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In an experiment on young's double - slit with the light of wavelength 800 nm, the screen is placed at a distance of 1 m from the slits having separation of 2mm. Now the screen is moved away farther 0.25 m. What should be the new wavelength of light so that the fringe - width remains the same (in nm)?
Correct answer is '640'. Can you explain this answer?
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In an experiment on young's double - slit with the light of wavele...
Fringe width
Now the screen is moved away further by 0.25 m
D = 1.25 m
d = 2 x 10-3 m
d = 2 x 10-3 m
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In an experiment on young's double - slit with the light of wavele...
Given Information:
- Wavelength of light used in the experiment: 800 nm
- Distance between the slits: 2 mm = 0.002 m
- Initial distance between the screen and the slits: 1 m
- Final distance between the screen and the slits: 1.25 m
Explanation:
1. Fringe Width Formula:
The formula for calculating the fringe width in Young's double-slit experiment is given by:
β = λD / d
Where:
- β is the fringe width
- λ is the wavelength of light
- D is the distance between the screen and the slits
- d is the distance between the slits
2. Finding the Initial Fringe Width:
Using the given values, we can calculate the initial fringe width using the formula:
βinitial = λinitial * Dinitial / d
Substituting the given values:
βinitial = (800 * 10-9) * 1 / 0.002
Simplifying the expression:
βinitial = 0.4 mm
3. Finding the Final Wavelength:
To find the new wavelength of light, we need to keep the fringe width constant when the screen is moved to a new distance.
Using the same formula, we can calculate the new wavelength as follows:
βfinal = λfinal * Dfinal / d
Substituting the given values:
0.4 mm = λfinal * 1.25 / 0.002
Simplifying the expression:
λfinal = (0.4 mm * 0.002) / 1.25
Converting millimeters to meters and simplifying further:
λfinal = 0.00064 m = 640 nm
Therefore, the new wavelength of light should be 640 nm in order to maintain the same fringe width when the screen is moved to a distance of 1.25 m.
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In an experiment on young's double - slit with the light of wavelength 800 nm, the screen is placed at a distance of 1 m from the slits having separation of 2mm. Now the screen is moved away farther 0.25 m. What should be the new wavelength of light so that the fringe - width remains the same (in nm)?Correct answer is '640'. Can you explain this answer?
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In an experiment on young's double - slit with the light of wavelength 800 nm, the screen is placed at a distance of 1 m from the slits having separation of 2mm. Now the screen is moved away farther 0.25 m. What should be the new wavelength of light so that the fringe - width remains the same (in nm)?Correct answer is '640'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about In an experiment on young's double - slit with the light of wavelength 800 nm, the screen is placed at a distance of 1 m from the slits having separation of 2mm. Now the screen is moved away farther 0.25 m. What should be the new wavelength of light so that the fringe - width remains the same (in nm)?Correct answer is '640'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment on young's double - slit with the light of wavelength 800 nm, the screen is placed at a distance of 1 m from the slits having separation of 2mm. Now the screen is moved away farther 0.25 m. What should be the new wavelength of light so that the fringe - width remains the same (in nm)?Correct answer is '640'. Can you explain this answer?.
In an experiment on young's double - slit with the light of wavelength 800 nm, the screen is placed at a distance of 1 m from the slits having separation of 2mm. Now the screen is moved away farther 0.25 m. What should be the new wavelength of light so that the fringe - width remains the same (in nm)?Correct answer is '640'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about In an experiment on young's double - slit with the light of wavelength 800 nm, the screen is placed at a distance of 1 m from the slits having separation of 2mm. Now the screen is moved away farther 0.25 m. What should be the new wavelength of light so that the fringe - width remains the same (in nm)?Correct answer is '640'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment on young's double - slit with the light of wavelength 800 nm, the screen is placed at a distance of 1 m from the slits having separation of 2mm. Now the screen is moved away farther 0.25 m. What should be the new wavelength of light so that the fringe - width remains the same (in nm)?Correct answer is '640'. Can you explain this answer?.
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