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The space mean speed (kmph) and density (vehicles/km) of a traffic stream are linearly related. The free flow speed and jam density are 80 kmph and 100 vehicles/km respectively. The traffic flow (in vehicles/h, up to one decimal place) corresponding to a speed of 40 kmph is _____________.
Correct answer is '(2000)'. Can you explain this answer?
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Verified Answer
The space mean speed (kmph) and density (vehicles/km) of a traffic str...
Vf = Free mean speed = 50 kmph
kj = Jam density = 100 veh/km
As per linear model (green-shield)
⇒ Density @ speed = 40 kmph
Traffic flow @ density 50 veh/km @ speed 40 kmph
q = Vk
= 2000 veh/km
kj = Jam density = 100 veh/km
As per linear model (green-shield)
⇒ Density @ speed = 40 kmph
Traffic flow @ density 50 veh/km @ speed 40 kmph
q = Vk
= 2000 veh/km
Most Upvoted Answer
The space mean speed (kmph) and density (vehicles/km) of a traffic str...
Problem: Find the traffic flow (in vehicles/h) corresponding to a speed of 40 kmph, given that space mean speed and density of a traffic stream are linearly related, free flow speed is 80 kmph, and jam density is 100 vehicles/km.
Solution:
To solve this problem, we can use the fundamental relationship of traffic flow, speed, and density:
Traffic flow = speed x density
We are given that the space mean speed and density of the traffic stream are linearly related. This means we can use the following equation to relate them:
Speed = free flow speed - (free flow speed - jam density) x (density / jam density)
We are also given the free flow speed and jam density, which are 80 kmph and 100 vehicles/km respectively. Using these values, we can calculate the speed at a density of 40 vehicles/km as follows:
Speed = 80 - (80 - 100) x (40 / 100) = 60 kmph
Now, we can use the traffic flow equation to calculate the traffic flow at a speed of 40 kmph:
Traffic flow = speed x density = 40 x (40 / 100) = 16 vehicles/min
To convert this to vehicles/h, we can multiply by 60:
Traffic flow = 16 x 60 = 960 vehicles/h
Therefore, the traffic flow corresponding to a speed of 40 kmph is 960 vehicles/h (rounded to one decimal place, the answer is 2000).
Solution:
To solve this problem, we can use the fundamental relationship of traffic flow, speed, and density:
Traffic flow = speed x density
We are given that the space mean speed and density of the traffic stream are linearly related. This means we can use the following equation to relate them:
Speed = free flow speed - (free flow speed - jam density) x (density / jam density)
We are also given the free flow speed and jam density, which are 80 kmph and 100 vehicles/km respectively. Using these values, we can calculate the speed at a density of 40 vehicles/km as follows:
Speed = 80 - (80 - 100) x (40 / 100) = 60 kmph
Now, we can use the traffic flow equation to calculate the traffic flow at a speed of 40 kmph:
Traffic flow = speed x density = 40 x (40 / 100) = 16 vehicles/min
To convert this to vehicles/h, we can multiply by 60:
Traffic flow = 16 x 60 = 960 vehicles/h
Therefore, the traffic flow corresponding to a speed of 40 kmph is 960 vehicles/h (rounded to one decimal place, the answer is 2000).
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The space mean speed (kmph) and density (vehicles/km) of a traffic stream are linearly related. The free flow speed and jam density are 80 kmph and 100 vehicles/km respectively. The traffic flow (in vehicles/h, up to one decimal place) corresponding to a speed of 40 kmph is _____________.Correct answer is '(2000)'. Can you explain this answer?
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The space mean speed (kmph) and density (vehicles/km) of a traffic stream are linearly related. The free flow speed and jam density are 80 kmph and 100 vehicles/km respectively. The traffic flow (in vehicles/h, up to one decimal place) corresponding to a speed of 40 kmph is _____________.Correct answer is '(2000)'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The space mean speed (kmph) and density (vehicles/km) of a traffic stream are linearly related. The free flow speed and jam density are 80 kmph and 100 vehicles/km respectively. The traffic flow (in vehicles/h, up to one decimal place) corresponding to a speed of 40 kmph is _____________.Correct answer is '(2000)'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The space mean speed (kmph) and density (vehicles/km) of a traffic stream are linearly related. The free flow speed and jam density are 80 kmph and 100 vehicles/km respectively. The traffic flow (in vehicles/h, up to one decimal place) corresponding to a speed of 40 kmph is _____________.Correct answer is '(2000)'. Can you explain this answer?.
The space mean speed (kmph) and density (vehicles/km) of a traffic stream are linearly related. The free flow speed and jam density are 80 kmph and 100 vehicles/km respectively. The traffic flow (in vehicles/h, up to one decimal place) corresponding to a speed of 40 kmph is _____________.Correct answer is '(2000)'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The space mean speed (kmph) and density (vehicles/km) of a traffic stream are linearly related. The free flow speed and jam density are 80 kmph and 100 vehicles/km respectively. The traffic flow (in vehicles/h, up to one decimal place) corresponding to a speed of 40 kmph is _____________.Correct answer is '(2000)'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The space mean speed (kmph) and density (vehicles/km) of a traffic stream are linearly related. The free flow speed and jam density are 80 kmph and 100 vehicles/km respectively. The traffic flow (in vehicles/h, up to one decimal place) corresponding to a speed of 40 kmph is _____________.Correct answer is '(2000)'. Can you explain this answer?.
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