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In an ideal op amp the open-loop gain is 103. The op amp is used in a feedback circuit, and the voltages appearing at two of its three signal terminals are measured as v2= 0V and v3= 2V where it is assumed that v1and v2are input terminals and v3is the output terminal. The value of the differential (vd) and common-mode (vcm)signal isa)Vd= 2 mV and vcm= 1 mvb)Vd= 2 mV and vcm= -1 mVc)Vd= 2 mV and vcm= 2mVd)Vd= 2 mV and vcm= -2mVCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about In an ideal op amp the open-loop gain is 103. The op amp is used in a feedback circuit, and the voltages appearing at two of its three signal terminals are measured as v2= 0V and v3= 2V where it is assumed that v1and v2are input terminals and v3is the output terminal. The value of the differential (vd) and common-mode (vcm)signal isa)Vd= 2 mV and vcm= 1 mvb)Vd= 2 mV and vcm= -1 mVc)Vd= 2 mV and vcm= 2mVd)Vd= 2 mV and vcm= -2mVCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an ideal op amp the open-loop gain is 103. The op amp is used in a feedback circuit, and the voltages appearing at two of its three signal terminals are measured as v2= 0V and v3= 2V where it is assumed that v1and v2are input terminals and v3is the output terminal. The value of the differential (vd) and common-mode (vcm)signal isa)Vd= 2 mV and vcm= 1 mvb)Vd= 2 mV and vcm= -1 mVc)Vd= 2 mV and vcm= 2mVd)Vd= 2 mV and vcm= -2mVCorrect answer is option 'B'. Can you explain this answer?.

Solutions for In an ideal op amp the open-loop gain is 103. The op amp is used in a feedback circuit, and the voltages appearing at two of its three signal terminals are measured as v2= 0V and v3= 2V where it is assumed that v1and v2are input terminals and v3is the output terminal. The value of the differential (vd) and common-mode (vcm)signal isa)Vd= 2 mV and vcm= 1 mvb)Vd= 2 mV and vcm= -1 mVc)Vd= 2 mV and vcm= 2mVd)Vd= 2 mV and vcm= -2mVCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.

Here you can find the meaning of In an ideal op amp the open-loop gain is 103. The op amp is used in a feedback circuit, and the voltages appearing at two of its three signal terminals are measured as v2= 0V and v3= 2V where it is assumed that v1and v2are input terminals and v3is the output terminal. The value of the differential (vd) and common-mode (vcm)signal isa)Vd= 2 mV and vcm= 1 mvb)Vd= 2 mV and vcm= -1 mVc)Vd= 2 mV and vcm= 2mVd)Vd= 2 mV and vcm= -2mVCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In an ideal op amp the open-loop gain is 103. The op amp is used in a feedback circuit, and the voltages appearing at two of its three signal terminals are measured as v2= 0V and v3= 2V where it is assumed that v1and v2are input terminals and v3is the output terminal. The value of the differential (vd) and common-mode (vcm)signal isa)Vd= 2 mV and vcm= 1 mvb)Vd= 2 mV and vcm= -1 mVc)Vd= 2 mV and vcm= 2mVd)Vd= 2 mV and vcm= -2mVCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for In an ideal op amp the open-loop gain is 103. The op amp is used in a feedback circuit, and the voltages appearing at two of its three signal terminals are measured as v2= 0V and v3= 2V where it is assumed that v1and v2are input terminals and v3is the output terminal. The value of the differential (vd) and common-mode (vcm)signal isa)Vd= 2 mV and vcm= 1 mvb)Vd= 2 mV and vcm= -1 mVc)Vd= 2 mV and vcm= 2mVd)Vd= 2 mV and vcm= -2mVCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of In an ideal op amp the open-loop gain is 103. The op amp is used in a feedback circuit, and the voltages appearing at two of its three signal terminals are measured as v2= 0V and v3= 2V where it is assumed that v1and v2are input terminals and v3is the output terminal. The value of the differential (vd) and common-mode (vcm)signal isa)Vd= 2 mV and vcm= 1 mvb)Vd= 2 mV and vcm= -1 mVc)Vd= 2 mV and vcm= 2mVd)Vd= 2 mV and vcm= -2mVCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In an ideal op amp the open-loop gain is 103. The op amp is used in a feedback circuit, and the voltages appearing at two of its three signal terminals are measured as v2= 0V and v3= 2V where it is assumed that v1and v2are input terminals and v3is the output terminal. The value of the differential (vd) and common-mode (vcm)signal isa)Vd= 2 mV and vcm= 1 mvb)Vd= 2 mV and vcm= -1 mVc)Vd= 2 mV and vcm= 2mVd)Vd= 2 mV and vcm= -2mVCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.