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Consider the isomeric aldehydes with molar mass 100, if all the isomers (only structural) are treated independently with NH2OH, how many of them would give more than two stereomeric oximes?
    Correct answer is '3'. Can you explain this answer?
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    Consider the isomeric aldehydes with molar mass 100, if all the isomer...
    MW = 100 indicates that molecular formula of aldehyde is C6H12O . For obtain ing more than two oximes, aldehyde must exist stereomeric.

    All the above has one chiral carbon each. Hence, when reacted with H2NOH, forms more than two oximes.
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    Consider the isomeric aldehydes with molar mass 100, if all the isomer...
    To determine the number of isomeric aldehydes that would give more than two stereomeric oximes when treated independently with NH2OH, we need to consider the reaction between the aldehyde and NH2OH to form the oxime.

    First, let's understand the reaction between an aldehyde and NH2OH. When an aldehyde reacts with NH2OH, an oxime is formed. The reaction involves the nucleophilic addition of NH2OH to the carbonyl carbon of the aldehyde, followed by the loss of water to form the oxime.

    Now, let's analyze the possible isomeric aldehydes with a molar mass of 100.

    1. Straight-chain aldehydes:
    - The general formula for a straight-chain aldehyde is CnH2nO, where n is the number of carbon atoms.
    - For a molar mass of 100, the possible straight-chain aldehydes are C4H8O and C5H10O.
    - Both C4H8O and C5H10O can form only one stereomeric oxime since there is no possibility of having chiral centers.

    2. Branched-chain aldehydes:
    - Branched-chain aldehydes have the general formula CnH2n-2O, where n is the number of carbon atoms.
    - For a molar mass of 100, the possible branched-chain aldehydes are C5H8O and C6H10O.
    - C5H8O can form two stereoisomeric oximes since it has one chiral carbon atom.
    - C6H10O can form more than two stereoisomeric oximes since it has two chiral carbon atoms. The number of stereoisomers can be determined using the 2^n formula, where n is the number of chiral carbon atoms. In this case, 2^2 = 4 stereoisomers are possible.

    3. Cycloalkyl aldehydes:
    - Cycloalkyl aldehydes have the general formula CnH2n-2O, where n is the number of carbon atoms.
    - For a molar mass of 100, the possible cycloalkyl aldehydes are C6H10O and C7H12O.
    - C6H10O can form two stereoisomeric oximes since it has one chiral carbon atom.
    - C7H12O can form more than two stereoisomeric oximes since it has two chiral carbon atoms. Using the 2^n formula, 2^2 = 4 stereoisomers are possible.

    Based on the analysis above, we can conclude that there are three isomeric aldehydes that would give more than two stereomeric oximes when treated independently with NH2OH. These aldehydes are C5H8O, C6H10O, and C7H12O.
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    Consider the isomeric aldehydes with molar mass 100, if all the isomers (only structural) are treated independently with NH2OH, how many of them would give more than two stereomeric oximes?Correct answer is '3'. Can you explain this answer?
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