Two trains are moving in the same direction at the speed of 35 km/hr a...
Relative speed of train = 71 - 35 = 36 × (5/18) = 10 m/s
Time = 48 seconds
So, length of faster train = 48 × 10 = 480 metres
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Two trains are moving in the same direction at the speed of 35 km/hr a...
Given information:
- Speed of slower train = 35 km/hr
- Speed of faster train = 71 km/hr
- Time taken by faster train to cross a man sitting in the slower train = 48 seconds
To find:
- Length of the faster train
Let's assume the length of the faster train is 'x' meters.
Since the two trains are moving in the same direction, the relative speed of the faster train with respect to the slower train is the difference between their speeds.
Relative speed = 71 km/hr - 35 km/hr = 36 km/hr = (36 × 5/18) m/s = 10 m/s
To cross the man sitting in the slower train, the faster train needs to cover the length of the man and its own length.
Therefore, the distance covered by the faster train in crossing the man is equal to the sum of their lengths.
Using the formula: Distance = Speed × Time, we can find the distance covered by the faster train in 48 seconds.
Distance = 10 m/s × 48 s = 480 meters
Now, we know that the distance covered by the faster train is equal to the sum of the lengths of the man and the faster train.
Therefore, x + length of man = 480 meters
Since the length of the man is negligible compared to the length of the train, we can assume it to be zero.
So, x + 0 = 480 meters
x = 480 meters
Hence, the length of the faster train is 480 meters, which is option C.