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 A beaker is filled with a liquid of density ρ up to a height h. If half the liquid is replaced by equal volume of another liquid of twice the density, what will be the change in the base pressure?
  • a)
    increased by ρgh
  • b)
    decreased by ρgh
  • c)
    increased by ρgh=2
  • d)
    decreased by ρgh=2
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A beaker is filled with a liquid of density ρ up to a height h. If...
Explanation: Base pressure when the beaker is filled with a liquid of density ρ up to a height h = ρgh
Base pressure when half the liquid is replaced by equal volume of another liquid of twice the density
= ρg h2 + 2ρg h2 = 32 ρgh
Thus the change in base pressure is = ρgh / 2. Since, P2 > P1, there will be an increase in pressure.
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A beaker is filled with a liquid of density ρ up to a height h. If half the liquid is replaced by equal volume of another liquid of twice the density, what will be the change in the base pressure? a)increased by ρghb)decreased by ρghc)increased by ρgh=2d)decreased by ρgh=2Correct answer is option 'C'. Can you explain this answer?
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