A 5-stage pipelined processor has Instruction Fetch (IF), Instruction Decode (ID), Opearnd Fetch (OF), Perform Operation (PO) and Write Operand (WO) stages. The IF, ID, OF and WO stages take 1 clock cycle each for any instruction. The PO stage takes 1 clock cycle for ADD and SUB instructions, 3 clock cycles for MUL instruction and 6 clock cycles for DIV instruction respectively. Operand forwarding is used in the pipeline. What is the number of clock cycles needed to execute the following sequence of instructions?Instruction Meaning of instructiont0 : MUL R2,R0,R1R2 R0 R1t1 : DIV R5,R3,R4 R5 R3/R4t2 : ADD R2,R5,R2R2 R5 + R2t3 : SUB R5,R2,R6 R 5 R2 R6a)13b)15c)17d)19Correct answer is option 'B'. Can you explain this answer? - EduRev Computer Science Engineering (CSE) Question

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Instruction Meaning of instruction

t₀ : MUL R₂,R₀,R₁R₂ ← R₀ ∗ R₁
t₁ : DIV R₅,R₃,R₄ R₅ ← R₃/R₄
t₂ : ADD R₂,R₅,R₂R₂ ← R₅ + R₂
t₃ : SUB R₅,R₂,R₆ R ← − 5 R₂R₆

a)
13
b)
15
c)
17
d)
19

Correct answer is option 'B'. Can you explain this answer?

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A 5-stage pipelined processor has Instruction Fetch (IF), Instruction ...

Operand forwarding allows an output to be passed for the next instruction. Here from the output of PO stage of DIV instruction operand is forwarded to the PO stage of ADD instruction and similarly between ADD and SUB instructions.
Hence, 15 cycles required.

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A 5-stage pipelined processor has Instruction Fetch (IF), Instruction ...

Given Information:
- A 5-stage pipelined processor with the stages: Instruction Fetch (IF), Instruction Decode (ID), Operand Fetch (OF), Perform Operation (PO), and Write Operand (WO).
- Each stage takes 1 clock cycle for any instruction, except for the PO stage.
- The PO stage takes 1 clock cycle for ADD and SUB instructions, 3 clock cycles for MUL instructions, and 6 clock cycles for DIV instructions.
- Operand forwarding is used in the pipeline.

Sequence of Instructions:
t0: MUL R2, R0, R1
t1: DIV R5, R3, R4
t2: ADD R2, R5, R2
t3: SUB R5, R2, R6

Step 1: Determine the Total Number of Stages:
The pipeline has 5 stages, so we have a total of 5 clock cycles.

Step 2: Determine the Number of Cycles for Each Instruction:
- MUL instruction:
- IF: 1 cycle
- ID: 1 cycle
- OF: 1 cycle
- PO: 3 cycles
- WO: 1 cycle
Total cycles for MUL instruction: 7 cycles

- DIV instruction:
- IF: 1 cycle
- ID: 1 cycle
- OF: 1 cycle
- PO: 6 cycles
- WO: 1 cycle
Total cycles for DIV instruction: 10 cycles

- ADD instruction:
- IF: 1 cycle
- ID: 1 cycle
- OF: 1 cycle
- PO: 1 cycle
- WO: 1 cycle
Total cycles for ADD instruction: 5 cycles

- SUB instruction:
- IF: 1 cycle
- ID: 1 cycle
- OF: 1 cycle
- PO: 1 cycle
- WO: 1 cycle
Total cycles for SUB instruction: 5 cycles

Step 3: Calculate the Total Number of Clock Cycles:
t0: MUL instruction requires 7 cycles
t1: DIV instruction requires 10 cycles
t2: ADD instruction requires 5 cycles
t3: SUB instruction requires 5 cycles

Total clock cycles = 7 + 10 + 5 + 5 = 27

Step 4: Consider Operand Forwarding:
Operand forwarding reduces the number of cycles required for dependent instructions. In this case, the ADD instruction depends on the result of the DIV instruction, and the SUB instruction depends on the result of the ADD instruction.

With operand forwarding, the ADD instruction can start in the same clock cycle as the DIV instruction completes, and the SUB instruction can start in the same clock cycle as the ADD instruction completes. Therefore, the total number of clock cycles required is reduced.

- MUL instruction: 7 cycles
- DIV instruction: 10 cycles (no change)
- ADD instruction: 4 cycles
- SUB instruction: 4 cycles

Total clock cycles = 7 + 10 + 4 + 4 = 25

Step 5: Final Answer:
The number of clock cycles needed to execute

Answered by Gate Gurus · View profile

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A 5-stage pipelined processor has Instruction Fetch (IF), Instruction Decode (ID), Operand Fetch (OF), Perform Operation (PO) and Write Operand (WO) stages. The IF, ID, OF and WO stages take 1 clock cycle each for any instruction. The PO stage takes 1 clock cycle for ADD and SUB instructions, 3 clock cycles for MUL instruction, and 6 clock cycles for DIV instruction respectively. Operand forwarding is used in the pipeline. What is the number of clock cycles needed to execute the following sequence of instructions?

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A 5-stage pipelined processor has Instruction Fetch (IF), Instruction Decode (ID), Opearnd Fetch (OF), Perform Operation (PO) and Write Operand (WO) stages. The IF, ID, OF and WO stages take 1 clock cycle each for any instruction. The PO stage takes 1 clock cycle for ADD and SUB instructions, 3 clock cycles for MUL instruction and 6 clock cycles for DIV instruction respectively. Operand forwarding is used in the pipeline. What is the number of clock cycles needed to execute the following sequence of instructions?Instruction Meaning of instructiont0 : MUL R2,R0,R1R2 ← R0 ∗ R1t1 : DIV R5,R3,R4 R5 ← R3/R4t2 : ADD R2,R5,R2R2 ← R5 + R2t3 : SUB R5,R2,R6 R ← − 5 R2 R6a)13b)15c)17d)19Correct answer is option 'B'. Can you explain this answer?

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A 5-stage pipelined processor has Instruction Fetch (IF), Instruction Decode (ID), Opearnd Fetch (OF), Perform Operation (PO) and Write Operand (WO) stages. The IF, ID, OF and WO stages take 1 clock cycle each for any instruction. The PO stage takes 1 clock cycle for ADD and SUB instructions, 3 clock cycles for MUL instruction and 6 clock cycles for DIV instruction respectively. Operand forwarding is used in the pipeline. What is the number of clock cycles needed to execute the following sequence of instructions?Instruction Meaning of instructiont0 : MUL R2,R0,R1R2 ← R0 ∗ R1t1 : DIV R5,R3,R4 R5 ← R3/R4t2 : ADD R2,R5,R2R2 ← R5 + R2t3 : SUB R5,R2,R6 R ← − 5 R2 R6a)13b)15c)17d)19Correct answer is option 'B'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A 5-stage pipelined processor has Instruction Fetch (IF), Instruction Decode (ID), Opearnd Fetch (OF), Perform Operation (PO) and Write Operand (WO) stages. The IF, ID, OF and WO stages take 1 clock cycle each for any instruction. The PO stage takes 1 clock cycle for ADD and SUB instructions, 3 clock cycles for MUL instruction and 6 clock cycles for DIV instruction respectively. Operand forwarding is used in the pipeline. What is the number of clock cycles needed to execute the following sequence of instructions?Instruction Meaning of instructiont0 : MUL R2,R0,R1R2 ← R0 ∗ R1t1 : DIV R5,R3,R4 R5 ← R3/R4t2 : ADD R2,R5,R2R2 ← R5 + R2t3 : SUB R5,R2,R6 R ← − 5 R2 R6a)13b)15c)17d)19Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5-stage pipelined processor has Instruction Fetch (IF), Instruction Decode (ID), Opearnd Fetch (OF), Perform Operation (PO) and Write Operand (WO) stages. The IF, ID, OF and WO stages take 1 clock cycle each for any instruction. The PO stage takes 1 clock cycle for ADD and SUB instructions, 3 clock cycles for MUL instruction and 6 clock cycles for DIV instruction respectively. Operand forwarding is used in the pipeline. What is the number of clock cycles needed to execute the following sequence of instructions?Instruction Meaning of instructiont0 : MUL R2,R0,R1R2 ← R0 ∗ R1t1 : DIV R5,R3,R4 R5 ← R3/R4t2 : ADD R2,R5,R2R2 ← R5 + R2t3 : SUB R5,R2,R6 R ← − 5 R2 R6a)13b)15c)17d)19Correct answer is option 'B'. Can you explain this answer?.

Solutions for A 5-stage pipelined processor has Instruction Fetch (IF), Instruction Decode (ID), Opearnd Fetch (OF), Perform Operation (PO) and Write Operand (WO) stages. The IF, ID, OF and WO stages take 1 clock cycle each for any instruction. The PO stage takes 1 clock cycle for ADD and SUB instructions, 3 clock cycles for MUL instruction and 6 clock cycles for DIV instruction respectively. Operand forwarding is used in the pipeline. What is the number of clock cycles needed to execute the following sequence of instructions?Instruction Meaning of instructiont0 : MUL R2,R0,R1R2 ← R0 ∗ R1t1 : DIV R5,R3,R4 R5 ← R3/R4t2 : ADD R2,R5,R2R2 ← R5 + R2t3 : SUB R5,R2,R6 R ← − 5 R2 R6a)13b)15c)17d)19Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE). Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.

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