IIT JAM Exam > IIT JAM Questions > The 7th bright fringe in the Young’s do...
Start Learning for Free
The 7th bright fringe in the Young’s double slit experiment using a light of wavelength 550 nm shifts to the central maxima after covering the two slits with two sheets of different refractive indices n1 and n2 but having same thickness 6 µm. The value of |n1–n2| is ________.
(Round off to 2 decimal places)
(Round off to 2 decimal places)
Correct answer is between '0.63,0.65'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The 7th bright fringe in the Young’s double slit experiment usin...
's double-slit experiment is formed at a distance of 3.5 cm from the central maximum. If the distance between the slits is 0.1 mm and the wavelength of light used is 500 nm, what is the distance between adjacent bright fringes?
We can use the formula for the position of the bright fringes in the double-slit experiment:
y = mλD/d
where y is the distance from the central maximum to the mth bright fringe, λ is the wavelength of light, D is the distance from the slits to the screen, d is the distance between the slits, and m is the order of the bright fringe.
We know that m = 7, y = 3.5 cm = 0.035 m, λ = 500 nm = 5 × 10^-7 m, and d = 0.1 mm = 10^-4 m. We can solve for D:
D = yd/(mλ) = (0.035 × 10^-4)/(7 × 5 × 10^-7) = 1.0 m
Now we can use the formula for the distance between adjacent bright fringes:
Δy = λD/d = 5 × 10^-7 × 1.0 / 10^-4 = 5 × 10^-3 m = 5 mm
Therefore, the distance between adjacent bright fringes is 5 mm.
We can use the formula for the position of the bright fringes in the double-slit experiment:
y = mλD/d
where y is the distance from the central maximum to the mth bright fringe, λ is the wavelength of light, D is the distance from the slits to the screen, d is the distance between the slits, and m is the order of the bright fringe.
We know that m = 7, y = 3.5 cm = 0.035 m, λ = 500 nm = 5 × 10^-7 m, and d = 0.1 mm = 10^-4 m. We can solve for D:
D = yd/(mλ) = (0.035 × 10^-4)/(7 × 5 × 10^-7) = 1.0 m
Now we can use the formula for the distance between adjacent bright fringes:
Δy = λD/d = 5 × 10^-7 × 1.0 / 10^-4 = 5 × 10^-3 m = 5 mm
Therefore, the distance between adjacent bright fringes is 5 mm.
Free Test
FREE
| Start Free Test |
Community Answer
The 7th bright fringe in the Young’s double slit experiment usin...
|
Explore Courses for IIT JAM exam
|
|
The 7th bright fringe in the Young’s double slit experiment using a light of wavelength 550 nm shifts to the central maxima after covering the two slits with two sheets of different refractive indices n1 and n2 but having same thickness 6 µm. The value of |n1–n2| is ________.(Round off to 2 decimal places)Correct answer is between '0.63,0.65'. Can you explain this answer?
Question Description
The 7th bright fringe in the Young’s double slit experiment using a light of wavelength 550 nm shifts to the central maxima after covering the two slits with two sheets of different refractive indices n1 and n2 but having same thickness 6 µm. The value of |n1–n2| is ________.(Round off to 2 decimal places)Correct answer is between '0.63,0.65'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about The 7th bright fringe in the Young’s double slit experiment using a light of wavelength 550 nm shifts to the central maxima after covering the two slits with two sheets of different refractive indices n1 and n2 but having same thickness 6 µm. The value of |n1–n2| is ________.(Round off to 2 decimal places)Correct answer is between '0.63,0.65'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The 7th bright fringe in the Young’s double slit experiment using a light of wavelength 550 nm shifts to the central maxima after covering the two slits with two sheets of different refractive indices n1 and n2 but having same thickness 6 µm. The value of |n1–n2| is ________.(Round off to 2 decimal places)Correct answer is between '0.63,0.65'. Can you explain this answer?.
The 7th bright fringe in the Young’s double slit experiment using a light of wavelength 550 nm shifts to the central maxima after covering the two slits with two sheets of different refractive indices n1 and n2 but having same thickness 6 µm. The value of |n1–n2| is ________.(Round off to 2 decimal places)Correct answer is between '0.63,0.65'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about The 7th bright fringe in the Young’s double slit experiment using a light of wavelength 550 nm shifts to the central maxima after covering the two slits with two sheets of different refractive indices n1 and n2 but having same thickness 6 µm. The value of |n1–n2| is ________.(Round off to 2 decimal places)Correct answer is between '0.63,0.65'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The 7th bright fringe in the Young’s double slit experiment using a light of wavelength 550 nm shifts to the central maxima after covering the two slits with two sheets of different refractive indices n1 and n2 but having same thickness 6 µm. The value of |n1–n2| is ________.(Round off to 2 decimal places)Correct answer is between '0.63,0.65'. Can you explain this answer?.
Solutions for The 7th bright fringe in the Young’s double slit experiment using a light of wavelength 550 nm shifts to the central maxima after covering the two slits with two sheets of different refractive indices n1 and n2 but having same thickness 6 µm. The value of |n1–n2| is ________.(Round off to 2 decimal places)Correct answer is between '0.63,0.65'. Can you explain this answer? in English & in Hindi are available as part of our courses for IIT JAM.
Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free.
Here you can find the meaning of The 7th bright fringe in the Young’s double slit experiment using a light of wavelength 550 nm shifts to the central maxima after covering the two slits with two sheets of different refractive indices n1 and n2 but having same thickness 6 µm. The value of |n1–n2| is ________.(Round off to 2 decimal places)Correct answer is between '0.63,0.65'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The 7th bright fringe in the Young’s double slit experiment using a light of wavelength 550 nm shifts to the central maxima after covering the two slits with two sheets of different refractive indices n1 and n2 but having same thickness 6 µm. The value of |n1–n2| is ________.(Round off to 2 decimal places)Correct answer is between '0.63,0.65'. Can you explain this answer?, a detailed solution for The 7th bright fringe in the Young’s double slit experiment using a light of wavelength 550 nm shifts to the central maxima after covering the two slits with two sheets of different refractive indices n1 and n2 but having same thickness 6 µm. The value of |n1–n2| is ________.(Round off to 2 decimal places)Correct answer is between '0.63,0.65'. Can you explain this answer? has been provided alongside types of The 7th bright fringe in the Young’s double slit experiment using a light of wavelength 550 nm shifts to the central maxima after covering the two slits with two sheets of different refractive indices n1 and n2 but having same thickness 6 µm. The value of |n1–n2| is ________.(Round off to 2 decimal places)Correct answer is between '0.63,0.65'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The 7th bright fringe in the Young’s double slit experiment using a light of wavelength 550 nm shifts to the central maxima after covering the two slits with two sheets of different refractive indices n1 and n2 but having same thickness 6 µm. The value of |n1–n2| is ________.(Round off to 2 decimal places)Correct answer is between '0.63,0.65'. Can you explain this answer? tests, examples and also practice IIT JAM tests.
|
|
Explore Courses for IIT JAM exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup