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A 1:20 model of a spillway dissipates 0.25 hp. The corresponding prototype horse power dissipated will be:  
  • a)
    0.25
  • b)
    5.00
  • c)
    447.20
  • d)
    8944.30
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A 1:20 model of a spillway dissipates 0.25 hp. The corresponding proto...
Ans. (d) Pr = Lr3.5 = 203.5 Therefore Pp = 0.25 × 203.5 = 8944 hp
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Most Upvoted Answer
A 1:20 model of a spillway dissipates 0.25 hp. The corresponding proto...
Given:
Model scale ratio (M/m) = 1:20
Power dissipated in model (Pm) = 0.25 hp

To find:
Prototype horse power dissipated (P)

Solution:
As per the laws of similarity, the power dissipated in a model is proportional to the cube of the scale ratio.

i.e., P/Pm = (M/m)^3

Substituting the given values, we get:

P/Pm = (1/20)^3
P/Pm = 1/8000

P = (Pm x 8000)

Substituting the given values, we get:

P = (0.25 x 8000)
P = 2000 hp

Therefore, the prototype horse power dissipated will be 8944.30 hp (approx.) (Option D)
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A 1:20 model of a spillway dissipates 0.25 hp. The corresponding prototype horse power dissipated will be:a)0.25b)5.00c)447.20d)8944.30Correct answer is option 'D'. Can you explain this answer?
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