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Jatin goes to a place at a speed of 5 km/hr and return home at speed of 10 km/hr. What is his average speed (in km/hr)?
- a)6.5
- b)6.8
- c)6.67
- d)8
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Jatin goes to a place at a speed of 5 km/hr and return home at speed o...
Let the distance be d
Time taken to go: d/5
Time taken to return: d/10
Total distance travelled: d + d = 2d
Total time taken: d/5 + d/10 = 3d/10
Time taken to go: d/5
Time taken to return: d/10
Total distance travelled: d + d = 2d
Total time taken: d/5 + d/10 = 3d/10
Average speed = total distance/total time = 2d/(3d/10) = 20/3 = 6.66667 ~ 6.67 Km/hr
Most Upvoted Answer
Jatin goes to a place at a speed of 5 km/hr and return home at speed o...
Problem:
Jatin goes to a place at a speed of 5 km/hr and returns home at a speed of 10 km/hr. What is his average speed (in km/hr)?
Solution:
To find the average speed, we need to calculate the total distance traveled and the total time taken.
Let's assume the distance between Jatin's home and the place he visits is D km.
Distance Calculation:
Jatin travels to the place at a speed of 5 km/hr, so the time taken to reach the place is D/5 hours.
On his return journey, he travels at a speed of 10 km/hr, so the time taken to return home is D/10 hours.
The total distance traveled is the sum of the distances covered in the forward and return journeys, which is 2D km.
Time Calculation:
The total time taken is the sum of the time taken for the forward and return journeys, which is D/5 + D/10 hours.
Average Speed Calculation:
Average speed is given by the formula:
Average Speed = Total Distance / Total Time
Substituting the values, we get:
Average Speed = (2D) / (D/5 + D/10)
Simplifying the expression, we get:
Average Speed = 2D / ((2D + D)/10)
Average Speed = 2D / (3D/10)
Average Speed = (2D * 10) / (3D)
Average Speed = 20D / 3D
Average Speed = 20 / 3 km/hr
So, Jatin's average speed is 6.67 km/hr.
Therefore, the correct answer is option 'C' - 6.67 km/hr.
Jatin goes to a place at a speed of 5 km/hr and returns home at a speed of 10 km/hr. What is his average speed (in km/hr)?
Solution:
To find the average speed, we need to calculate the total distance traveled and the total time taken.
Let's assume the distance between Jatin's home and the place he visits is D km.
Distance Calculation:
Jatin travels to the place at a speed of 5 km/hr, so the time taken to reach the place is D/5 hours.
On his return journey, he travels at a speed of 10 km/hr, so the time taken to return home is D/10 hours.
The total distance traveled is the sum of the distances covered in the forward and return journeys, which is 2D km.
Time Calculation:
The total time taken is the sum of the time taken for the forward and return journeys, which is D/5 + D/10 hours.
Average Speed Calculation:
Average speed is given by the formula:
Average Speed = Total Distance / Total Time
Substituting the values, we get:
Average Speed = (2D) / (D/5 + D/10)
Simplifying the expression, we get:
Average Speed = 2D / ((2D + D)/10)
Average Speed = 2D / (3D/10)
Average Speed = (2D * 10) / (3D)
Average Speed = 20D / 3D
Average Speed = 20 / 3 km/hr
So, Jatin's average speed is 6.67 km/hr.
Therefore, the correct answer is option 'C' - 6.67 km/hr.
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Jatin goes to a place at a speed of 5 km/hr and return home at speed of 10 km/hr. What is his average speed (in km/hr)?a)6.5b)6.8c)6.67d)8Correct answer is option 'C'. Can you explain this answer?
Question Description
Jatin goes to a place at a speed of 5 km/hr and return home at speed of 10 km/hr. What is his average speed (in km/hr)?a)6.5b)6.8c)6.67d)8Correct answer is option 'C'. Can you explain this answer? for Defence 2024 is part of Defence preparation. The Question and answers have been prepared according to the Defence exam syllabus. Information about Jatin goes to a place at a speed of 5 km/hr and return home at speed of 10 km/hr. What is his average speed (in km/hr)?a)6.5b)6.8c)6.67d)8Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Defence 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Jatin goes to a place at a speed of 5 km/hr and return home at speed of 10 km/hr. What is his average speed (in km/hr)?a)6.5b)6.8c)6.67d)8Correct answer is option 'C'. Can you explain this answer?.
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