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Let N be the set of natural numbers. Consider the following sets, P: Set of Rational numbers (positive and negative) Q: Set of functions from {0, 1} to N R: Set of functions from N to {0, 1} S: Set of finite subsets of N Which of the above sets are countable?
  • a)
    Q and S only
  • b)
    P and S only
  • c)
    P and R only
  • d)
    P, Q and S only
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Let N be the set of natural numbers. Consider the following sets, P: S...
Set of Rational numbers (+ve or -ve) are countable.. Set of functions from {0, 1} to N are countable because it has one to one correspondence to N. Set of functions from N to {0, 1} is uncountable, because it has one to one correspondence to set of real numbers between (0 and 1). Set of finite subsets of N is countable. Sets P, Q and S are countable, therefore option (D) is Correct.
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Most Upvoted Answer
Let N be the set of natural numbers. Consider the following sets, P: S...
The correct answer is option 'D', which means that the sets P, Q, and S are countable. Let's analyze each set to understand why they are countable.

1. Set P: Set of Rational numbers (positive and negative)
- Rational numbers can be represented as fractions, where the numerator and denominator are integers.
- We can list all the rational numbers by enumerating the fractions in a systematic way, such as by listing them in increasing order of their absolute values.
- Since the set of integers is countable, and every rational number can be expressed as a fraction of two integers, the set of rational numbers is countable.

2. Set Q: Set of functions from {0, 1} to N
- A function from {0, 1} to N can be represented as a pair of natural numbers.
- We can list all the possible pairs of natural numbers in a systematic way, such as by listing them in increasing order of their sum.
- Since the set of natural numbers is countable, the set of functions from {0, 1} to N is countable.

3. Set R: Set of functions from N to {0, 1}
- A function from N to {0, 1} can be thought of as a sequence of 0s and 1s.
- We can list all the possible sequences of 0s and 1s in a systematic way, such as by listing them in lexicographic order (dictionary order).
- Since the set of sequences of 0s and 1s is equivalent to the set of binary numbers, which is countable, the set of functions from N to {0, 1} is countable.

4. Set S: Set of finite subsets of N
- A finite subset of N can be represented as a sequence of natural numbers.
- We can list all the possible finite sequences of natural numbers in a systematic way, such as by listing them in lexicographic order.
- Since the set of finite sequences of natural numbers is countable, the set of finite subsets of N is countable.

In conclusion, the sets P, Q, and S are countable because they can be enumerated in a systematic way. Therefore, the correct answer is option 'D' - P, Q, and S only.
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Let N be the set of natural numbers. Consider the following sets, P: Set of Rational numbers (positive and negative) Q: Set of functions from {0, 1} to N R: Set of functions from N to {0, 1} S: Set of finite subsets of N Which of the above sets are countable?a)Q and S onlyb)P and S onlyc)P and R onlyd)P, Q and S onlyCorrect answer is option 'D'. Can you explain this answer?
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