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Which of the following has no real root?
  • a)
    x2−5x+3√2=0
  • b)
    x2+4x−3√2=0
  • c)
    x2−4x+3√2=0
  • d)
    x2−4x−3√2=0
Correct answer is option 'C'. Can you explain this answer?
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Which of the following has no real root?a)x2−5x+3√2=0b)x2+...
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Which of the following has no real root?a)x2−5x+3√2=0b)x2+...
Explanation:

Given Quadratic Equations:
a) x² - 5x + 3√2 = 0
b) x² + 4x - 3√2 = 0
c) x² - 4x + 3√2 = 0
d) x² - 4x - 3√2 = 0

Real Root of a Quadratic Equation:
A quadratic equation ax² + bx + c = 0 has real roots if the discriminant b² - 4ac is greater than or equal to 0.

Calculating Discriminant for each equation:
a) Discriminant = (-5)² - 4*1*(3√2) = 25 - 12√2
b) Discriminant = 4² - 4*1*(-3√2) = 16 + 12√2
c) Discriminant = (-4)² - 4*1*(3√2) = 16 - 12√2
d) Discriminant = (-4)² - 4*1*(-3√2) = 16 + 12√2

Analysis:
- For equation (a), the discriminant is not equal to 0, so it has real roots.
- For equation (b), the discriminant is not equal to 0, so it has real roots.
- For equation (c), the discriminant is equal to 0, which means it has equal real roots.
- For equation (d), the discriminant is not equal to 0, so it has real roots.

Conclusion:
Therefore, the equation x² - 4x + 3√2 = 0 has no real roots as its discriminant is equal to 0.
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