6 times of a fraction is greater than 7 times of its reciprocal by 11....
To solve this problem, we can start by setting up an equation based on the given information.
Let's assume the fraction is represented by 'x'.
According to the problem, 6 times the fraction is greater than 7 times its reciprocal by 11. We can express this as:
6x > 7(1/x) + 11
Now, let's simplify the equation step by step to solve for 'x'.
Simplifying the right side of the equation:
7(1/x) + 11 = 7/x + 11
Finding a common denominator:
7/x + 11 = (7 + 11x) / x
Substituting the simplified expression back into the equation:
6x > (7 + 11x) / x
Multiplying both sides of the equation by 'x' to eliminate the denominator:
6x^2 > 7 + 11x
Rearranging the equation to isolate the terms on one side:
6x^2 - 11x - 7 > 0
Now we have a quadratic inequality. To solve it, we can factor the expression or use the quadratic formula.
Factoring the quadratic expression:
(2x - 7)(3x + 1) > 0
Setting each factor greater than zero to find the intervals where the inequality is satisfied:
2x - 7 > 0 or 3x + 1 > 0
Solving each inequality separately:
2x > 7 or 3x > -1
x > 7/2 or x > -1/3
Since we are looking for a fraction, the value of 'x' cannot be negative. Therefore, we discard the interval x > -1/3.
So, the solution is x > 7/2, which means the fraction is greater than 7/2.
Among the given answer choices, the only fraction that satisfies this condition is 7/3 (option B).
Therefore, the correct answer is option B, 7/3.