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A flocculation tank contains 1800 m3 of water, which is mixed using paddles at an average velocity gradient G of 100/s. The water temperature and the corresponding dynamic viscosity are 30oC and 0.798 × 10–3 Ns/m2, respectively. The theoretical power required to achieve the stated value of G (in kW, up to two decimal places) is ___________.
    Correct answer is '(14.36)'. Can you explain this answer?
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    Calculation of Theoretical Power Required for Flocculation Tank

    Given Data:
    - Volume of water in flocculation tank (V): 1800 m3
    - Average velocity gradient (G): 100/s
    - Water temperature: 30°C
    - Dynamic viscosity of water (μ): 0.798 × 10^–3 Ns/m2

    Formula Used:
    Theoretical Power (P) = V * μ * G^2

    Calculation:
    - Convert water temperature to Kelvin: T = 30 + 273 = 303 K
    - Calculate kinematic viscosity (ν) using dynamic viscosity: ν = μ / ρ, where ρ is the density of water at 30°C
    - Calculate density of water at 30°C using the formula: ρ = 1000 / (1 + β * (T - Tref)), where β is the coefficient of volume expansion (2.1 × 10^-4 / °C) and Tref is the reference temperature (4°C)
    - Substitute the values of ρ, ν, V, G, and μ into the formula to find the Theoretical Power

    Calculation Steps:
    1. Calculate ρ using the given formula.
    2. Calculate ν using the formula: ν = μ / ρ.
    3. Substitute the values of ρ, V, G, and ν into the formula: P = V * ν * G^2.
    4. Calculate the Theoretical Power P in kW.

    Therefore, the Theoretical Power required to achieve the stated value of G is 14.36 kW.
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    A flocculation tank contains 1800 m3 of water, which is mixed using paddles at an average velocity gradient G of 100/s. The water temperature and the corresponding dynamic viscosity are 30oC and0.798 × 10–3 Ns/m2,respectively. The theoretical power required to achieve the stated value of G (in kW, up to two decimal places) is ___________.Correct answer is '(14.36)'. Can you explain this answer?
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    A flocculation tank contains 1800 m3 of water, which is mixed using paddles at an average velocity gradient G of 100/s. The water temperature and the corresponding dynamic viscosity are 30oC and0.798 × 10–3 Ns/m2,respectively. The theoretical power required to achieve the stated value of G (in kW, up to two decimal places) is ___________.Correct answer is '(14.36)'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A flocculation tank contains 1800 m3 of water, which is mixed using paddles at an average velocity gradient G of 100/s. The water temperature and the corresponding dynamic viscosity are 30oC and0.798 × 10–3 Ns/m2,respectively. The theoretical power required to achieve the stated value of G (in kW, up to two decimal places) is ___________.Correct answer is '(14.36)'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A flocculation tank contains 1800 m3 of water, which is mixed using paddles at an average velocity gradient G of 100/s. The water temperature and the corresponding dynamic viscosity are 30oC and0.798 × 10–3 Ns/m2,respectively. The theoretical power required to achieve the stated value of G (in kW, up to two decimal places) is ___________.Correct answer is '(14.36)'. Can you explain this answer?.
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