JEE Exam  >  JEE Questions  >  Resolve a weight of 10N in two direction whic... Start Learning for Free
Resolve a weight of 10N in two direction which are called parallel and perpendicular to a slope inclined at 30degree to the horizontal .?
Most Upvoted Answer
Resolve a weight of 10N in two direction which are called parallel and...
**Resolving a Weight of 10N on an Inclined Slope**

To resolve the weight of 10N in two directions, parallel and perpendicular to a slope inclined at 30 degrees to the horizontal, we need to break down the weight vector into its components along the slope and perpendicular to the slope.

1. **Understanding the Situation:**
- The weight vector represents the force of gravity acting on an object.
- The slope is inclined at an angle of 30 degrees to the horizontal.

2. **Resolving the Weight Vector:**
- Resolving the weight vector means breaking it down into two components, one parallel to the slope and the other perpendicular to the slope.
- The component parallel to the slope is referred to as the "parallel component," and the component perpendicular to the slope is referred to as the "perpendicular component."

3. **Calculating the Parallel Component:**
- The parallel component is the force acting along the slope.
- Since the slope is inclined at 30 degrees to the horizontal, we can use trigonometry to calculate the parallel component.
- The parallel component can be found by multiplying the weight (10N) by the cosine of the angle (30 degrees).
- Mathematically, the parallel component (P) can be calculated as P = weight * cos(angle).

- P = 10N * cos(30°)
- P = 10N * 0.866
- P ≈ 8.66N

4. **Calculating the Perpendicular Component:**
- The perpendicular component is the force acting perpendicular to the slope.
- Again, using trigonometry, we can calculate the perpendicular component.
- The perpendicular component can be found by multiplying the weight (10N) by the sine of the angle (30 degrees).
- Mathematically, the perpendicular component (Q) can be calculated as Q = weight * sin(angle).

- Q = 10N * sin(30°)
- Q = 10N * 0.5
- Q = 5N

5. **Summary:**
- The weight of 10N can be resolved into two components along the slope: a parallel component of approximately 8.66N and a perpendicular component of 5N.
- The parallel component acts parallel to the slope, while the perpendicular component acts perpendicular to the slope.
- The two components together add up to the original weight vector of 10N.

By resolving the weight vector into its components, we can understand how the weight is distributed along the inclined slope and how it contributes to the overall forces acting on the object.
Community Answer
Resolve a weight of 10N in two direction which are called parallel and...
5N correct Ans
Explore Courses for JEE exam

Similar JEE Doubts

Resolve a weight of 10N in two direction which are called parallel and perpendicular to a slope inclined at 30degree to the horizontal .?
Question Description
Resolve a weight of 10N in two direction which are called parallel and perpendicular to a slope inclined at 30degree to the horizontal .? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Resolve a weight of 10N in two direction which are called parallel and perpendicular to a slope inclined at 30degree to the horizontal .? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Resolve a weight of 10N in two direction which are called parallel and perpendicular to a slope inclined at 30degree to the horizontal .?.
Solutions for Resolve a weight of 10N in two direction which are called parallel and perpendicular to a slope inclined at 30degree to the horizontal .? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Resolve a weight of 10N in two direction which are called parallel and perpendicular to a slope inclined at 30degree to the horizontal .? defined & explained in the simplest way possible. Besides giving the explanation of Resolve a weight of 10N in two direction which are called parallel and perpendicular to a slope inclined at 30degree to the horizontal .?, a detailed solution for Resolve a weight of 10N in two direction which are called parallel and perpendicular to a slope inclined at 30degree to the horizontal .? has been provided alongside types of Resolve a weight of 10N in two direction which are called parallel and perpendicular to a slope inclined at 30degree to the horizontal .? theory, EduRev gives you an ample number of questions to practice Resolve a weight of 10N in two direction which are called parallel and perpendicular to a slope inclined at 30degree to the horizontal .? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev