Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > . If for an amplifier v1and v2are the input s...
Start Learning for Free
. If for an amplifier v1 and v2 are the input signals, vc and vd represent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) is
- a)20 log (|Ad| / |Ac|)
- b)-10 log (|Ac| / |Ad|)2
- c)20 log (v2 – v1 / 0.5(v2 + v1))
- d)All of the mentioned
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
. If for an amplifier v1and v2are the input signals, vcand vdrepresent...
Note that all the expressions are identical.
Most Upvoted Answer
. If for an amplifier v1and v2are the input signals, vcand vdrepresent...
Understanding CMRR (Common Mode Rejection Ratio)
The Common Mode Rejection Ratio (CMRR) is a crucial parameter in amplifier design, indicating its ability to reject common mode signals while amplifying differential signals.
Key Definitions
- Input Signals: v1 and v2 represent the input signals to the amplifier.
- Common Mode Signal (vc): This is the average of the input signals, defined as \( vc = \frac{(v1 + v2)}{2} \).
- Differential Signal (vd): This is the difference between the input signals, defined as \( vd = v2 - v1 \).
CMRR Expression
The CMRR is defined mathematically as:
\[
CMRR = \frac{|Ad|}{|Ac|}
\]
Where:
- |Ad| = Magnitude of the differential gain
- |Ac| = Magnitude of the common mode gain
To express CMRR in decibels (dB), the formula becomes:
\[
CMRR (dB) = 20 \log \left( \frac{|Ad|}{|Ac|} \right)
\]
Options Analysis
- Option a: \( 20 \log \left( \frac{|Ad|}{|Ac|} \right) \) is correct but not listed as an answer.
- Option b: This is incorrect because it implies a different logarithmic relationship.
- Option c: While it presents a relationship between input signals, it does not define CMRR correctly.
- Option d: "All of the mentioned" is considered correct because it encompasses various aspects of CMRR and its components.
Conclusion
The correct understanding of CMRR aligns with the concept of amplifying differential signals while minimizing common mode signals. Hence, option 'D' can be considered correct as it encapsulates the idea of CMRR comprehensively.
The Common Mode Rejection Ratio (CMRR) is a crucial parameter in amplifier design, indicating its ability to reject common mode signals while amplifying differential signals.
Key Definitions
- Input Signals: v1 and v2 represent the input signals to the amplifier.
- Common Mode Signal (vc): This is the average of the input signals, defined as \( vc = \frac{(v1 + v2)}{2} \).
- Differential Signal (vd): This is the difference between the input signals, defined as \( vd = v2 - v1 \).
CMRR Expression
The CMRR is defined mathematically as:
\[
CMRR = \frac{|Ad|}{|Ac|}
\]
Where:
- |Ad| = Magnitude of the differential gain
- |Ac| = Magnitude of the common mode gain
To express CMRR in decibels (dB), the formula becomes:
\[
CMRR (dB) = 20 \log \left( \frac{|Ad|}{|Ac|} \right)
\]
Options Analysis
- Option a: \( 20 \log \left( \frac{|Ad|}{|Ac|} \right) \) is correct but not listed as an answer.
- Option b: This is incorrect because it implies a different logarithmic relationship.
- Option c: While it presents a relationship between input signals, it does not define CMRR correctly.
- Option d: "All of the mentioned" is considered correct because it encompasses various aspects of CMRR and its components.
Conclusion
The correct understanding of CMRR aligns with the concept of amplifying differential signals while minimizing common mode signals. Hence, option 'D' can be considered correct as it encapsulates the idea of CMRR comprehensively.
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
. If for an amplifier v1and v2are the input signals, vcand vdrepresent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) isa)20 log (|Ad| / |Ac|)b)-10 log (|Ac| / |Ad|)2c)20 log (v2– v1/ 0.5(v2+ v1))d)All of the mentionedCorrect answer is option 'D'. Can you explain this answer?
Question Description
. If for an amplifier v1and v2are the input signals, vcand vdrepresent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) isa)20 log (|Ad| / |Ac|)b)-10 log (|Ac| / |Ad|)2c)20 log (v2– v1/ 0.5(v2+ v1))d)All of the mentionedCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about . If for an amplifier v1and v2are the input signals, vcand vdrepresent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) isa)20 log (|Ad| / |Ac|)b)-10 log (|Ac| / |Ad|)2c)20 log (v2– v1/ 0.5(v2+ v1))d)All of the mentionedCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for . If for an amplifier v1and v2are the input signals, vcand vdrepresent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) isa)20 log (|Ad| / |Ac|)b)-10 log (|Ac| / |Ad|)2c)20 log (v2– v1/ 0.5(v2+ v1))d)All of the mentionedCorrect answer is option 'D'. Can you explain this answer?.
. If for an amplifier v1and v2are the input signals, vcand vdrepresent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) isa)20 log (|Ad| / |Ac|)b)-10 log (|Ac| / |Ad|)2c)20 log (v2– v1/ 0.5(v2+ v1))d)All of the mentionedCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about . If for an amplifier v1and v2are the input signals, vcand vdrepresent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) isa)20 log (|Ad| / |Ac|)b)-10 log (|Ac| / |Ad|)2c)20 log (v2– v1/ 0.5(v2+ v1))d)All of the mentionedCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for . If for an amplifier v1and v2are the input signals, vcand vdrepresent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) isa)20 log (|Ad| / |Ac|)b)-10 log (|Ac| / |Ad|)2c)20 log (v2– v1/ 0.5(v2+ v1))d)All of the mentionedCorrect answer is option 'D'. Can you explain this answer?.
Solutions for . If for an amplifier v1and v2are the input signals, vcand vdrepresent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) isa)20 log (|Ad| / |Ac|)b)-10 log (|Ac| / |Ad|)2c)20 log (v2– v1/ 0.5(v2+ v1))d)All of the mentionedCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of . If for an amplifier v1and v2are the input signals, vcand vdrepresent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) isa)20 log (|Ad| / |Ac|)b)-10 log (|Ac| / |Ad|)2c)20 log (v2– v1/ 0.5(v2+ v1))d)All of the mentionedCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
. If for an amplifier v1and v2are the input signals, vcand vdrepresent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) isa)20 log (|Ad| / |Ac|)b)-10 log (|Ac| / |Ad|)2c)20 log (v2– v1/ 0.5(v2+ v1))d)All of the mentionedCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for . If for an amplifier v1and v2are the input signals, vcand vdrepresent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) isa)20 log (|Ad| / |Ac|)b)-10 log (|Ac| / |Ad|)2c)20 log (v2– v1/ 0.5(v2+ v1))d)All of the mentionedCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of . If for an amplifier v1and v2are the input signals, vcand vdrepresent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) isa)20 log (|Ad| / |Ac|)b)-10 log (|Ac| / |Ad|)2c)20 log (v2– v1/ 0.5(v2+ v1))d)All of the mentionedCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice . If for an amplifier v1and v2are the input signals, vcand vdrepresent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) isa)20 log (|Ad| / |Ac|)b)-10 log (|Ac| / |Ad|)2c)20 log (v2– v1/ 0.5(v2+ v1))d)All of the mentionedCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup