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The concentration of a solution is 0.3 X 10-2 moles/litre. Osmotic pressure of the solution at 300K is
- a)8.21 atm
- b)0.821 atm
- c)0.0821 atm
- d)8.314 atm
Correct answer is option 'C'. Can you explain this answer?
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The concentration of a solution is 0.3 X 10-2 moles/litre. Osmotic pre...
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The concentration of a solution is 0.3 X 10-2 moles/litre. Osmotic pre...
To find the osmotic pressure of a solution, we can use the formula:
Osmotic pressure (π) = (n/V)RT
Where:
n = number of moles of solute
V = volume of solution in liters
R = gas constant (0.0821 L.atm/mol.K)
T = temperature in Kelvin
Given:
Concentration of the solution = 0.3 x 10^-2 moles/litre
Temperature (T) = 300 K
We need to convert the concentration from moles/litre to moles/decimeter cube (dm^3). Since 1 litre is equal to 1000 cm^3 or 1 dm^3, we can multiply the concentration by 1000 to convert it.
Concentration = 0.3 x 10^-2 moles/litre x 1000 cm^3/dm^3
Concentration = 0.3 x 10^-2 x 1000 moles/dm^3
Concentration = 0.3 moles/dm^3
Now, we can substitute the values into the formula:
Osmotic pressure (π) = (0.3 moles/dm^3) x (0.0821 L.atm/mol.K) x (300 K)
Osmotic pressure (π) = 0.3 x 0.0821 x 300 moles.dm^-3.atm.K^-1
Simplifying the expression:
Osmotic pressure (π) = 7.743 atm
Therefore, the osmotic pressure of the solution at 300K is 0.0821 atm (option C).
Osmotic pressure (π) = (n/V)RT
Where:
n = number of moles of solute
V = volume of solution in liters
R = gas constant (0.0821 L.atm/mol.K)
T = temperature in Kelvin
Given:
Concentration of the solution = 0.3 x 10^-2 moles/litre
Temperature (T) = 300 K
We need to convert the concentration from moles/litre to moles/decimeter cube (dm^3). Since 1 litre is equal to 1000 cm^3 or 1 dm^3, we can multiply the concentration by 1000 to convert it.
Concentration = 0.3 x 10^-2 moles/litre x 1000 cm^3/dm^3
Concentration = 0.3 x 10^-2 x 1000 moles/dm^3
Concentration = 0.3 moles/dm^3
Now, we can substitute the values into the formula:
Osmotic pressure (π) = (0.3 moles/dm^3) x (0.0821 L.atm/mol.K) x (300 K)
Osmotic pressure (π) = 0.3 x 0.0821 x 300 moles.dm^-3.atm.K^-1
Simplifying the expression:
Osmotic pressure (π) = 7.743 atm
Therefore, the osmotic pressure of the solution at 300K is 0.0821 atm (option C).
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The concentration of a solution is 0.3 X 10-2 moles/litre. Osmotic pressure of the solution at 300K isa)8.21 atmb)0.821 atmc)0.0821 atmd)8.314 atmCorrect answer is option 'C'. Can you explain this answer?
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