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A computer system has an L1 cache, an L2 cache, and a main memory unit connected as shown below. The block size in L1cache is 4 words. The block size in L2 cache is 16 words. The memory access times are 2 nanoseconds, 20 nano seconds and 200 nano seconds for L1 cache, L2 cache and the main memory unit respectively.
When there is a miss in L1 cache and a hit in L2 cache, a block is transferred from L2 cache to L1 cache. What is the timetaken for this transfer?
  • a)
    2 nanoseconds
  • b)
    20 nanoseconds
  • c)
    22 nanoseconds
  • d)
    88 nanoseconds
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A computer system has an L1 cache, an L2 cache, and a main memory unit...
Ideally the answer should be 20 ns as it is the time to transfer a block from L2 to L1 and this time only is asked in
question. But there is confusion regarding access time of L2 as this means the time to read data from L2 till CPU but here
we need the time till L1 only. So, I assume the following is what is meant by the question.
A block is transferred from L2 to L1. And L1 block size being 4 words (since L1 is requesting we need to consider L1 block
size and not L2 block size) and data width being 4 bytes, it requires one L2 access (for read) and one L1 access (for store).
So, time = 20+2 = 22 ns.
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A computer system has an L1 cache, an L2 cache, and a main memory unit connected as shown below. The block size in L1cache is 4 words. The block size in L2 cache is 16 words. The memory access times are 2 nanoseconds, 20 nano seconds and 200 nano seconds for L1 cache, L2 cache and the main memory unit respectively.When there is a miss in L1 cache and a hit in L2 cache, a block is transferred from L2 cache to L1 cache. What is the timetaken for this transfer?a)2 nanosecondsb)20 nanosecondsc)22 nanosecondsd)88 nanosecondsCorrect answer is option 'C'. Can you explain this answer?
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A computer system has an L1 cache, an L2 cache, and a main memory unit connected as shown below. The block size in L1cache is 4 words. The block size in L2 cache is 16 words. The memory access times are 2 nanoseconds, 20 nano seconds and 200 nano seconds for L1 cache, L2 cache and the main memory unit respectively.When there is a miss in L1 cache and a hit in L2 cache, a block is transferred from L2 cache to L1 cache. What is the timetaken for this transfer?a)2 nanosecondsb)20 nanosecondsc)22 nanosecondsd)88 nanosecondsCorrect answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A computer system has an L1 cache, an L2 cache, and a main memory unit connected as shown below. The block size in L1cache is 4 words. The block size in L2 cache is 16 words. The memory access times are 2 nanoseconds, 20 nano seconds and 200 nano seconds for L1 cache, L2 cache and the main memory unit respectively.When there is a miss in L1 cache and a hit in L2 cache, a block is transferred from L2 cache to L1 cache. What is the timetaken for this transfer?a)2 nanosecondsb)20 nanosecondsc)22 nanosecondsd)88 nanosecondsCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A computer system has an L1 cache, an L2 cache, and a main memory unit connected as shown below. The block size in L1cache is 4 words. The block size in L2 cache is 16 words. The memory access times are 2 nanoseconds, 20 nano seconds and 200 nano seconds for L1 cache, L2 cache and the main memory unit respectively.When there is a miss in L1 cache and a hit in L2 cache, a block is transferred from L2 cache to L1 cache. What is the timetaken for this transfer?a)2 nanosecondsb)20 nanosecondsc)22 nanosecondsd)88 nanosecondsCorrect answer is option 'C'. Can you explain this answer?.
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