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The velocity field in a flow system is given by v = 2i + (x + y)j + (xyz)k. The acceleration of the fluid at (1, 1, 2) is
  • a)
    j + k
  • b)
    2i + 10 k
  • c)
    4j + 10k
  • d)
    4i + 12 k
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The velocity field in a flow system is given by v = 2i + (x + y)j + (x...




= 2 + (x + y) + (xyz)(0) + 0


= 2(yz) + (x + y)(xz) + (xyz)(xy) + 0
az = 2(1 × 2) + (1 + 1)(1 × 2) + (1 × 1 × 2) (1×1)
= 10k
Therefore, 
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Most Upvoted Answer
The velocity field in a flow system is given by v = 2i + (x + y)j + (x...
Given, velocity field, v = 2i(x y)j(xyz)k
The acceleration of the fluid can be found by taking the derivative of the velocity field with respect to time, t.

Acceleration, a = dv/dt

Since the velocity field is not a function of time, the acceleration can be found by taking the derivative of the velocity field with respect to position, x, y, and z.

Acceleration, a = (d/dt)[2i(x y)j(xyz)k]
= 2[(yj + xy∂j/∂x) + (xj + y∂j/∂y) + (yzk + xyz∂k/∂z)]

At (1, 1, 2),
a = 2[(j + ∂j/∂x) + (i + ∂j/∂y) + (2zk + 2∂k/∂z)]
= 2[j - k + 4k]
= 4j + 10k

Therefore, the correct option is (c) 4j + 10k.
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The velocity field in a flow system is given by v = 2i + (x + y)j + (xyz)k. The acceleration of the fluid at (1, 1, 2) isa)j + kb)2i + 10 kc)4j + 10kd)4i + 12 kCorrect answer is option 'C'. Can you explain this answer?
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