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A 1:20 model of a spillway dissipated 0.25 hp. The corresponding prototype horsepower dissipated will be ______ hp. (Answer up to two decimal places)
    Correct answer is '8944.30'. Can you explain this answer?
    Most Upvoted Answer
    A 1:20 model of a spillway dissipated 0.25 hp. The corresponding prot...
    We have
    Linear Scale ratio Lr = 20, Pm = 0.25 hp
    Power ratio for prototype and model is given by
    Pp/Pm =(20)3.5 x 0.25
    = 8944.30 hp
    Free Test
    Community Answer
    A 1:20 model of a spillway dissipated 0.25 hp. The corresponding prot...
    Given:
    - Model scale: 1:20
    - Model power dissipated: 0.25 hp

    To find:
    - Prototype power dissipated

    Assumption:
    - The model and prototype have similar geometric properties.

    Formula:
    - Power ratio (P_ratio) = (Model power/Prototype power) = (Model scale)^3

    Solution:

    Step 1: Calculate the power ratio (P_ratio)
    - We are given that the model power is 0.25 hp.
    - The scale of the model is 1:20, which means the model is 1/20th the size of the prototype.
    - To calculate the power ratio, we need to cube the scale factor: P_ratio = (1/20)^3 = 1/8000.

    Step 2: Calculate the prototype power dissipated
    - The power ratio represents the ratio of power dissipated between the model and the prototype.
    - Therefore, the prototype power dissipated is given by: Prototype power = Model power / P_ratio.
    - Substituting the given values: Prototype power = 0.25 hp / (1/8000) = 0.25 hp * 8000 = 2000 hp.

    Answer:
    The corresponding prototype power dissipated is 2000 hp.
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    A 1:20 model of a spillway dissipated 0.25 hp. The corresponding prototype horsepower dissipated will be ______ hp. (Answer up to two decimal places)Correct answer is '8944.30'. Can you explain this answer?
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