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Let P be a singly linked list. Let Q be the pointer to an intermediate node x in the list. What is the worst-case time complexity of the best-known algorithm to delete the node x from the list ?
- a)O(n)
- b)O(log2 n)
- c)O(log n)
- d)O(1)
Correct answer is option 'A'. Can you explain this answer?
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Let P be a singly linked list. Let Q be the pointer to an intermediate...
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Let P be a singly linked list. Let Q be the pointer to an intermediate...
Deleting a node from a singly linked list
Deleting a node from a singly linked list involves changing the pointers of the previous node to point to the next node, effectively removing the node from the list.
Worst-case time complexity of deleting an intermediate node
In the worst case, when we want to delete an intermediate node x from the list, we need to traverse the list to find the node that precedes x. This is because singly linked lists do not have a pointer to the previous node.
Therefore, the worst-case time complexity of the best-known algorithm to delete an intermediate node x from a singly linked list is O(n), where n is the number of nodes in the list.
This is because we may need to traverse the entire list to find the node that precedes x.
Conclusion
In conclusion, the worst-case time complexity of the best-known algorithm to delete an intermediate node x from a singly linked list is O(n). This is because we may need to traverse the entire list to find the node that precedes x.
Deleting a node from a singly linked list involves changing the pointers of the previous node to point to the next node, effectively removing the node from the list.
Worst-case time complexity of deleting an intermediate node
In the worst case, when we want to delete an intermediate node x from the list, we need to traverse the list to find the node that precedes x. This is because singly linked lists do not have a pointer to the previous node.
Therefore, the worst-case time complexity of the best-known algorithm to delete an intermediate node x from a singly linked list is O(n), where n is the number of nodes in the list.
This is because we may need to traverse the entire list to find the node that precedes x.
Conclusion
In conclusion, the worst-case time complexity of the best-known algorithm to delete an intermediate node x from a singly linked list is O(n). This is because we may need to traverse the entire list to find the node that precedes x.
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Let P be a singly linked list. Let Q be the pointer to an intermediate...
Answer is d because it is given pointer is on intermediate node in the list. so worst case order is O(1). same question has been asked in gate previous years paper.
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Let P be a singly linked list. Let Q be the pointer to an intermediate node x in the list. What is the worst-case time complexity of the best-known algorithm to delete the node x from the list ?a)O(n)b)O(log2 n)c)O(log n)d)O(1)Correct answer is option 'A'. Can you explain this answer?
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