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A broad gauge railway line passes through a horizontal curved section (radius = 875 m) of length 200 m. The allowable speed on this portion is 100 km/h. For calculating the cant, consider the gauge as centre-to-centre distance between the rail heads, equal to 1750mm, The maximum permissible cant (in mm, round off to 1 decimal place) with respect to the centretocentre distance between the rail heads is ______.
Correct answer is '157.6'. Can you explain this answer?
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A broad gauge railway line passes through a horizontal curved section ...
Given data:
R = 875 mm
Allowable speed = 100 kmph
Gauge length G = 1750 mm
Allowable cant
R = 875 mm
Allowable speed = 100 kmph
Gauge length G = 1750 mm
Allowable cant
Most Upvoted Answer
A broad gauge railway line passes through a horizontal curved section ...
Problem: Calculate the maximum permissible cant on a curved railway track with radius 875 m and length 200 m, given the allowable speed is 100 km/h and the gauge is 1750 mm.
Solution:
To ensure safe and comfortable travel on a curved section of a railway track, a cant is provided. Cant is the difference in height between the inner and outer rails of a curved track. The cant is provided in such a way that the centrifugal force acting on a train is balanced by the lateral force provided by the cant.
Step 1: Calculate the cant deficiency
The cant deficiency is the amount by which the actual cant falls short of the required cant. It is given by the formula:
Cant deficiency = (V^2 / gR) - e
where,
V = speed of the train in m/s
g = acceleration due to gravity = 9.81 m/s^2
R = radius of curvature of the track
e = superelevation or cant in mm/m
Substituting the given values, we get:
V = 100 km/h = 27.78 m/s
R = 875 m
g = 9.81 m/s^2
Cant deficiency = (27.78^2 / (9.81 x 875)) - e
Cant deficiency = 0.0405 - e
Step 2: Calculate the maximum permissible cant
The maximum permissible cant is given by the formula:
Maximum permissible cant = (Gauge / 2) x (Cant deficiency + Cant gradient)
where,
Gauge = distance between the rail heads
Cant gradient = rate of change of cant per unit length of track
For a broad gauge railway, the gauge is 1750 mm.
The cant gradient is usually taken as 1 in 200, which means that the cant increases by 1 mm for every 200 mm of track length.
Substituting the given values, we get:
Cant gradient = 1 mm / 200 mm = 0.005
Gauge = 1750 mm
Maximum permissible cant = (1750 / 2) x (0.0405 + 0.005)
Maximum permissible cant = 157.6 mm (rounded off to 1 decimal place)
Therefore, the maximum permissible cant with respect to the centre-to-centre distance between the rail heads is 157.6 mm.
Solution:
To ensure safe and comfortable travel on a curved section of a railway track, a cant is provided. Cant is the difference in height between the inner and outer rails of a curved track. The cant is provided in such a way that the centrifugal force acting on a train is balanced by the lateral force provided by the cant.
Step 1: Calculate the cant deficiency
The cant deficiency is the amount by which the actual cant falls short of the required cant. It is given by the formula:
Cant deficiency = (V^2 / gR) - e
where,
V = speed of the train in m/s
g = acceleration due to gravity = 9.81 m/s^2
R = radius of curvature of the track
e = superelevation or cant in mm/m
Substituting the given values, we get:
V = 100 km/h = 27.78 m/s
R = 875 m
g = 9.81 m/s^2
Cant deficiency = (27.78^2 / (9.81 x 875)) - e
Cant deficiency = 0.0405 - e
Step 2: Calculate the maximum permissible cant
The maximum permissible cant is given by the formula:
Maximum permissible cant = (Gauge / 2) x (Cant deficiency + Cant gradient)
where,
Gauge = distance between the rail heads
Cant gradient = rate of change of cant per unit length of track
For a broad gauge railway, the gauge is 1750 mm.
The cant gradient is usually taken as 1 in 200, which means that the cant increases by 1 mm for every 200 mm of track length.
Substituting the given values, we get:
Cant gradient = 1 mm / 200 mm = 0.005
Gauge = 1750 mm
Maximum permissible cant = (1750 / 2) x (0.0405 + 0.005)
Maximum permissible cant = 157.6 mm (rounded off to 1 decimal place)
Therefore, the maximum permissible cant with respect to the centre-to-centre distance between the rail heads is 157.6 mm.
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A broad gauge railway line passes through a horizontal curved section (radius = 875 m) of length 200 m. The allowable speed on this portion is 100 km/h. For calculating the cant, consider the gauge as centre-to-centre distance between the rail heads, equal to 1750mm, The maximum permissible cant (in mm, round off to 1 decimal place) with respect to the centretocentre distance between the rail heads is ______.Correct answer is '157.6'. Can you explain this answer?
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A broad gauge railway line passes through a horizontal curved section (radius = 875 m) of length 200 m. The allowable speed on this portion is 100 km/h. For calculating the cant, consider the gauge as centre-to-centre distance between the rail heads, equal to 1750mm, The maximum permissible cant (in mm, round off to 1 decimal place) with respect to the centretocentre distance between the rail heads is ______.Correct answer is '157.6'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A broad gauge railway line passes through a horizontal curved section (radius = 875 m) of length 200 m. The allowable speed on this portion is 100 km/h. For calculating the cant, consider the gauge as centre-to-centre distance between the rail heads, equal to 1750mm, The maximum permissible cant (in mm, round off to 1 decimal place) with respect to the centretocentre distance between the rail heads is ______.Correct answer is '157.6'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A broad gauge railway line passes through a horizontal curved section (radius = 875 m) of length 200 m. The allowable speed on this portion is 100 km/h. For calculating the cant, consider the gauge as centre-to-centre distance between the rail heads, equal to 1750mm, The maximum permissible cant (in mm, round off to 1 decimal place) with respect to the centretocentre distance between the rail heads is ______.Correct answer is '157.6'. Can you explain this answer?.
A broad gauge railway line passes through a horizontal curved section (radius = 875 m) of length 200 m. The allowable speed on this portion is 100 km/h. For calculating the cant, consider the gauge as centre-to-centre distance between the rail heads, equal to 1750mm, The maximum permissible cant (in mm, round off to 1 decimal place) with respect to the centretocentre distance between the rail heads is ______.Correct answer is '157.6'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A broad gauge railway line passes through a horizontal curved section (radius = 875 m) of length 200 m. The allowable speed on this portion is 100 km/h. For calculating the cant, consider the gauge as centre-to-centre distance between the rail heads, equal to 1750mm, The maximum permissible cant (in mm, round off to 1 decimal place) with respect to the centretocentre distance between the rail heads is ______.Correct answer is '157.6'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A broad gauge railway line passes through a horizontal curved section (radius = 875 m) of length 200 m. The allowable speed on this portion is 100 km/h. For calculating the cant, consider the gauge as centre-to-centre distance between the rail heads, equal to 1750mm, The maximum permissible cant (in mm, round off to 1 decimal place) with respect to the centretocentre distance between the rail heads is ______.Correct answer is '157.6'. Can you explain this answer?.
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