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At 298 K, given specific conductance of saturated
AgCl solution=3.41 x 10-6 Ω-1 cm-1 and that of water used =1.60 x 10-6 Ω-1 cm-1.
Equivalent conductance of saturated AgCl solution= 138.3 Ω-1 cm2 equiv-1
AgCl solution=3.41 x 10-6 Ω-1 cm-1 and that of water used =1.60 x 10-6 Ω-1 cm-1.
Equivalent conductance of saturated AgCl solution= 138.3 Ω-1 cm2 equiv-1
Thus, solubility product (KSp) of AgCl is
- a)1.81 x 10-6
- b)1.31 x 10-5
- c)1.72 x 10-10
- d)1.72 x 10-8
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
At 298 K, given specific conductance of saturatedAgCl solution=3.41 x ...
Water has also conductance, hence to obtain pure value of conductance of AgCI, conductance of water should be substracted from the conductance of AgCI given.
Pure specific conductance of AgCI = (3.41 x 10-6 - 1.60 x 10-6)
= 1.81 x 10-6Ω -1cm-1
AgCI is sparingly soluble, hence its solubility may be taken its concentration.
Also,
in saturated solution sparingly soluble salt
Also,
in saturated solution sparingly soluble salt∴
∴ AgCl (s) 
Ag+ + Cl-
∴ Ksp = [Ag+] [Cl-] = S2
= (1.31 x 10-5)2
= 1.72 x 10-10 mol2L-2
Ag+ + Cl-∴ Ksp = [Ag+] [Cl-] = S2
= (1.31 x 10-5)2
= 1.72 x 10-10 mol2L-2
Most Upvoted Answer
At 298 K, given specific conductance of saturatedAgCl solution=3.41 x ...
This question is incomplete as the units for the specific conductance of AgCl solution are missing. The answer will depend on the units of specific conductance provided.
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At 298 K, given specific conductance of saturatedAgCl solution=3.41 x 10-6Ω-1cm-1 and that of water used =1.60x 10-6Ω-1cm-1.Equivalent conductance of saturated AgCl solution= 138.3Ω-1cm2equiv-1 Thus, solubility product (KSp) of AgCl isa)1.81 x 10-6b)1.31 x 10-5c)1.72x 10-10d)1.72x 10-8Correct answer is option 'C'. Can you explain this answer?
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At 298 K, given specific conductance of saturatedAgCl solution=3.41 x 10-6Ω-1cm-1 and that of water used =1.60x 10-6Ω-1cm-1.Equivalent conductance of saturated AgCl solution= 138.3Ω-1cm2equiv-1 Thus, solubility product (KSp) of AgCl isa)1.81 x 10-6b)1.31 x 10-5c)1.72x 10-10d)1.72x 10-8Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about At 298 K, given specific conductance of saturatedAgCl solution=3.41 x 10-6Ω-1cm-1 and that of water used =1.60x 10-6Ω-1cm-1.Equivalent conductance of saturated AgCl solution= 138.3Ω-1cm2equiv-1 Thus, solubility product (KSp) of AgCl isa)1.81 x 10-6b)1.31 x 10-5c)1.72x 10-10d)1.72x 10-8Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 298 K, given specific conductance of saturatedAgCl solution=3.41 x 10-6Ω-1cm-1 and that of water used =1.60x 10-6Ω-1cm-1.Equivalent conductance of saturated AgCl solution= 138.3Ω-1cm2equiv-1 Thus, solubility product (KSp) of AgCl isa)1.81 x 10-6b)1.31 x 10-5c)1.72x 10-10d)1.72x 10-8Correct answer is option 'C'. Can you explain this answer?.
At 298 K, given specific conductance of saturatedAgCl solution=3.41 x 10-6Ω-1cm-1 and that of water used =1.60x 10-6Ω-1cm-1.Equivalent conductance of saturated AgCl solution= 138.3Ω-1cm2equiv-1 Thus, solubility product (KSp) of AgCl isa)1.81 x 10-6b)1.31 x 10-5c)1.72x 10-10d)1.72x 10-8Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about At 298 K, given specific conductance of saturatedAgCl solution=3.41 x 10-6Ω-1cm-1 and that of water used =1.60x 10-6Ω-1cm-1.Equivalent conductance of saturated AgCl solution= 138.3Ω-1cm2equiv-1 Thus, solubility product (KSp) of AgCl isa)1.81 x 10-6b)1.31 x 10-5c)1.72x 10-10d)1.72x 10-8Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 298 K, given specific conductance of saturatedAgCl solution=3.41 x 10-6Ω-1cm-1 and that of water used =1.60x 10-6Ω-1cm-1.Equivalent conductance of saturated AgCl solution= 138.3Ω-1cm2equiv-1 Thus, solubility product (KSp) of AgCl isa)1.81 x 10-6b)1.31 x 10-5c)1.72x 10-10d)1.72x 10-8Correct answer is option 'C'. Can you explain this answer?.
Solutions for At 298 K, given specific conductance of saturatedAgCl solution=3.41 x 10-6Ω-1cm-1 and that of water used =1.60x 10-6Ω-1cm-1.Equivalent conductance of saturated AgCl solution= 138.3Ω-1cm2equiv-1 Thus, solubility product (KSp) of AgCl isa)1.81 x 10-6b)1.31 x 10-5c)1.72x 10-10d)1.72x 10-8Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Here you can find the meaning of At 298 K, given specific conductance of saturatedAgCl solution=3.41 x 10-6Ω-1cm-1 and that of water used =1.60x 10-6Ω-1cm-1.Equivalent conductance of saturated AgCl solution= 138.3Ω-1cm2equiv-1 Thus, solubility product (KSp) of AgCl isa)1.81 x 10-6b)1.31 x 10-5c)1.72x 10-10d)1.72x 10-8Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
At 298 K, given specific conductance of saturatedAgCl solution=3.41 x 10-6Ω-1cm-1 and that of water used =1.60x 10-6Ω-1cm-1.Equivalent conductance of saturated AgCl solution= 138.3Ω-1cm2equiv-1 Thus, solubility product (KSp) of AgCl isa)1.81 x 10-6b)1.31 x 10-5c)1.72x 10-10d)1.72x 10-8Correct answer is option 'C'. Can you explain this answer?, a detailed solution for At 298 K, given specific conductance of saturatedAgCl solution=3.41 x 10-6Ω-1cm-1 and that of water used =1.60x 10-6Ω-1cm-1.Equivalent conductance of saturated AgCl solution= 138.3Ω-1cm2equiv-1 Thus, solubility product (KSp) of AgCl isa)1.81 x 10-6b)1.31 x 10-5c)1.72x 10-10d)1.72x 10-8Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of At 298 K, given specific conductance of saturatedAgCl solution=3.41 x 10-6Ω-1cm-1 and that of water used =1.60x 10-6Ω-1cm-1.Equivalent conductance of saturated AgCl solution= 138.3Ω-1cm2equiv-1 Thus, solubility product (KSp) of AgCl isa)1.81 x 10-6b)1.31 x 10-5c)1.72x 10-10d)1.72x 10-8Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice At 298 K, given specific conductance of saturatedAgCl solution=3.41 x 10-6Ω-1cm-1 and that of water used =1.60x 10-6Ω-1cm-1.Equivalent conductance of saturated AgCl solution= 138.3Ω-1cm2equiv-1 Thus, solubility product (KSp) of AgCl isa)1.81 x 10-6b)1.31 x 10-5c)1.72x 10-10d)1.72x 10-8Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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