Class 12 Exam  >  Class 12 Questions  >  A mixture containing all isomeric cyclohexane... Start Learning for Free
A mixture containing all isomeric cyclohexanedione is treated with excess of NaHSO3 solution. How many different disulphite salts are formed?
    Correct answer is '8'. Can you explain this answer?
    Verified Answer
    A mixture containing all isomeric cyclohexanedione is treated with exc...


    View all questions of this test
    Most Upvoted Answer
    A mixture containing all isomeric cyclohexanedione is treated with exc...
    Different disulphite salts formed from the mixture of isomeric cyclohexanedione can be explained as follows:

    1. Introduction:
    In this scenario, we have a mixture containing all isomeric forms of cyclohexanedione. These isomeric forms differ in the position of the carbonyl groups on the cyclohexane ring. When this mixture is treated with an excess of NaHSO3 solution, it undergoes a reaction to form disulphite salts.

    2. Reaction:
    The reaction between the cyclohexanedione and NaHSO3 proceeds via a nucleophilic addition-elimination mechanism. The nucleophilic sulfur dioxide ion (SO3^2-) attacks one of the carbonyl groups of the cyclohexanedione, leading to the formation of a cyclic intermediate. This intermediate then undergoes elimination of water to form the disulphite salt.

    3. Isomerism:
    Due to the presence of two carbonyl groups in cyclohexanedione, there are multiple possible isomeric forms. These isomers differ in the position of the carbonyl groups on the cyclohexane ring. The different isomeric forms of cyclohexanedione include:

    - 1,2-cyclohexanedione
    - 1,3-cyclohexanedione
    - 1,4-cyclohexanedione
    - 1,2-dimethylcyclohexanedione
    - 1,3-dimethylcyclohexanedione
    - 1,4-dimethylcyclohexanedione

    4. Formation of disulphite salts:
    When each of these isomeric forms of cyclohexanedione reacts with NaHSO3, they form different disulphite salts. The disulphite salts are formed by the addition of two SO3^2- ions to the carbonyl groups of the cyclohexanedione, followed by elimination of water. As a result, eight different disulphite salts are formed, corresponding to each isomeric form of cyclohexanedione.

    5. Conclusion:
    In summary, when a mixture containing all isomeric cyclohexanedione is treated with an excess of NaHSO3 solution, eight different disulphite salts are formed. Each isomeric form of cyclohexanedione reacts differently with NaHSO3, leading to the formation of distinct disulphite salts. This demonstrates the importance of considering isomerism in chemical reactions and the formation of different products based on the structural differences of the reactants.
    Explore Courses for Class 12 exam
    A mixture containing all isomeric cyclohexanedione is treated with excess of NaHSO3 solution. How many different disulphite salts are formed?Correct answer is '8'. Can you explain this answer?
    Question Description
    A mixture containing all isomeric cyclohexanedione is treated with excess of NaHSO3 solution. How many different disulphite salts are formed?Correct answer is '8'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A mixture containing all isomeric cyclohexanedione is treated with excess of NaHSO3 solution. How many different disulphite salts are formed?Correct answer is '8'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture containing all isomeric cyclohexanedione is treated with excess of NaHSO3 solution. How many different disulphite salts are formed?Correct answer is '8'. Can you explain this answer?.
    Solutions for A mixture containing all isomeric cyclohexanedione is treated with excess of NaHSO3 solution. How many different disulphite salts are formed?Correct answer is '8'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
    Here you can find the meaning of A mixture containing all isomeric cyclohexanedione is treated with excess of NaHSO3 solution. How many different disulphite salts are formed?Correct answer is '8'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A mixture containing all isomeric cyclohexanedione is treated with excess of NaHSO3 solution. How many different disulphite salts are formed?Correct answer is '8'. Can you explain this answer?, a detailed solution for A mixture containing all isomeric cyclohexanedione is treated with excess of NaHSO3 solution. How many different disulphite salts are formed?Correct answer is '8'. Can you explain this answer? has been provided alongside types of A mixture containing all isomeric cyclohexanedione is treated with excess of NaHSO3 solution. How many different disulphite salts are formed?Correct answer is '8'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A mixture containing all isomeric cyclohexanedione is treated with excess of NaHSO3 solution. How many different disulphite salts are formed?Correct answer is '8'. Can you explain this answer? tests, examples and also practice Class 12 tests.
    Explore Courses for Class 12 exam
    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev