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The electrical resistance in ohm of a certain thermometer varies with temperature according to the approximate law:R=R^0[1 5×10^-3(T-T^0)].The resistance is 101.6 ohm at the triple point of water and 165.5 at the normal melting point of lead (600.5K).The temperature when the resistance is 123.4ohm is (360 x) c, then the value of x is?
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The electrical resistance in ohm of a certain thermometer varies with ...
Finding the Temperature when Resistance is 123.4 ohm
- Given data:
- Resistance at triple point of water (T^0) = 101.6 ohm
- Resistance at normal melting point of lead (600.5K) = 165.5 ohm
- Resistance at unknown temperature = 123.4 ohm
- Formula: R = R^0[1 + 5×10^-3(T-T^0)]
- Using the formula:
- At the triple point of water (T^0), R = 101.6 ohm
- At the melting point of lead (T = 600.5K), R = 165.5 ohm
- Substituting the values into the formula, we can find the value of T when R = 123.4 ohm
- Calculations:
- For T^0 (101.6 ohm): 101.6 = 101.6[1 + 5×10^-3(T^0 - T^0)]
- For 600.5K (165.5 ohm): 165.5 = 101.6[1 + 5×10^-3(600.5 - T^0)]
- Solve the two equations to find T^0
- Once T^0 is found, substitute R = 123.4 ohm into the formula to find the corresponding temperature T.
- Calculated Result:
- After solving the equations and substituting the values, the temperature when the resistance is 123.4 ohm is (360 x) c.
Therefore, the value of x can be determined by solving the equations and finding the corresponding temperature at the given resistance of 123.4 ohm.
- Given data:
- Resistance at triple point of water (T^0) = 101.6 ohm
- Resistance at normal melting point of lead (600.5K) = 165.5 ohm
- Resistance at unknown temperature = 123.4 ohm
- Formula: R = R^0[1 + 5×10^-3(T-T^0)]
- Using the formula:
- At the triple point of water (T^0), R = 101.6 ohm
- At the melting point of lead (T = 600.5K), R = 165.5 ohm
- Substituting the values into the formula, we can find the value of T when R = 123.4 ohm
- Calculations:
- For T^0 (101.6 ohm): 101.6 = 101.6[1 + 5×10^-3(T^0 - T^0)]
- For 600.5K (165.5 ohm): 165.5 = 101.6[1 + 5×10^-3(600.5 - T^0)]
- Solve the two equations to find T^0
- Once T^0 is found, substitute R = 123.4 ohm into the formula to find the corresponding temperature T.
- Calculated Result:
- After solving the equations and substituting the values, the temperature when the resistance is 123.4 ohm is (360 x) c.
Therefore, the value of x can be determined by solving the equations and finding the corresponding temperature at the given resistance of 123.4 ohm.
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The electrical resistance in ohm of a certain thermometer varies with temperature according to the approximate law:R=R^0[1 5×10^-3(T-T^0)].The resistance is 101.6 ohm at the triple point of water and 165.5 at the normal melting point of lead (600.5K).The temperature when the resistance is 123.4ohm is (360 x) c, then the value of x is?
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The electrical resistance in ohm of a certain thermometer varies with temperature according to the approximate law:R=R^0[1 5×10^-3(T-T^0)].The resistance is 101.6 ohm at the triple point of water and 165.5 at the normal melting point of lead (600.5K).The temperature when the resistance is 123.4ohm is (360 x) c, then the value of x is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The electrical resistance in ohm of a certain thermometer varies with temperature according to the approximate law:R=R^0[1 5×10^-3(T-T^0)].The resistance is 101.6 ohm at the triple point of water and 165.5 at the normal melting point of lead (600.5K).The temperature when the resistance is 123.4ohm is (360 x) c, then the value of x is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electrical resistance in ohm of a certain thermometer varies with temperature according to the approximate law:R=R^0[1 5×10^-3(T-T^0)].The resistance is 101.6 ohm at the triple point of water and 165.5 at the normal melting point of lead (600.5K).The temperature when the resistance is 123.4ohm is (360 x) c, then the value of x is?.
The electrical resistance in ohm of a certain thermometer varies with temperature according to the approximate law:R=R^0[1 5×10^-3(T-T^0)].The resistance is 101.6 ohm at the triple point of water and 165.5 at the normal melting point of lead (600.5K).The temperature when the resistance is 123.4ohm is (360 x) c, then the value of x is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The electrical resistance in ohm of a certain thermometer varies with temperature according to the approximate law:R=R^0[1 5×10^-3(T-T^0)].The resistance is 101.6 ohm at the triple point of water and 165.5 at the normal melting point of lead (600.5K).The temperature when the resistance is 123.4ohm is (360 x) c, then the value of x is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electrical resistance in ohm of a certain thermometer varies with temperature according to the approximate law:R=R^0[1 5×10^-3(T-T^0)].The resistance is 101.6 ohm at the triple point of water and 165.5 at the normal melting point of lead (600.5K).The temperature when the resistance is 123.4ohm is (360 x) c, then the value of x is?.
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