Class 12 Exam > Class 12 Questions > Statement I : When a mixture of ethanal and p...
Start Learning for Free
Statement I : When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol (excluding stereoisomers) are formed.
Statement II : In mixed aldol condensation, two self and two cross condensation products are always formed.
Statement II : In mixed aldol condensation, two self and two cross condensation products are always formed.
- a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I
- b)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I
- c)Statement I is correct but Statement II is incorrect
- d)Statement II is correct but Statement I is incorrect
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Statement I : When a mixture of ethanal and propanal is treated with a...
It would be true only if both carbonyls are capable of forming enolates, i.e. possesses α-H
Most Upvoted Answer
Statement I : When a mixture of ethanal and propanal is treated with a...
Statement I: When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol (excluding stereoisomers) are formed.
Statement II: In mixed aldol condensation, two self and two cross condensation products are always formed.
Explanation:
Aldol condensation is a reaction in which an enol or enolate reacts with a carbonyl compound to form a β-hydroxyaldehyde or β-hydroxyketone. This reaction involves the nucleophilic addition of the enolate/enol to the carbonyl group followed by dehydration.
Statement I states that when a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol (excluding stereoisomers) are formed. This statement is incorrect.
Explanation for Statement I:
When ethanal (CH3CHO) reacts with propanal (CH3CH2CHO) in the presence of a base like aqueous Na2CO3, aldol condensation occurs. The reaction can proceed in two ways:
1. Self-Condensation: Ethanal reacts with itself to form a β-hydroxyaldehyde.
CH3CHO + CH3CHO → CH3CH(OH)CHO
2. Cross-Condensation: Ethanal reacts with propanal to form a β-hydroxyaldehyde.
CH3CHO + CH3CH2CHO → CH3CH(OH)CH2CHO
So, when ethanal and propanal are treated with aqueous Na2CO3, only two aldol products are formed - one self-condensation product and one cross-condensation product. Therefore, Statement I is incorrect.
Statement II states that in mixed aldol condensation, two self and two cross-condensation products are always formed. This statement is incorrect.
Explanation for Statement II:
In mixed aldol condensation, two different carbonyl compounds are used in the reaction. The reaction can proceed in four possible ways:
1. Self-Condensation of Carbonyl Compound 1: Carbonyl compound 1 reacts with itself to form a β-hydroxyaldehyde or β-hydroxyketone.
2. Self-Condensation of Carbonyl Compound 2: Carbonyl compound 2 reacts with itself to form a β-hydroxyaldehyde or β-hydroxyketone.
3. Cross-Condensation between Carbonyl Compound 1 and Carbonyl Compound 2: Carbonyl compound 1 reacts with carbonyl compound 2 to form a β-hydroxyaldehyde or β-hydroxyketone.
4. Cross-Condensation between Carbonyl Compound 2 and Carbonyl Compound 1: Carbonyl compound 2 reacts with carbonyl compound 1 to form a β-hydroxyaldehyde or β-hydroxyketone.
So, in mixed aldol condensation, four aldol products are formed - two self-condensation products (one from each carbonyl compound) and two cross-condensation products (one from each combination of carbonyl compounds).
Therefore, both Statement I and Statement II are incorrect.
Hence, the correct answer is option C) Statement I is correct but Statement II is incorrect.
Statement II: In mixed aldol condensation, two self and two cross condensation products are always formed.
Explanation:
Aldol condensation is a reaction in which an enol or enolate reacts with a carbonyl compound to form a β-hydroxyaldehyde or β-hydroxyketone. This reaction involves the nucleophilic addition of the enolate/enol to the carbonyl group followed by dehydration.
Statement I states that when a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol (excluding stereoisomers) are formed. This statement is incorrect.
Explanation for Statement I:
When ethanal (CH3CHO) reacts with propanal (CH3CH2CHO) in the presence of a base like aqueous Na2CO3, aldol condensation occurs. The reaction can proceed in two ways:
1. Self-Condensation: Ethanal reacts with itself to form a β-hydroxyaldehyde.
CH3CHO + CH3CHO → CH3CH(OH)CHO
2. Cross-Condensation: Ethanal reacts with propanal to form a β-hydroxyaldehyde.
CH3CHO + CH3CH2CHO → CH3CH(OH)CH2CHO
So, when ethanal and propanal are treated with aqueous Na2CO3, only two aldol products are formed - one self-condensation product and one cross-condensation product. Therefore, Statement I is incorrect.
Statement II states that in mixed aldol condensation, two self and two cross-condensation products are always formed. This statement is incorrect.
Explanation for Statement II:
In mixed aldol condensation, two different carbonyl compounds are used in the reaction. The reaction can proceed in four possible ways:
1. Self-Condensation of Carbonyl Compound 1: Carbonyl compound 1 reacts with itself to form a β-hydroxyaldehyde or β-hydroxyketone.
2. Self-Condensation of Carbonyl Compound 2: Carbonyl compound 2 reacts with itself to form a β-hydroxyaldehyde or β-hydroxyketone.
3. Cross-Condensation between Carbonyl Compound 1 and Carbonyl Compound 2: Carbonyl compound 1 reacts with carbonyl compound 2 to form a β-hydroxyaldehyde or β-hydroxyketone.
4. Cross-Condensation between Carbonyl Compound 2 and Carbonyl Compound 1: Carbonyl compound 2 reacts with carbonyl compound 1 to form a β-hydroxyaldehyde or β-hydroxyketone.
So, in mixed aldol condensation, four aldol products are formed - two self-condensation products (one from each carbonyl compound) and two cross-condensation products (one from each combination of carbonyl compounds).
Therefore, both Statement I and Statement II are incorrect.
Hence, the correct answer is option C) Statement I is correct but Statement II is incorrect.
|
Explore Courses for Class 12 exam
|
|
Top Courses for Class 12View all
Question Description
Statement I : When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol(excluding stereoisomers) are formed.Statement II : In mixed aldolcondensation, two self and two cross condensation products are always formed.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Statement I : When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol(excluding stereoisomers) are formed.Statement II : In mixed aldolcondensation, two self and two cross condensation products are always formed.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Statement I : When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol(excluding stereoisomers) are formed.Statement II : In mixed aldolcondensation, two self and two cross condensation products are always formed.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'C'. Can you explain this answer?.
Statement I : When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol(excluding stereoisomers) are formed.Statement II : In mixed aldolcondensation, two self and two cross condensation products are always formed.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Statement I : When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol(excluding stereoisomers) are formed.Statement II : In mixed aldolcondensation, two self and two cross condensation products are always formed.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Statement I : When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol(excluding stereoisomers) are formed.Statement II : In mixed aldolcondensation, two self and two cross condensation products are always formed.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Statement I : When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol(excluding stereoisomers) are formed.Statement II : In mixed aldolcondensation, two self and two cross condensation products are always formed.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of Statement I : When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol(excluding stereoisomers) are formed.Statement II : In mixed aldolcondensation, two self and two cross condensation products are always formed.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Statement I : When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol(excluding stereoisomers) are formed.Statement II : In mixed aldolcondensation, two self and two cross condensation products are always formed.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Statement I : When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol(excluding stereoisomers) are formed.Statement II : In mixed aldolcondensation, two self and two cross condensation products are always formed.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Statement I : When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol(excluding stereoisomers) are formed.Statement II : In mixed aldolcondensation, two self and two cross condensation products are always formed.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Statement I : When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol(excluding stereoisomers) are formed.Statement II : In mixed aldolcondensation, two self and two cross condensation products are always formed.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup