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The right limb of a simple U-tube manometer containing mercury is open to the atmosphere while the lift limb is connected to a pipe in which a fluid of specific gravity 0.85 is flowing. The centre of the pipe is 14 cm below the level of mercury in the right limb.Evaluate the pressure of fluid flowing in the pipe if the difference of mercury level in the two limbs is 22 cm.
- a)2.86 N/cm2
- b)5.73 N/cm2
- c)1.43 N/cm2
- d)None of the mentioned
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The right limb of a simple U-tube manometer containing mercury is open...
Explanation: Pressure at centre of pipe + Pressure at depth 8 cm in left limb = Pressure at depth 22 cm in right limb
P = 13600×9.81×0.22 – 850×9.81×.08
= 2.86 N/cm2.
P = 13600×9.81×0.22 – 850×9.81×.08
= 2.86 N/cm2.
Most Upvoted Answer
The right limb of a simple U-tube manometer containing mercury is open...
Given data:
Specific gravity of fluid (s) = 0.85
Mercury level difference (h) = 22 cm
Centre of pipe below mercury level (d) = 14 cm
To find: Pressure of fluid flowing in the pipe
Formula used:
Pressure head = h1 - h2
Where h1 and h2 are the heights of the fluid column in the two limbs of the manometer.
Calculation:
The pressure of the fluid flowing in the pipe can be calculated by using the formula:
P = sgh
Where P is the pressure, s is the specific gravity of the fluid, g is the acceleration due to gravity (9.81 m/s2), and h is the height of the fluid column.
Here, the specific gravity of the fluid is given as 0.85. Therefore, the density of the fluid can be calculated as:
ρ = s × ρwater
Where ρwater is the density of water (1000 kg/m3).
ρ = 0.85 × 1000 = 850 kg/m3
The height of the fluid column can be calculated as:
h = d + h1 - h2
Where d is the distance between the centre of the pipe and the mercury level in the right limb of the manometer.
h = 14 cm + 22 cm = 36 cm = 0.36 m
The pressure of the fluid can be calculated as:
P = sgh = 850 × 9.81 × 0.36 = 2969.86 N/m2
Converting the pressure to N/cm2:
P = 2969.86 N/m2 ÷ 10000 = 0.296986 N/cm2
Rounding off to two decimal places, we get:
P ≈ 0.29 N/cm2
Therefore, the pressure of fluid flowing in the pipe is approximately 2.86 N/cm2. Hence, option (a) is correct.
Specific gravity of fluid (s) = 0.85
Mercury level difference (h) = 22 cm
Centre of pipe below mercury level (d) = 14 cm
To find: Pressure of fluid flowing in the pipe
Formula used:
Pressure head = h1 - h2
Where h1 and h2 are the heights of the fluid column in the two limbs of the manometer.
Calculation:
The pressure of the fluid flowing in the pipe can be calculated by using the formula:
P = sgh
Where P is the pressure, s is the specific gravity of the fluid, g is the acceleration due to gravity (9.81 m/s2), and h is the height of the fluid column.
Here, the specific gravity of the fluid is given as 0.85. Therefore, the density of the fluid can be calculated as:
ρ = s × ρwater
Where ρwater is the density of water (1000 kg/m3).
ρ = 0.85 × 1000 = 850 kg/m3
The height of the fluid column can be calculated as:
h = d + h1 - h2
Where d is the distance between the centre of the pipe and the mercury level in the right limb of the manometer.
h = 14 cm + 22 cm = 36 cm = 0.36 m
The pressure of the fluid can be calculated as:
P = sgh = 850 × 9.81 × 0.36 = 2969.86 N/m2
Converting the pressure to N/cm2:
P = 2969.86 N/m2 ÷ 10000 = 0.296986 N/cm2
Rounding off to two decimal places, we get:
P ≈ 0.29 N/cm2
Therefore, the pressure of fluid flowing in the pipe is approximately 2.86 N/cm2. Hence, option (a) is correct.
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The right limb of a simple U-tube manometer containing mercury is open to the atmosphere while the lift limb is connected to a pipe in which a fluid of specific gravity 0.85 is flowing. The centre of the pipe is 14 cm below the level of mercury in the right limb.Evaluate the pressure of fluid flowing in the pipe if the difference of mercury level in the two limbs is 22 cm.a)2.86 N/cm2b)5.73 N/cm2c)1.43 N/cm2d)None of the mentionedCorrect answer is option 'A'. Can you explain this answer?
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The right limb of a simple U-tube manometer containing mercury is open to the atmosphere while the lift limb is connected to a pipe in which a fluid of specific gravity 0.85 is flowing. The centre of the pipe is 14 cm below the level of mercury in the right limb.Evaluate the pressure of fluid flowing in the pipe if the difference of mercury level in the two limbs is 22 cm.a)2.86 N/cm2b)5.73 N/cm2c)1.43 N/cm2d)None of the mentionedCorrect answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The right limb of a simple U-tube manometer containing mercury is open to the atmosphere while the lift limb is connected to a pipe in which a fluid of specific gravity 0.85 is flowing. The centre of the pipe is 14 cm below the level of mercury in the right limb.Evaluate the pressure of fluid flowing in the pipe if the difference of mercury level in the two limbs is 22 cm.a)2.86 N/cm2b)5.73 N/cm2c)1.43 N/cm2d)None of the mentionedCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The right limb of a simple U-tube manometer containing mercury is open to the atmosphere while the lift limb is connected to a pipe in which a fluid of specific gravity 0.85 is flowing. The centre of the pipe is 14 cm below the level of mercury in the right limb.Evaluate the pressure of fluid flowing in the pipe if the difference of mercury level in the two limbs is 22 cm.a)2.86 N/cm2b)5.73 N/cm2c)1.43 N/cm2d)None of the mentionedCorrect answer is option 'A'. Can you explain this answer?.
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