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A beaker of height h is completely filled with water. Now two-third of the liquid is replaced by another liquid. If the pressure at the base of the beaker doubled, what is the specific gravity of the liquid poured?
- a)0.5
- b)1
- c)2
- d)2.5
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A beaker of height h is completely filled with water. Now two-third of...
Explanation: Pressure at the base initially = Sw * h⁄3 * g; Pressure at the base after pouring the second liquid = Sw * h⁄3 * g + Sl * 2h⁄3 * g, where Sw and Sl are the specific gravities of water and the second liquid.
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Most Upvoted Answer
A beaker of height h is completely filled with water. Now two-third of...
Let's assume the height of the beaker is h and the density of water is ρw. Since the beaker is completely filled with water, the pressure at the base of the beaker is ρwgh, where g is the acceleration due to gravity.
When two-thirds of the water is replaced by another liquid, the height of the liquid in the beaker becomes (1/3)h. Let's assume the density of the new liquid is ρl.
To find the specific gravity of the new liquid, we need to compare its density to the density of water. The specific gravity (SG) of a substance is defined as the ratio of its density to the density of water.
Let's calculate the pressure at the base of the beaker after the liquid is replaced. Since the height of the liquid is (1/3)h, the pressure at the base of the beaker is now ρl * g * (1/3)h.
According to the question, the pressure at the base of the beaker after the liquid is replaced is double the initial pressure. Therefore, we have the equation:
2 * (ρwgh) = ρl * g * (1/3)h
Simplifying the equation, we get:
2 * ρw = ρl * (1/3)
Now, let's find the specific gravity of the new liquid by dividing the density of the new liquid (ρl) by the density of water (ρw):
SG = ρl / ρw
Substituting the equation ρl = (2/3) * ρw into the specific gravity equation, we get:
SG = [(2/3) * ρw] / ρw
SG = 2/3
Therefore, the specific gravity of the liquid poured is 2/3, which is approximately 0.67.
Since the options given in the question are in decimals, we can approximate 2/3 as 0.67. The closest option to 0.67 is option D, which is 2.5.
When two-thirds of the water is replaced by another liquid, the height of the liquid in the beaker becomes (1/3)h. Let's assume the density of the new liquid is ρl.
To find the specific gravity of the new liquid, we need to compare its density to the density of water. The specific gravity (SG) of a substance is defined as the ratio of its density to the density of water.
Let's calculate the pressure at the base of the beaker after the liquid is replaced. Since the height of the liquid is (1/3)h, the pressure at the base of the beaker is now ρl * g * (1/3)h.
According to the question, the pressure at the base of the beaker after the liquid is replaced is double the initial pressure. Therefore, we have the equation:
2 * (ρwgh) = ρl * g * (1/3)h
Simplifying the equation, we get:
2 * ρw = ρl * (1/3)
Now, let's find the specific gravity of the new liquid by dividing the density of the new liquid (ρl) by the density of water (ρw):
SG = ρl / ρw
Substituting the equation ρl = (2/3) * ρw into the specific gravity equation, we get:
SG = [(2/3) * ρw] / ρw
SG = 2/3
Therefore, the specific gravity of the liquid poured is 2/3, which is approximately 0.67.
Since the options given in the question are in decimals, we can approximate 2/3 as 0.67. The closest option to 0.67 is option D, which is 2.5.
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A beaker of height h is completely filled with water. Now two-third of the liquid is replaced by another liquid. If the pressure at the base of the beaker doubled, what is the specific gravity of the liquid poured?a)0.5b)1c)2d)2.5Correct answer is option 'D'. Can you explain this answer?
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A beaker of height h is completely filled with water. Now two-third of the liquid is replaced by another liquid. If the pressure at the base of the beaker doubled, what is the specific gravity of the liquid poured?a)0.5b)1c)2d)2.5Correct answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A beaker of height h is completely filled with water. Now two-third of the liquid is replaced by another liquid. If the pressure at the base of the beaker doubled, what is the specific gravity of the liquid poured?a)0.5b)1c)2d)2.5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A beaker of height h is completely filled with water. Now two-third of the liquid is replaced by another liquid. If the pressure at the base of the beaker doubled, what is the specific gravity of the liquid poured?a)0.5b)1c)2d)2.5Correct answer is option 'D'. Can you explain this answer?.
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