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Jatin goes to a place at a speed of 5 km/hr and return home at speed of 10 km/hr. What is his average speed (in km/hr)?
- a)6.5
- b)6.8
- c)6.67
- d)8
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Jatin goes to a place at a speed of 5 km/hr and return home at speed o...
Let the distance be d
Time taken to go: d/5
Time taken to return: d/10
Total distance travelled: d + d = 2d
Total time taken: d/5 + d/10 = 3d/10
Time taken to go: d/5
Time taken to return: d/10
Total distance travelled: d + d = 2d
Total time taken: d/5 + d/10 = 3d/10
Average speed = total distance/total time = 2d/(3d/10) = 20/3 = 6.66667 ~ 6.67 Km/hr
Most Upvoted Answer
Jatin goes to a place at a speed of 5 km/hr and return home at speed o...
Problem:
Jatin goes to a place at a speed of 5 km/hr and returns home at a speed of 10 km/hr. What is his average speed (in km/hr)?
Solution:
To find the average speed, we need to calculate the total distance traveled and the total time taken.
Let's assume the distance between Jatin's home and the place he visits is D km.
Distance Calculation:
Jatin travels to the place at a speed of 5 km/hr, so the time taken to reach the place is D/5 hours.
On his return journey, he travels at a speed of 10 km/hr, so the time taken to return home is D/10 hours.
The total distance traveled is the sum of the distances covered in the forward and return journeys, which is 2D km.
Time Calculation:
The total time taken is the sum of the time taken for the forward and return journeys, which is D/5 + D/10 hours.
Average Speed Calculation:
Average speed is given by the formula:
Average Speed = Total Distance / Total Time
Substituting the values, we get:
Average Speed = (2D) / (D/5 + D/10)
Simplifying the expression, we get:
Average Speed = 2D / ((2D + D)/10)
Average Speed = 2D / (3D/10)
Average Speed = (2D * 10) / (3D)
Average Speed = 20D / 3D
Average Speed = 20 / 3 km/hr
So, Jatin's average speed is 6.67 km/hr.
Therefore, the correct answer is option 'C' - 6.67 km/hr.
Jatin goes to a place at a speed of 5 km/hr and returns home at a speed of 10 km/hr. What is his average speed (in km/hr)?
Solution:
To find the average speed, we need to calculate the total distance traveled and the total time taken.
Let's assume the distance between Jatin's home and the place he visits is D km.
Distance Calculation:
Jatin travels to the place at a speed of 5 km/hr, so the time taken to reach the place is D/5 hours.
On his return journey, he travels at a speed of 10 km/hr, so the time taken to return home is D/10 hours.
The total distance traveled is the sum of the distances covered in the forward and return journeys, which is 2D km.
Time Calculation:
The total time taken is the sum of the time taken for the forward and return journeys, which is D/5 + D/10 hours.
Average Speed Calculation:
Average speed is given by the formula:
Average Speed = Total Distance / Total Time
Substituting the values, we get:
Average Speed = (2D) / (D/5 + D/10)
Simplifying the expression, we get:
Average Speed = 2D / ((2D + D)/10)
Average Speed = 2D / (3D/10)
Average Speed = (2D * 10) / (3D)
Average Speed = 20D / 3D
Average Speed = 20 / 3 km/hr
So, Jatin's average speed is 6.67 km/hr.
Therefore, the correct answer is option 'C' - 6.67 km/hr.
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