Resolve a weight of 10N in two direction which are called parallel and...
**Resolving a Weight of 10N on an Inclined Slope**
To resolve the weight of 10N in two directions, parallel and perpendicular to a slope inclined at 30 degrees to the horizontal, we need to break down the weight vector into its components along the slope and perpendicular to the slope.
1. **Understanding the Situation:**
- The weight vector represents the force of gravity acting on an object.
- The slope is inclined at an angle of 30 degrees to the horizontal.
2. **Resolving the Weight Vector:**
- Resolving the weight vector means breaking it down into two components, one parallel to the slope and the other perpendicular to the slope.
- The component parallel to the slope is referred to as the "parallel component," and the component perpendicular to the slope is referred to as the "perpendicular component."
3. **Calculating the Parallel Component:**
- The parallel component is the force acting along the slope.
- Since the slope is inclined at 30 degrees to the horizontal, we can use trigonometry to calculate the parallel component.
- The parallel component can be found by multiplying the weight (10N) by the cosine of the angle (30 degrees).
- Mathematically, the parallel component (P) can be calculated as P = weight * cos(angle).
- P = 10N * cos(30°)
- P = 10N * 0.866
- P ≈ 8.66N
4. **Calculating the Perpendicular Component:**
- The perpendicular component is the force acting perpendicular to the slope.
- Again, using trigonometry, we can calculate the perpendicular component.
- The perpendicular component can be found by multiplying the weight (10N) by the sine of the angle (30 degrees).
- Mathematically, the perpendicular component (Q) can be calculated as Q = weight * sin(angle).
- Q = 10N * sin(30°)
- Q = 10N * 0.5
- Q = 5N
5. **Summary:**
- The weight of 10N can be resolved into two components along the slope: a parallel component of approximately 8.66N and a perpendicular component of 5N.
- The parallel component acts parallel to the slope, while the perpendicular component acts perpendicular to the slope.
- The two components together add up to the original weight vector of 10N.
By resolving the weight vector into its components, we can understand how the weight is distributed along the inclined slope and how it contributes to the overall forces acting on the object.
Resolve a weight of 10N in two direction which are called parallel and...
5N correct Ans
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