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The total number of instantaneous centres for a mechanism for n links is

  • a)
    n(n-1)/2

  • b)
    n

  • c)
    n –1

  • d)
    n/2

  • e)
    n(n - 1)

Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The total number of instantaneous centres for a mechanism for n links ...
The number of pairs of links or the number of instantaneous centres is the number of combinations of n links taken two at a time. Mathematically, number of instantaneous centresN = n(n – 1)/2
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Most Upvoted Answer
The total number of instantaneous centres for a mechanism for n links ...
(n-1)
d)2n
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Community Answer
The total number of instantaneous centres for a mechanism for n links ...
N(n-1)/2
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