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Let S = {θ ∈ [ -2π, 2π] : 2 cos2 θ + 3sin θ = 0} . Then the sum of the elements of S is: 
  • a)
  • b)
  • c)
  • d)
    π
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Let S = {θ ∈[ -2π, 2π] : 2 cos2 θ + 3sin &theta...
solving the trigonometric equation, we get sin θ 
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Let S = {θ ∈[ -2π, 2π] : 2 cos2 θ + 3sin θ = 0} . Then the sum of the elements of S is:a)b)2πc)d)πCorrect answer is option 'B'. Can you explain this answer?
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Let S = {θ ∈[ -2π, 2π] : 2 cos2 θ + 3sin θ = 0} . Then the sum of the elements of S is:a)b)2πc)d)πCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let S = {θ ∈[ -2π, 2π] : 2 cos2 θ + 3sin θ = 0} . Then the sum of the elements of S is:a)b)2πc)d)πCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let S = {θ ∈[ -2π, 2π] : 2 cos2 θ + 3sin θ = 0} . Then the sum of the elements of S is:a)b)2πc)d)πCorrect answer is option 'B'. Can you explain this answer?.
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