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A body is projected with a velocity of 20 m/s in a direction making an angle of 60 degree with the horizontal. calculate it's (I) position after 0.5s and velocity after 0.5s
? Related: Projectile Motion
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A body is projected with a velocity of 20 m/s in a direction making an...
Projectile Motion
Projectile motion is the motion of an object that is thrown or projected into the air and then moves under the influence of gravity alone. It is a type of two-dimensional motion in which an object moves along a curved path.
Position after 0.5s
To calculate the position of the body after 0.5 seconds, we need to use the following equations:
- horizontal distance, x = v0t cosθ
- vertical distance, y = v0t sinθ - 0.5gt^2
where v0 is the initial velocity, θ is the angle of projection, g is the acceleration due to gravity (9.8 m/s^2), and t is the time.
Substituting the given values, we get:
- x = 20 × 0.5 × cos60° = 5 m
- y = 20 × 0.5 × sin60° - 0.5 × 9.8 × 0.5^2 = 5 √3 - 1.225 ≈ 7.3 m
Therefore, the position of the body after 0.5 seconds is (5, 7.3) meters.
Velocity after 0.5s
To calculate the velocity of the body after 0.5 seconds, we need to use the following equations:
- horizontal velocity, vx = v0 cosθ
- vertical velocity, vy = v0 sinθ - gt
where v0 is the initial velocity, θ is the angle of projection, g is the acceleration due to gravity (9.8 m/s^2), and t is the time.
Substituting the given values, we get:
- vx = 20 × cos60° = 10 m/s
- vy = 20 × sin60° - 9.8 × 0.5 = 10 √3 - 4.9 ≈ 5.1 m/s
Therefore, the velocity of the body after 0.5 seconds is (10, 5.1) m/s.
Projectile motion is the motion of an object that is thrown or projected into the air and then moves under the influence of gravity alone. It is a type of two-dimensional motion in which an object moves along a curved path.
Position after 0.5s
To calculate the position of the body after 0.5 seconds, we need to use the following equations:
- horizontal distance, x = v0t cosθ
- vertical distance, y = v0t sinθ - 0.5gt^2
where v0 is the initial velocity, θ is the angle of projection, g is the acceleration due to gravity (9.8 m/s^2), and t is the time.
Substituting the given values, we get:
- x = 20 × 0.5 × cos60° = 5 m
- y = 20 × 0.5 × sin60° - 0.5 × 9.8 × 0.5^2 = 5 √3 - 1.225 ≈ 7.3 m
Therefore, the position of the body after 0.5 seconds is (5, 7.3) meters.
Velocity after 0.5s
To calculate the velocity of the body after 0.5 seconds, we need to use the following equations:
- horizontal velocity, vx = v0 cosθ
- vertical velocity, vy = v0 sinθ - gt
where v0 is the initial velocity, θ is the angle of projection, g is the acceleration due to gravity (9.8 m/s^2), and t is the time.
Substituting the given values, we get:
- vx = 20 × cos60° = 10 m/s
- vy = 20 × sin60° - 9.8 × 0.5 = 10 √3 - 4.9 ≈ 5.1 m/s
Therefore, the velocity of the body after 0.5 seconds is (10, 5.1) m/s.
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A body is projected with a velocity of 20 m/s in a direction making an...
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A body is projected with a velocity of 20 m/s in a direction making an angle of 60 degree with the horizontal. calculate it's (I) position after 0.5s and velocity after 0.5s Related: Projectile Motion?
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A body is projected with a velocity of 20 m/s in a direction making an angle of 60 degree with the horizontal. calculate it's (I) position after 0.5s and velocity after 0.5s Related: Projectile Motion? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A body is projected with a velocity of 20 m/s in a direction making an angle of 60 degree with the horizontal. calculate it's (I) position after 0.5s and velocity after 0.5s Related: Projectile Motion? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body is projected with a velocity of 20 m/s in a direction making an angle of 60 degree with the horizontal. calculate it's (I) position after 0.5s and velocity after 0.5s Related: Projectile Motion?.
A body is projected with a velocity of 20 m/s in a direction making an angle of 60 degree with the horizontal. calculate it's (I) position after 0.5s and velocity after 0.5s Related: Projectile Motion? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A body is projected with a velocity of 20 m/s in a direction making an angle of 60 degree with the horizontal. calculate it's (I) position after 0.5s and velocity after 0.5s Related: Projectile Motion? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body is projected with a velocity of 20 m/s in a direction making an angle of 60 degree with the horizontal. calculate it's (I) position after 0.5s and velocity after 0.5s Related: Projectile Motion?.
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