Tank A contains 6 times as much water as Tank B. How much water must M...
To solve this problem, we need to set up an equation based on the information given in the problem.
Let's assume that the amount of water in Tank B is x litres.
According to the problem, Tank A contains 6 times as much water as Tank B, so the amount of water in Tank A is 6x litres.
We need to transfer some water from Tank A to Tank B so that each tank contains 70 litres of water.
Let's say we transfer y litres of water from Tank A to Tank B.
After the transfer, the amount of water in Tank A will be 6x - y litres, and the amount of water in Tank B will be x + y litres.
Since each tank should contain 70 litres of water, we can set up the following equation:
6x - y = 70 (equation 1)
x + y = 70 (equation 2)
We can solve this system of equations using the method of substitution or elimination.
Let's solve it using the method of elimination:
Adding equation 1 and equation 2, we get:
6x - y + x + y = 70 + 70
7x = 140
x = 20
Now that we know the value of x, we can substitute it back into equation 2 to find the value of y:
20 + y = 70
y = 70 - 20
y = 50
Therefore, Mohan needs to transfer 50 litres of water from Tank A to Tank B so that each tank contains 70 litres of water.
Hence, the correct answer is option A) 50 litres.