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Let P be a singly linked list. Let Q be the pointer to an intermediate node x in the list. What is the worst-case time complexity of the best known algorithm to delete the node x from the list? (a) O(n) (b) O(log^2 n)
(c) O(log n) (d) O(1)?
(c) O(log n) (d) O(1)?
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Let P be a singly linked list. Let Q be the pointer to an intermediate...
Answer:
Time complexity of deleting a node x from a singly linked list:
The time complexity of the best known algorithm to delete a node x from a singly linked list depends on the position of the node x in the list. If x is the first node in the list, then the time complexity of deleting the node x would be O(1). However, if x is an intermediate node or the last node in the list, then the time complexity of deleting the node x would be O(n), where n is the number of nodes in the list.
Explanation:
Deleting a node x from a singly linked list involves updating the pointers of the previous node and the next node of x to point to each other, effectively removing x from the list. The time complexity of this operation depends on the position of x in the list.
If x is the first node in the list:
If x is the first node in the list, then deleting the node x involves updating the pointer of the head of the list to point to the next node of x. This operation takes constant time, and hence the time complexity of deleting x is O(1).
If x is an intermediate node or the last node in the list:
If x is an intermediate node or the last node in the list, then deleting the node x involves traversing the list to find the previous node of x and updating its next pointer to point to the next node of x. This operation takes linear time, and hence the time complexity of deleting x is O(n).
Conclusion:
Therefore, the worst-case time complexity of the best known algorithm to delete a node x from a singly linked list is O(n), where n is the number of nodes in the list.
Time complexity of deleting a node x from a singly linked list:
The time complexity of the best known algorithm to delete a node x from a singly linked list depends on the position of the node x in the list. If x is the first node in the list, then the time complexity of deleting the node x would be O(1). However, if x is an intermediate node or the last node in the list, then the time complexity of deleting the node x would be O(n), where n is the number of nodes in the list.
Explanation:
Deleting a node x from a singly linked list involves updating the pointers of the previous node and the next node of x to point to each other, effectively removing x from the list. The time complexity of this operation depends on the position of x in the list.
If x is the first node in the list:
If x is the first node in the list, then deleting the node x involves updating the pointer of the head of the list to point to the next node of x. This operation takes constant time, and hence the time complexity of deleting x is O(1).
If x is an intermediate node or the last node in the list:
If x is an intermediate node or the last node in the list, then deleting the node x involves traversing the list to find the previous node of x and updating its next pointer to point to the next node of x. This operation takes linear time, and hence the time complexity of deleting x is O(n).
Conclusion:
Therefore, the worst-case time complexity of the best known algorithm to delete a node x from a singly linked list is O(n), where n is the number of nodes in the list.
Community Answer
Let P be a singly linked list. Let Q be the pointer to an intermediate...
It's O(n)
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Let P be a singly linked list. Let Q be the pointer to an intermediate node x in the list. What is the worst-case time complexity of the best known algorithm to delete the node x from the list? (a) O(n) (b) O(log^2 n) (c) O(log n) (d) O(1)?
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