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A queue is implemented using an array such that ENQUEUE and DEQUEUE operations are performed efficiently. Which one of the following statements is CORRECT ( n refers to the number of items in the queue)?
- a)Both operations can be performed in O(1) time.
- b)At most one operation can be performed in O(1) time but the worst case time for the operation will be Ω(n).
- c)The worst case time complexity for both operations will be Ω(n).
- d)Worst case time complexity for both operations will be Ω(logn)
Correct answer is option 'A'. Can you explain this answer?
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A queue is implemented using an array such that ENQUEUE and DEQUEUE op...
Answer A - Circular Queue Implementation
Both operations can be performed in O(1) time in Circular Queue implimentation where Enqueue and Dequeue operation are done at last node. Single pointer needed at last node.
Most Upvoted Answer
A queue is implemented using an array such that ENQUEUE and DEQUEUE op...
Explanation:
To implement a queue efficiently using an array, we can use a circular array. In a circular array, the elements are stored in a circular manner, i.e., if the end of the array is reached, the next element is stored at the beginning of the array.
ENQUEUE Operation:
To perform the enqueue operation efficiently, we need to insert an element at the end of the queue. In a circular array, this can be done by simply incrementing the end index and inserting the element at that index. If the end index reaches the end of the array, it wraps around to the beginning of the array.
DEQUEUE Operation:
To perform the dequeue operation efficiently, we need to remove the element at the front of the queue. In a circular array, this can be done by simply incrementing the front index and removing the element at that index. If the front index reaches the end of the array, it wraps around to the beginning of the array.
Time Complexity:
In the implementation described above, both enqueue and dequeue operations can be performed in O(1) time.
- Enqueue operation: O(1) time as we are simply incrementing the end index and inserting the element at that index.
- Dequeue operation: O(1) time as we are simply incrementing the front index and removing the element at that index.
Conclusion:
Hence, the correct answer is option A. Both enqueue and dequeue operations can be performed efficiently in O(1) time.
To implement a queue efficiently using an array, we can use a circular array. In a circular array, the elements are stored in a circular manner, i.e., if the end of the array is reached, the next element is stored at the beginning of the array.
ENQUEUE Operation:
To perform the enqueue operation efficiently, we need to insert an element at the end of the queue. In a circular array, this can be done by simply incrementing the end index and inserting the element at that index. If the end index reaches the end of the array, it wraps around to the beginning of the array.
DEQUEUE Operation:
To perform the dequeue operation efficiently, we need to remove the element at the front of the queue. In a circular array, this can be done by simply incrementing the front index and removing the element at that index. If the front index reaches the end of the array, it wraps around to the beginning of the array.
Time Complexity:
In the implementation described above, both enqueue and dequeue operations can be performed in O(1) time.
- Enqueue operation: O(1) time as we are simply incrementing the end index and inserting the element at that index.
- Dequeue operation: O(1) time as we are simply incrementing the front index and removing the element at that index.
Conclusion:
Hence, the correct answer is option A. Both enqueue and dequeue operations can be performed efficiently in O(1) time.
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A queue is implemented using an array such that ENQUEUE and DEQUEUE operations are performed efficiently. Which one of the following statements is CORRECT ( nrefers to the number of items in the queue)?a)Both operations can be performed in O(1) time.b)At most one operation can be performed in O(1)time but the worst case time for the operation will beΩ(n).c)The worst case time complexity for both operations will be Ω(n).d)Worst case time complexity for both operations will beΩ(logn)Correct answer is option 'A'. Can you explain this answer?
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