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Let [ε0] denote the dimensional formula of the permittivity of the  vacuum, and [μ0] that of the permeability of the vacuum. If M = mass, L = length,  T = time and I = electric current,
  • a)
    0] = M-1 L-3T2 Ι
  • b)
    0] = M -1 L-3T4 Ι2
  • c)
    0]= M LT-2 Ι-2
  • d)
    0] = M L2T -1Ι
Correct answer is option 'B,C'. Can you explain this answer?
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Let [ε0] denote the dimensional formula of the permittivity of...

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Let [ε0] denote the dimensional formula of the permittivity of...
Explanation:

a) Dimensional formula for permittivity of vacuum, ε0:
- The formula for permittivity of vacuum includes dimensions for mass (M), length (L), time (T), and electric current (I).
- The correct formula is M-1 L-3T4 Ι2. This is because permittivity is measured in F/m (farads per meter), which corresponds to the given dimensions.

b) Dimensional formula for permeability of vacuum, μ0:
- The formula for permeability of vacuum also includes dimensions for mass (M), length (L), time (T), and electric current (I).
- The correct formula is M LT-2 Ι-2. This is because permeability is measured in H/m (henries per meter), which corresponds to the given dimensions.
Therefore, the correct dimensional formulas for the permittivity of vacuum (ε0) and the permeability of vacuum (μ0) are as follows:
- ε0 = M-1 L-3T4 Ι2
- μ0 = M LT-2 Ι-2
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Let [ε0] denote the dimensional formula of the permittivity of the vacuum, and [μ0] that of the permeability of the vacuum. If M = mass, L = length, T = time and I = electric current,a)[ε0] = M-1 L-3T2 Ιb)[ε0] = M -1 L-3T4 Ι2c)[μ0]= M LT-2 Ι-2d)[μ0] = M L2T -1ΙCorrect answer is option 'B,C'. Can you explain this answer?
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Let [ε0] denote the dimensional formula of the permittivity of the vacuum, and [μ0] that of the permeability of the vacuum. If M = mass, L = length, T = time and I = electric current,a)[ε0] = M-1 L-3T2 Ιb)[ε0] = M -1 L-3T4 Ι2c)[μ0]= M LT-2 Ι-2d)[μ0] = M L2T -1ΙCorrect answer is option 'B,C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let [ε0] denote the dimensional formula of the permittivity of the vacuum, and [μ0] that of the permeability of the vacuum. If M = mass, L = length, T = time and I = electric current,a)[ε0] = M-1 L-3T2 Ιb)[ε0] = M -1 L-3T4 Ι2c)[μ0]= M LT-2 Ι-2d)[μ0] = M L2T -1ΙCorrect answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let [ε0] denote the dimensional formula of the permittivity of the vacuum, and [μ0] that of the permeability of the vacuum. If M = mass, L = length, T = time and I = electric current,a)[ε0] = M-1 L-3T2 Ιb)[ε0] = M -1 L-3T4 Ι2c)[μ0]= M LT-2 Ι-2d)[μ0] = M L2T -1ΙCorrect answer is option 'B,C'. Can you explain this answer?.
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