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Consider a 3-bit error detection and 1-bit error correction hamming code for 4-bit datq. The extra parity bits required would be ___ and the 3-bit error detection is possible because the code has a minimum distance of ____
Correct answer is 'Answer for 2 blanks are [ 3,4 ]'. Can you explain this answer?
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Consider a 3-bit error detection and 1-bit error correction hamming co...
The Hamming distance between two bit strings is the number of bits that would have to flip to make the strings identical.
To detect d errors requires a minimum Hamming distance of d + 1 .
Correcting d bit flips requires a minimum Hamming distance of 2 * d + 1 , where d is number of bit in errors .
For the first blank , each error detection we need 1 parity bit
for 3 bit error detection we need 3 parity bit ...... So, 3 parity bit requires here. answer is 3.
Also we can calculate this way, formula is d+p+1 <= 2p where d=data bits , p = parity bits , d=4 bit given.
according to 1st question, d= 4 so 4+p+1<= 2p
p+5 <= 2p now if p=2 it becomes 7 <= 4 , Not satisfy . p = 3 it becomes 8 <= 8 , satisfy.
so p must be 3 .[ Minimum value of p is 3 ]
The second blank the 3-bit error detection is possible because the code has a minimum distance of ____ answer is
3+1=4, where d=3. Formula used d+1.
Answer for 2 blanks are [ 3,4 ]
To detect d errors requires a minimum Hamming distance of d + 1 .
Correcting d bit flips requires a minimum Hamming distance of 2 * d + 1 , where d is number of bit in errors .
For the first blank , each error detection we need 1 parity bit
for 3 bit error detection we need 3 parity bit ...... So, 3 parity bit requires here. answer is 3.
Also we can calculate this way, formula is d+p+1 <= 2p where d=data bits , p = parity bits , d=4 bit given.
according to 1st question, d= 4 so 4+p+1<= 2p
p+5 <= 2p now if p=2 it becomes 7 <= 4 , Not satisfy . p = 3 it becomes 8 <= 8 , satisfy.
so p must be 3 .[ Minimum value of p is 3 ]
The second blank the 3-bit error detection is possible because the code has a minimum distance of ____ answer is
3+1=4, where d=3. Formula used d+1.
Answer for 2 blanks are [ 3,4 ]
Most Upvoted Answer
Consider a 3-bit error detection and 1-bit error correction hamming co...
Explanation:
Hamming Code: Hamming code is a linear error-correcting code technique used in digital communication to detect and correct errors. It allows the detection of up to two simultaneous bit errors and the correction of single-bit errors.
3-bit error detection and 1-bit error correction hamming code: In this type of hamming code, there are 3 parity bits and 4 data bits. The parity bits are calculated based on the position of the bit in the code word. The first parity bit covers all the bits that have a first bit that is set to 1, the second parity bit covers all the bits that have a second bit that is set to 1, and the third parity bit covers all the bits that have a third bit that is set to 1. This allows for the detection of up to 3-bit errors and the correction of 1-bit errors.
Extra parity bits: In this type of hamming code, there are already 3 parity bits, so no extra parity bits are required.
Minimum distance: The minimum distance of a code is the minimum number of bit positions in which any two code words differ. In this hamming code, the minimum distance is 4, which means that any two code words differ in at least 4 bit positions. This allows for the detection of up to 3-bit errors.
Answer:
The extra parity bits required would be 3 and the 3-bit error detection is possible because the code has a minimum distance of 4.
Hamming Code: Hamming code is a linear error-correcting code technique used in digital communication to detect and correct errors. It allows the detection of up to two simultaneous bit errors and the correction of single-bit errors.
3-bit error detection and 1-bit error correction hamming code: In this type of hamming code, there are 3 parity bits and 4 data bits. The parity bits are calculated based on the position of the bit in the code word. The first parity bit covers all the bits that have a first bit that is set to 1, the second parity bit covers all the bits that have a second bit that is set to 1, and the third parity bit covers all the bits that have a third bit that is set to 1. This allows for the detection of up to 3-bit errors and the correction of 1-bit errors.
Extra parity bits: In this type of hamming code, there are already 3 parity bits, so no extra parity bits are required.
Minimum distance: The minimum distance of a code is the minimum number of bit positions in which any two code words differ. In this hamming code, the minimum distance is 4, which means that any two code words differ in at least 4 bit positions. This allows for the detection of up to 3-bit errors.
Answer:
The extra parity bits required would be 3 and the 3-bit error detection is possible because the code has a minimum distance of 4.
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Consider a 3-bit error detection and 1-bit error correction hamming code for 4-bit datq. The extra parity bits required would be ___ and the 3-bit error detection is possible because the code has a minimum distance of ____Correct answer is 'Answer for 2 blanks are [ 3,4 ]'. Can you explain this answer?
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Consider a 3-bit error detection and 1-bit error correction hamming code for 4-bit datq. The extra parity bits required would be ___ and the 3-bit error detection is possible because the code has a minimum distance of ____Correct answer is 'Answer for 2 blanks are [ 3,4 ]'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider a 3-bit error detection and 1-bit error correction hamming code for 4-bit datq. The extra parity bits required would be ___ and the 3-bit error detection is possible because the code has a minimum distance of ____Correct answer is 'Answer for 2 blanks are [ 3,4 ]'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a 3-bit error detection and 1-bit error correction hamming code for 4-bit datq. The extra parity bits required would be ___ and the 3-bit error detection is possible because the code has a minimum distance of ____Correct answer is 'Answer for 2 blanks are [ 3,4 ]'. Can you explain this answer?.
Consider a 3-bit error detection and 1-bit error correction hamming code for 4-bit datq. The extra parity bits required would be ___ and the 3-bit error detection is possible because the code has a minimum distance of ____Correct answer is 'Answer for 2 blanks are [ 3,4 ]'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider a 3-bit error detection and 1-bit error correction hamming code for 4-bit datq. The extra parity bits required would be ___ and the 3-bit error detection is possible because the code has a minimum distance of ____Correct answer is 'Answer for 2 blanks are [ 3,4 ]'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a 3-bit error detection and 1-bit error correction hamming code for 4-bit datq. The extra parity bits required would be ___ and the 3-bit error detection is possible because the code has a minimum distance of ____Correct answer is 'Answer for 2 blanks are [ 3,4 ]'. Can you explain this answer?.
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