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One integer Value Correct Type
Direction (Q. Nos. 17-22) This section contains 6 questions. When worked out will result in an integer from 0 to 9 (both inclusive).
Q.
If all the aldehyde isomers of C5H10O is independently treated with HCN/NaCN solution, how many of them will give racemic mixture of cyanohydrin?
Correct answer is '3'. Can you explain this answer?
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One integer Value Correct Type Direction (Q. Nos. 17-22) This section ...
IV is enantiomeric. Its pure enantiomer, with HCN/NaCN, would produce pair of diastereomers.
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One integer Value Correct Type Direction (Q. Nos. 17-22) This section ...
Introduction:
In this question, we are given the compound C5H10O and we need to determine how many of its aldehyde isomers will give a racemic mixture of cyanohydrin when treated with HCN/NaCN solution.
Isomers of C5H10O:
To solve this question, let's first determine the possible isomers of C5H10O.
1. Pentanal (CH3CH2CH2CH2CHO)
2. 2-Methylbutanal (CH3CH(CH3)CH2CHO)
3. 3-Methylbutanal (CH3CH2CH(CH3)CHO)
4. 2,2-Dimethylpropanal (CH3C(CH3)2CHO)
5. 2-Ethylbutanal (CH3CH2CH(CH3)CH2CHO)
Determination of racemic mixture formation:
Now, let's determine which of these aldehyde isomers will give a racemic mixture of cyanohydrin when treated with HCN/NaCN solution.
1. Pentanal: When pentanal reacts with HCN/NaCN, it forms a cyanohydrin. Since there are no chiral centers present in pentanal, it will not give a racemic mixture.
2. 2-Methylbutanal: This compound has one chiral center. When it reacts with HCN/NaCN, it can give both the R and S enantiomers of the cyanohydrin. Therefore, it will give a racemic mixture.
3. 3-Methylbutanal: This compound also has one chiral center. When it reacts with HCN/NaCN, it can give both the R and S enantiomers of the cyanohydrin. Therefore, it will give a racemic mixture.
4. 2,2-Dimethylpropanal: This compound has two chiral centers. When it reacts with HCN/NaCN, it can give four possible stereoisomers of the cyanohydrin. Two of these stereoisomers will be enantiomeric pairs, leading to the formation of a racemic mixture.
5. 2-Ethylbutanal: This compound has one chiral center. When it reacts with HCN/NaCN, it can give both the R and S enantiomers of the cyanohydrin. Therefore, it will give a racemic mixture.
Conclusion:
Out of the five aldehyde isomers of C5H10O, three of them (2-Methylbutanal, 3-Methylbutanal, and 2,2-Dimethylpropanal) will give a racemic mixture of cyanohydrin when treated with HCN/NaCN solution.
In this question, we are given the compound C5H10O and we need to determine how many of its aldehyde isomers will give a racemic mixture of cyanohydrin when treated with HCN/NaCN solution.
Isomers of C5H10O:
To solve this question, let's first determine the possible isomers of C5H10O.
1. Pentanal (CH3CH2CH2CH2CHO)
2. 2-Methylbutanal (CH3CH(CH3)CH2CHO)
3. 3-Methylbutanal (CH3CH2CH(CH3)CHO)
4. 2,2-Dimethylpropanal (CH3C(CH3)2CHO)
5. 2-Ethylbutanal (CH3CH2CH(CH3)CH2CHO)
Determination of racemic mixture formation:
Now, let's determine which of these aldehyde isomers will give a racemic mixture of cyanohydrin when treated with HCN/NaCN solution.
1. Pentanal: When pentanal reacts with HCN/NaCN, it forms a cyanohydrin. Since there are no chiral centers present in pentanal, it will not give a racemic mixture.
2. 2-Methylbutanal: This compound has one chiral center. When it reacts with HCN/NaCN, it can give both the R and S enantiomers of the cyanohydrin. Therefore, it will give a racemic mixture.
3. 3-Methylbutanal: This compound also has one chiral center. When it reacts with HCN/NaCN, it can give both the R and S enantiomers of the cyanohydrin. Therefore, it will give a racemic mixture.
4. 2,2-Dimethylpropanal: This compound has two chiral centers. When it reacts with HCN/NaCN, it can give four possible stereoisomers of the cyanohydrin. Two of these stereoisomers will be enantiomeric pairs, leading to the formation of a racemic mixture.
5. 2-Ethylbutanal: This compound has one chiral center. When it reacts with HCN/NaCN, it can give both the R and S enantiomers of the cyanohydrin. Therefore, it will give a racemic mixture.
Conclusion:
Out of the five aldehyde isomers of C5H10O, three of them (2-Methylbutanal, 3-Methylbutanal, and 2,2-Dimethylpropanal) will give a racemic mixture of cyanohydrin when treated with HCN/NaCN solution.
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One integer Value Correct Type Direction (Q. Nos. 17-22) This section contains 6 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If all the aldehyde isomers of C5H10O is independently treated with HCN/NaCN solution, how many of them will give racemic mixture of cyanohydrin?Correct answer is '3'. Can you explain this answer?
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One integer Value Correct Type Direction (Q. Nos. 17-22) This section contains 6 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If all the aldehyde isomers of C5H10O is independently treated with HCN/NaCN solution, how many of them will give racemic mixture of cyanohydrin?Correct answer is '3'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One integer Value Correct Type Direction (Q. Nos. 17-22) This section contains 6 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If all the aldehyde isomers of C5H10O is independently treated with HCN/NaCN solution, how many of them will give racemic mixture of cyanohydrin?Correct answer is '3'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One integer Value Correct Type Direction (Q. Nos. 17-22) This section contains 6 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If all the aldehyde isomers of C5H10O is independently treated with HCN/NaCN solution, how many of them will give racemic mixture of cyanohydrin?Correct answer is '3'. Can you explain this answer?.
One integer Value Correct Type Direction (Q. Nos. 17-22) This section contains 6 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If all the aldehyde isomers of C5H10O is independently treated with HCN/NaCN solution, how many of them will give racemic mixture of cyanohydrin?Correct answer is '3'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One integer Value Correct Type Direction (Q. Nos. 17-22) This section contains 6 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If all the aldehyde isomers of C5H10O is independently treated with HCN/NaCN solution, how many of them will give racemic mixture of cyanohydrin?Correct answer is '3'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One integer Value Correct Type Direction (Q. Nos. 17-22) This section contains 6 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If all the aldehyde isomers of C5H10O is independently treated with HCN/NaCN solution, how many of them will give racemic mixture of cyanohydrin?Correct answer is '3'. Can you explain this answer?.
Solutions for One integer Value Correct Type Direction (Q. Nos. 17-22) This section contains 6 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If all the aldehyde isomers of C5H10O is independently treated with HCN/NaCN solution, how many of them will give racemic mixture of cyanohydrin?Correct answer is '3'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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