Sonu travels 8 Km towards North, then travels 12 Km towards East and t...
Distance between the starting point O and final point C is OC. So, ODC is A right angled triangle In a right angle triangle:
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Sonu travels 8 Km towards North, then travels 12 Km towards East and t...
Solution:
Sonu starts at a certain point and travels 8 km towards the north. Then, he travels 12 km towards the east. Finally, he travels 8 km towards the north again. We need to find out how far he is from the starting point.
To solve this problem, we can use the concept of coordinates. Let's assume the starting point as (0,0) on a coordinate plane.
Step 1: Traveling 8 km towards the North
When Sonu travels 8 km towards the north from the starting point, his position will be at (0,8).
Step 2: Traveling 12 km towards the East
From the current position (0,8), Sonu travels 12 km towards the east. This will make his position (12,8).
Step 3: Traveling 8 km towards the North again
Starting from the position (12,8), Sonu travels 8 km towards the north. His final position will be (12,16).
Therefore, Sonu is 12 km towards the east and 16 km towards the north from the starting point. We can use the Pythagorean theorem to find the distance between the starting point and Sonu's final position.
Using the Pythagorean theorem:
Distance = √((Change in x-coordinate)^2 + (Change in y-coordinate)^2)
Distance = √((12-0)^2 + (16-0)^2)
Distance = √(12^2 + 16^2)
Distance = √(144 + 256)
Distance = √400
Distance = 20 km
Therefore, Sonu is 20 km away from the starting point.