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A parabolic vertical curve is being designed to join a road of grade + 5% with a road of grade –3%. The length of the vertical curve is 400 m measured along the horizontal. The vertical point of curvature (VPC) is located on the road of grade +5%. The difference in height between VPC and vertical point of intersection (VPI) (in m, round off to the nearest integer) is ______________
    Correct answer is '10'. Can you explain this answer?
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    A parabolic vertical curve is being designed to join a road of grade +...

    Height difference between
    VPI & VPC = 5% of 200 m = 10 m
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    A parabolic vertical curve is being designed to join a road of grade +...
    -3%. The initial grade line is at elevation 1000 ft and the final grade line is at elevation 900 ft. The length of the vertical curve is 500 ft.

    To begin designing the parabolic vertical curve, we need to find the elevation at the midpoint of the curve. The midpoint is located at 250 ft from the initial grade line.

    Using the formula for the elevation of a parabolic vertical curve at a given distance, we can calculate the elevation at the midpoint:

    Elevation = Initial elevation + ((Final elevation - Initial elevation) / (Length of curve / 2))^2

    Elevation = 1000 + ((900 - 1000) / (500 / 2))^2
    Elevation = 1000 + ((-100) / 250)^2
    Elevation = 1000 + (-0.4)^2
    Elevation = 1000 + 0.16
    Elevation = 1000.16 ft

    Therefore, the elevation at the midpoint of the curve is 1000.16 ft.

    Next, we need to find the elevation of the high point of the curve. The high point is located at 250 ft from the initial grade line and 250 ft from the final grade line.

    Using the same formula as before, we can calculate the elevation at the high point:

    Elevation = Initial elevation + ((Final elevation - Initial elevation) / (Length of curve / 2))^2

    Elevation = 1000 + ((900 - 1000) / (500 / 2))^2
    Elevation = 1000 + ((-100) / 250)^2
    Elevation = 1000 + (-0.4)^2
    Elevation = 1000 + 0.16
    Elevation = 1000.16 ft

    Therefore, the elevation at the high point of the curve is also 1000.16 ft.

    Now, we can calculate the rates of change of grade at the high point and the initial and final grade lines.

    Rate of change of grade at the high point = (Final grade - Initial grade) / Length of curve
    Rate of change of grade at the high point = (-3% - 5%) / 500 ft
    Rate of change of grade at the high point = -8% / 500 ft
    Rate of change of grade at the high point = -0.08 ft/ft

    Rate of change of grade at the initial grade line = (Elevation at the high point - Initial elevation) / Length of curve
    Rate of change of grade at the initial grade line = (1000.16 ft - 1000 ft) / 500 ft
    Rate of change of grade at the initial grade line = 0.16 ft / 500 ft
    Rate of change of grade at the initial grade line = 0.00032 ft/ft

    Rate of change of grade at the final grade line = (Final elevation - Elevation at the high point) / Length of curve
    Rate of change of grade at the final grade line = (900 ft - 1000.16 ft) / 500 ft
    Rate of change of grade at the final grade line = -100.16 ft / 500 ft
    Rate of change of grade at the final grade line = -0.20032 ft/ft

    Therefore, the rates of change of grade
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    A parabolic vertical curve is being designed to join a road of grade +...
    N=|+5% -(-3%)|
       = | +8%|
       = 0.08
    Difference in height
     Y=( N/2L) � x^2
      Where x^2 = n1 � L / N
                          = (0.05 � 400)/0.08
                           =250 m
    Thus Y = 0.08 � 250^2 / 2 � 400
                Y = 6.25 m. (Ans).
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    A parabolic vertical curve is being designed to join a road of grade + 5% with a road of grade –3%. The length of the vertical curve is 400 m measured along the horizontal. The vertical point of curvature (VPC) is located on the road of grade +5%. The difference in height between VPC and vertical point of intersection (VPI) (in m, round off to the nearest integer) is ______________Correct answer is '10'. Can you explain this answer?
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    A parabolic vertical curve is being designed to join a road of grade + 5% with a road of grade –3%. The length of the vertical curve is 400 m measured along the horizontal. The vertical point of curvature (VPC) is located on the road of grade +5%. The difference in height between VPC and vertical point of intersection (VPI) (in m, round off to the nearest integer) is ______________Correct answer is '10'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A parabolic vertical curve is being designed to join a road of grade + 5% with a road of grade –3%. The length of the vertical curve is 400 m measured along the horizontal. The vertical point of curvature (VPC) is located on the road of grade +5%. The difference in height between VPC and vertical point of intersection (VPI) (in m, round off to the nearest integer) is ______________Correct answer is '10'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A parabolic vertical curve is being designed to join a road of grade + 5% with a road of grade –3%. The length of the vertical curve is 400 m measured along the horizontal. The vertical point of curvature (VPC) is located on the road of grade +5%. The difference in height between VPC and vertical point of intersection (VPI) (in m, round off to the nearest integer) is ______________Correct answer is '10'. Can you explain this answer?.
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