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Consider the concurrent processes P1, P2 and P3 as shown below, which access a shared variable D that has been initialization to 100.

The processes are executed on a uniprocessor system running a time-shared operating system. If the minimum and maximum possible values of D after the three processes have completed execution are X and Y respectively, then the value of Y–X is _________.
    Correct answer is '80'. Can you explain this answer?
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    Consider the concurrent processes P1, P2 and P3 as shown below, which ...
    For maximum value:
    First P2 & P1 read the D value as 100.
    So, P2 update it first 
    ⇒ D = D - 50 = 100 - 50 = 50
    After P2, P1 overwrite the value 50 by 120
    ⇒ D = D + 20 =100 + 20 =120
    Then P3 read the value of D as 120 and adds 10 to it
    ⇒ D = 120 + 10 = 130
    ∴ The max value of D after all 3 processes are executed is 130(Y).
    For minimum Value:
    All processes read the D value as 100.
    But, ensure that last update is from P2.
    So that, the min value of D after all 3 processes are executed is 50 (X).
    ∴ Difference between X and Y is ( Y - X) = 130 - 50 = 80
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    Consider the concurrent processes P1, P2 and P3 as shown below, which access a shared variable D that has been initialization to 100.The processes are executed on a uniprocessor system running a time-shared operating system. If the minimum and maximum possible values of D after the three processes have completed execution are X and Y respectively, then the value of Y–X is _________.Correct answer is '80'. Can you explain this answer?
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