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An aromatic carboxylic acid has some of hydrogen of benzene replaced by —COOH group. Neutralisation equivalent of this acid is exactly 63.5. How many carboxyl groups are present on the benzene ring of original aromatic acid?
Correct answer is '4'. Can you explain this answer?
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An aromatic carboxylic acid has some of hydrogen of benzene replaced b...
The formula of acid is C6H6-n(COOH)n
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An aromatic carboxylic acid has some of hydrogen of benzene replaced b...
Understanding the Problem
The neutralization equivalent of an acid is defined as the mass of the acid that reacts with one equivalent of a base. For carboxylic acids, this is directly related to the number of carboxyl (–COOH) groups present.
Given Data
- Neutralization equivalent = 63.5 g/equiv
Calculating Molar Mass
To find the number of carboxyl groups (n), we can use the formula:
- Neutralization Equivalent = Molar Mass / n
Here, the molar mass of the aromatic carboxylic acid can be calculated based on the formula of benzene (C6H6) and the addition of carboxyl groups.
Finding Molar Mass
Assuming the aromatic acid is derived from benzene:
- Molar mass of benzene (C6H6) = 78 g/mol
- Molar mass of –COOH = 44 g/mol
Thus, the molar mass of the aromatic acid can be expressed as:
- Molar Mass = 78 + 44n
Setting up the equation based on the neutralization equivalent:
- 63.5 = (78 + 44n) / n
Solving the Equation
Rearranging the equation gives:
- 63.5n = 78 + 44n
This simplifies to:
- 63.5n - 44n = 78
- 19.5n = 78
- n = 78 / 19.5
- n = 4
Conclusion
The number of carboxyl groups present on the benzene ring of the original aromatic acid is **4**. Thus, the final structure of the acid can be represented as tetracarboxylic acid, confirming the presence of four –COOH groups on the benzene ring.
The neutralization equivalent of an acid is defined as the mass of the acid that reacts with one equivalent of a base. For carboxylic acids, this is directly related to the number of carboxyl (–COOH) groups present.
Given Data
- Neutralization equivalent = 63.5 g/equiv
Calculating Molar Mass
To find the number of carboxyl groups (n), we can use the formula:
- Neutralization Equivalent = Molar Mass / n
Here, the molar mass of the aromatic carboxylic acid can be calculated based on the formula of benzene (C6H6) and the addition of carboxyl groups.
Finding Molar Mass
Assuming the aromatic acid is derived from benzene:
- Molar mass of benzene (C6H6) = 78 g/mol
- Molar mass of –COOH = 44 g/mol
Thus, the molar mass of the aromatic acid can be expressed as:
- Molar Mass = 78 + 44n
Setting up the equation based on the neutralization equivalent:
- 63.5 = (78 + 44n) / n
Solving the Equation
Rearranging the equation gives:
- 63.5n = 78 + 44n
This simplifies to:
- 63.5n - 44n = 78
- 19.5n = 78
- n = 78 / 19.5
- n = 4
Conclusion
The number of carboxyl groups present on the benzene ring of the original aromatic acid is **4**. Thus, the final structure of the acid can be represented as tetracarboxylic acid, confirming the presence of four –COOH groups on the benzene ring.
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An aromatic carboxylic acid has some of hydrogen of benzene replaced by —COOH group. Neutralisation equivalent of this acid is exactly 63.5. How many carboxyl groups are present on the benzene ring of original aromatic acid?Correct answer is '4'. Can you explain this answer?
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An aromatic carboxylic acid has some of hydrogen of benzene replaced by —COOH group. Neutralisation equivalent of this acid is exactly 63.5. How many carboxyl groups are present on the benzene ring of original aromatic acid?Correct answer is '4'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An aromatic carboxylic acid has some of hydrogen of benzene replaced by —COOH group. Neutralisation equivalent of this acid is exactly 63.5. How many carboxyl groups are present on the benzene ring of original aromatic acid?Correct answer is '4'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An aromatic carboxylic acid has some of hydrogen of benzene replaced by —COOH group. Neutralisation equivalent of this acid is exactly 63.5. How many carboxyl groups are present on the benzene ring of original aromatic acid?Correct answer is '4'. Can you explain this answer?.
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