer?
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A single coloumn manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find the pressure in the pipe if the area of reservoir is 250 times the area of tube for the manometer reading. The difference in mercury level is 40 cm. On the left limb the fluid is upto the height of 20 cm.a)10.42 N/cm2b)5.21 N/cm2c)2.60 N/cm2d)None of the mentionedCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A single coloumn manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find the pressure in the pipe if the area of reservoir is 250 times the area of tube for the manometer reading. The difference in mercury level is 40 cm. On the left limb the fluid is upto the height of 20 cm.a)10.42 N/cm2b)5.21 N/cm2c)2.60 N/cm2d)None of the mentionedCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single coloumn manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find the pressure in the pipe if the area of reservoir is 250 times the area of tube for the manometer reading. The difference in mercury level is 40 cm. On the left limb the fluid is upto the height of 20 cm.a)10.42 N/cm2b)5.21 N/cm2c)2.60 N/cm2d)None of the mentionedCorrect answer is option 'B'. Can you explain this answer?.
A single coloumn manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find the pressure in the pipe if the area of reservoir is 250 times the area of tube for the manometer reading. The difference in mercury level is 40 cm. On the left limb the fluid is upto the height of 20 cm.a)10.42 N/cm2b)5.21 N/cm2c)2.60 N/cm2d)None of the mentionedCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A single coloumn manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find the pressure in the pipe if the area of reservoir is 250 times the area of tube for the manometer reading. The difference in mercury level is 40 cm. On the left limb the fluid is upto the height of 20 cm.a)10.42 N/cm2b)5.21 N/cm2c)2.60 N/cm2d)None of the mentionedCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single coloumn manometer is connected to a pipe containing a liquid of specific gravity 0.75. Find the pressure in the pipe if the area of reservoir is 250 times the area of tube for the manometer reading. The difference in mercury level is 40 cm. On the left limb the fluid is upto the height of 20 cm.a)10.42 N/cm2b)5.21 N/cm2c)2.60 N/cm2d)None of the mentionedCorrect answer is option 'B'. Can you explain this answer?.
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