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For an ideal operational amplifier (except for the fact that it has finite gain) one set of the value for the input voltages (v2is the positive terminal v1is the negative terminal) and output voltage (v0) as determined experimentally is v1= 2.01V, v2=2.00V and v0= -0.99V. Experiment was carried with different values of input and output voltages. Which of the following is not possible considering experimental error?a)v1= 1.99V, v2= 2.00V, v0= 1.00Vb)v1= 1.00V, v2= 1.00V, v0= 0Vc)v1= 1.00V, v2= 1.10V, v0= 10.1Vd)v1= 0.99V, v2= 2.00V, v0= 1.00VCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about For an ideal operational amplifier (except for the fact that it has finite gain) one set of the value for the input voltages (v2is the positive terminal v1is the negative terminal) and output voltage (v0) as determined experimentally is v1= 2.01V, v2=2.00V and v0= -0.99V. Experiment was carried with different values of input and output voltages. Which of the following is not possible considering experimental error?a)v1= 1.99V, v2= 2.00V, v0= 1.00Vb)v1= 1.00V, v2= 1.00V, v0= 0Vc)v1= 1.00V, v2= 1.10V, v0= 10.1Vd)v1= 0.99V, v2= 2.00V, v0= 1.00VCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For an ideal operational amplifier (except for the fact that it has finite gain) one set of the value for the input voltages (v2is the positive terminal v1is the negative terminal) and output voltage (v0) as determined experimentally is v1= 2.01V, v2=2.00V and v0= -0.99V. Experiment was carried with different values of input and output voltages. Which of the following is not possible considering experimental error?a)v1= 1.99V, v2= 2.00V, v0= 1.00Vb)v1= 1.00V, v2= 1.00V, v0= 0Vc)v1= 1.00V, v2= 1.10V, v0= 10.1Vd)v1= 0.99V, v2= 2.00V, v0= 1.00VCorrect answer is option 'D'. Can you explain this answer?.

Solutions for For an ideal operational amplifier (except for the fact that it has finite gain) one set of the value for the input voltages (v2is the positive terminal v1is the negative terminal) and output voltage (v0) as determined experimentally is v1= 2.01V, v2=2.00V and v0= -0.99V. Experiment was carried with different values of input and output voltages. Which of the following is not possible considering experimental error?a)v1= 1.99V, v2= 2.00V, v0= 1.00Vb)v1= 1.00V, v2= 1.00V, v0= 0Vc)v1= 1.00V, v2= 1.10V, v0= 10.1Vd)v1= 0.99V, v2= 2.00V, v0= 1.00VCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.

Here you can find the meaning of For an ideal operational amplifier (except for the fact that it has finite gain) one set of the value for the input voltages (v2is the positive terminal v1is the negative terminal) and output voltage (v0) as determined experimentally is v1= 2.01V, v2=2.00V and v0= -0.99V. Experiment was carried with different values of input and output voltages. Which of the following is not possible considering experimental error?a)v1= 1.99V, v2= 2.00V, v0= 1.00Vb)v1= 1.00V, v2= 1.00V, v0= 0Vc)v1= 1.00V, v2= 1.10V, v0= 10.1Vd)v1= 0.99V, v2= 2.00V, v0= 1.00VCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of For an ideal operational amplifier (except for the fact that it has finite gain) one set of the value for the input voltages (v2is the positive terminal v1is the negative terminal) and output voltage (v0) as determined experimentally is v1= 2.01V, v2=2.00V and v0= -0.99V. Experiment was carried with different values of input and output voltages. Which of the following is not possible considering experimental error?a)v1= 1.99V, v2= 2.00V, v0= 1.00Vb)v1= 1.00V, v2= 1.00V, v0= 0Vc)v1= 1.00V, v2= 1.10V, v0= 10.1Vd)v1= 0.99V, v2= 2.00V, v0= 1.00VCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for For an ideal operational amplifier (except for the fact that it has finite gain) one set of the value for the input voltages (v2is the positive terminal v1is the negative terminal) and output voltage (v0) as determined experimentally is v1= 2.01V, v2=2.00V and v0= -0.99V. Experiment was carried with different values of input and output voltages. Which of the following is not possible considering experimental error?a)v1= 1.99V, v2= 2.00V, v0= 1.00Vb)v1= 1.00V, v2= 1.00V, v0= 0Vc)v1= 1.00V, v2= 1.10V, v0= 10.1Vd)v1= 0.99V, v2= 2.00V, v0= 1.00VCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of For an ideal operational amplifier (except for the fact that it has finite gain) one set of the value for the input voltages (v2is the positive terminal v1is the negative terminal) and output voltage (v0) as determined experimentally is v1= 2.01V, v2=2.00V and v0= -0.99V. Experiment was carried with different values of input and output voltages. Which of the following is not possible considering experimental error?a)v1= 1.99V, v2= 2.00V, v0= 1.00Vb)v1= 1.00V, v2= 1.00V, v0= 0Vc)v1= 1.00V, v2= 1.10V, v0= 10.1Vd)v1= 0.99V, v2= 2.00V, v0= 1.00VCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice For an ideal operational amplifier (except for the fact that it has finite gain) one set of the value for the input voltages (v2is the positive terminal v1is the negative terminal) and output voltage (v0) as determined experimentally is v1= 2.01V, v2=2.00V and v0= -0.99V. Experiment was carried with different values of input and output voltages. Which of the following is not possible considering experimental error?a)v1= 1.99V, v2= 2.00V, v0= 1.00Vb)v1= 1.00V, v2= 1.00V, v0= 0Vc)v1= 1.00V, v2= 1.10V, v0= 10.1Vd)v1= 0.99V, v2= 2.00V, v0= 1.00VCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.